This page assumes nothing. If the parent note wrote a symbol, we build it here from a picture first. Read top to bottom — each block uses only what came before.
Why we need this picture. Every symbol below is a number you could read off this one snapshot. Thermodynamics is the study of how these snapshot-numbers relate and how they change when you push the piston or heat the gas.
The picture: the length of the cylinder times its cross-section — the shaded region in the figure above. That's it. V is the most concrete symbol in the whole subject: you can see it.
Why the topic needs it.V is one thing you can physically clamp (lock the piston) or let float. Which one you clamp decides which potential is useful — so V must be understood first.
The picture: tiny gas molecules bouncing off the piston. Each bounce is a little shove. Add up all the shoves over the piston's area and divide by that area — that's p (the orange arrows).
Why the topic needs it.p is the other thing you can clamp (open beaker = fixed atmospheric pressure). V and p are the two "mechanical" handles.
The picture: the same bouncing molecules as before, but now the length of their motion arrows is what T tracks — long arrows = hot, short arrows = cold.
Why the topic needs it.T is the handle a thermostat controls. Most real experiments hold T fixed (a beaker sitting in a room), which is exactly why potentials like F and G — built to use T as a natural variable — exist.
The picture: a few marbles in a box. If there's only one tidy arrangement (all in a corner), S is low. If they can be anywhere (many arrangements), S is high. The figure shows "few ways" (left, low S) versus "many ways" (right, high S).
Why the topic needs it. Substituting δQrev=TdS and δW=pdV into the First Law turns the messy δ-law into the clean master equation.
Reading it as a picture.dU is the total change in the piggy bank. +TdS = energy deposited by heat. −pdV = energy spent pushing the piston. Every potential in the parent note is built by algebraically rearranging this one line.
The picture: stand on the energy-landscape U(S,V). Walk one step in the S-direction only (never sideways in V). The steepness of that step is the partial derivative.
Why the topic needs it. From dU=TdS−pdV, matching term-by-term gives T=(∂U/∂S)V and −p=(∂U/∂V)S. These are the "equations of state for free" the parent note promised — and they're just readings of slope.