Step 1 — Ek single source ki first dark ring kahan hai?
Width a ke single slit ke liye, first minimum tab hota hai jab slit ke across path difference ek wavelength ke barabar ho:
asinθ=λ⇒θmin≈aλ
Yeh step kyun? Slit ki top half ko bottom half se pair karte hue, top se har ray apne partner ko cancel kar deti hai jo a/2 neeche hai jab unka path difference λ/2 ho; poori slit pe sum karne par asinθ=λ pe total destructive interference milti hai.
Step 2 — Circular aperture correction.
Ek real lens/aankh/telescope ka circular aperture hota hai (diameter D), slit nahi. Ek strip ki jagah disc pe diffraction integrate karne se 1.22 ka ek numerical factor aata hai (Bessel function J1 ka first zero):
θmin=1.22Dλ
Yeh step kyun? Slit λ/a deta hai; circular geometry diffracted energy ko redistribute karta hai aur first dark ring ko thoda bahar push karta hai, 1.22 se multiply karke. (Slit aperture ke liye, 1.22 hata do aur width a use karo.)
Step 3 — Rayleigh apply karo.
"Peak on first minimum" ka matlab hai do sources ke beech minimum angular separation jo hum resolve kar sakte hain woh exactly θmin ke barabar hai:
(a) Telescope / aankh (objects door hain): sources angle θ se separated hain. Resolvable hai agar θ≥θR=1.22λ/D.
(b) Microscope (objects paas hain, smallest distanced se define hote hain): Yahan hum slide pe do points ke beech smallest separation d ki parwah karte hain. Similarly objective ke collecting cone ke saath derive karne par milta hai:
D ki jagah N.A. kyun? Paas ke object ke liye relevant quantity woh cone half-angle hai jo lens collect karta hai, sirf diameter nahi; immersion oil (n>1) effective cone ko wide karta hai, dmin ko shrink karta hai — isliye oil-immersion microscopy finer detail resolve karta hai.
Do sources tab just resolved hain jab ek ke diffraction pattern ka central maximum doosre ke first minimum (first dark ring) ke saath coincide kare.
Circular aperture ki limiting angular resolution ka formula?
θR=1.22λ/D, radians mein.
Factor 1.22 kahan se aata hai?
Circular aperture ke liye Bessel function J1 ke first zero se (vs slit ke liye λ/a).
Resolving power kya hai?
Do close objects ko alag karne ki ability; 1/θR ke barabar — bada matlab finer detail resolvable.
Resolving power aperture diameter aur wavelength pe kaise depend karta hai?
Improve hota hai (θR chota) bade D aur chote λ se.
N.A. ke terms mein microscope resolution limit?
dmin=0.61λ/N.A., jahan N.A. =nsinβ.
Microscopy mein oil immersion kyun use karte hain?
Yeh n (aur isliye N.A.) badhata hai, collecting cone ko wide karta hai aur finer resolution ke liye dmin shrink karta hai.
Bade telescopes resolution ke liye kyun achhe hain?
Bada D, θR=1.22λ/D ko reduce karta hai, isliye taaron ke finer angular separations distinguish kiye ja sakte hain.
Kya magnification aur resolving power same hain?
Nahi — magnification enlarge karta hai; diffraction limit se zyada jaane par "empty magnification" milti hai koi extra detail nahi.
Do just-resolved peaks ke beech roughly kitna intensity dip hota hai?
Lagbhag 26%, do peaks ke beech dip ke roop mein detect karne ke liye kaafi.
Recall Feynman: ek 12-saal ke bachche ko samjhao
Jab ek tiny door dot ki light ek round hole se guzarti hai, toh woh tiny dot nahi rehti — yeh ek chote fuzzy circle mein spread ho jaati hai, jaise ek flashlight beam wider hoti jaati hai. Ab do dots imagine karo: har ek apna fuzzy circle banata hai. Agar circles bahut overlap karein, toh aankhen ek fuzzy blob dekhti hain aur aap nahi bata sakte ki do dots the! Rayleigh rule kehta hai: aap unhe tab just barely alag bata sakte ho jab ek fuzzy circle ke bright middle ko doosre ki dark edge-ring pe rakha jaaye. Bada hole har circle ko kam fuzzy banata hai, isliye aap dots ko zyada easily alag bata sakte ho — isliye giant telescopes do taare dekh sakte hain jo hamare liye ek taare jaisa lagta hai.