Before you can read the Reynolds Transport Theorem on the parent note, you need a small toolbox. We build each tool from zero, in an order where every tool leans only on the ones before it. Nothing is assumed.
The first idea in fluids is that instead of one moving ball, we have a whole space full of stuff, and at every point something has a value.
Look at the figure: at every dot in space, there's a little arrow. That collection of arrows is the velocity field. This is the whole reason fluids feel different from a single particle — there is no single object to follow; there is a carpet of arrows filling the room.
The picture: imagine chopping the fluid into millions of tiny sugar-cubes. ρ tells you how heavy each cube is per unit of its size. Water has ρ≈1000kg/m3: one cubic metre weighs 1000 kg.
Some quantities double when you double the amount of stuff (weigh two buckets, get twice the mass). Others don't (two buckets of water are the same temperature as one).
The picture: B is the total pile; b is how much pile each kilogram carries. Multiply back and you recover the pile: a small mass dm carries bdm=bρdV of the property.
In the figure, the Lagrangian observer (blue) drifts downstream glued to the same water blob. The Eulerian observer (yellow) stays bolted to one spot and lets water rush past.
The trick that starts the whole derivation: at one instant t, we let the system exactly fill the CV. An instant later they've drifted apart — some system leaks out, some new fluid enters. That mismatch is precisely the surface term.
Look at the figure. On the right wall, the fluid arrow v and n^ point the same way — fluid is leaving. On the left wall, v points in while n^ still points out — they oppose. This sign is how the maths knows outflow from inflow, automatically.
We now need a number: how fast does fluid actually pierce the wall? Not "how fast is the fluid" — fluid sliding along the wall crosses nothing. We need the piece of v that points alongn^.
The figure drops a perpendicular from the tip of v onto the n^ line — that shadow length is v⋅n^. Read the three cases across the figure:
Fluid heading straight out (θ=0): cos0=1, full speed crosses — maximum outflow.
Fluid sliding along the wall (θ=90∘): cos90∘=0, nothing crosses — exactly what we want, tangential flow pierces nothing.
Fluid heading straight in (θ=180∘): cos180∘=−1, the shadow is negative — inflow, correctly signed minus.
The picture: ∫CVρbdV tiles the interior with cubes and totals the property stored inside; ∮CSρb(v⋅n^)dA tiles the skin with tiles and totals what leaks across.
The storage term dtd∫CVρbdV asks: is the total stuff inside my fixed box changing over time? It has nothing to do with flow — it's about unsteadiness. For steady flow it is zero, even while fluid rushes through.