A solenoid: length ℓ, N turns, cross-section A, n=N/ℓ turns per metre.
Step 1 — Field inside (Ampère's law).B=μ0nI=μ0ℓNIWhy this step? Inside a long solenoid the field is uniform and axial; an Amperian rectangle gives Bℓpath=μ0(nℓpath)I.
Step 2 — Flux through ONE turn.Φ=BA=μ0ℓNIAWhy this step? Flux =∫B⋅dA=BA because B is uniform and perpendicular to the cross-section.
Step 3 — Flux LINKAGE (all N turns).NΦ=μ0ℓN2AIWhy this step? Each of the N turns is threaded by the same Φ, so total linkage is NΦ.
Step 4 — Read off L=NΦ/I.L=μ0ℓN2A=μ0n2AℓWhy this matters:L∝N2 — doubling turns quadruples inductance, because each turn both makes more flux and links more flux.
Inner long solenoid (the source) with n1=N1/ℓ; outer/overlying coil of N2 turns on the same area A, length ℓ.
Step 1. Inner current I1 makes B1=μ0n1I1 inside.
Step 2. Flux through one turn of coil 2: Φ21=B1A=μ0n1I1A (only the inner-solenoid area carries field).
Step 3. Linkage in coil 2: N2Φ21=μ0N2n1AI1.
Step 4.M=I1N2Φ21=μ0ℓN1N2A=μ0n1N2A
Imagine pushing a heavy swing. A coil of wire is like a swing for electric current: once the current is moving, it doesn't want to suddenly stop or change — it "swings back" with a little electrical push (the back-EMF). Self-inductance is how stubborn the swing is about its own motion. Mutual inductance is when your swing is tied by a rope to a friend's swing: when you change yours, theirs feels a tug too. The more loops in the wire and the tighter they're packed, the more stubborn the swing.
Dekho, self-inductance L ka matlab simple hai: jab kisi coil mein current behta hai, woh apna magnetic field banata hai aur flux coil ke through pass hota hai. Ab agar current change hota hai, to flux change hota hai, aur Faraday's law kehta hai ki badalta flux EMF paida karta hai. Yeh EMF change ko oppose karta hai (Lenz's law, isliye minus sign): ε=−LdI/dt. Isliye coil ek "current ka flywheel" jaisa behave karti hai — current ko achanak badalne nahi deti. Yaad rakho: EMF current par nahi, current ke rate of change par depend karta hai. Constant current = zero self-EMF.
Solenoid ke liye derive karna easy hai: andar field B=μ0nI, ek turn ka flux Φ=BA, aur total linkage NΦ, to L=μ0N2A/ℓ. Yahan dhyan do — L, N2 ke proportional hai, sirf N ke nahi, kyunki har turn flux banata bhi hai aur link bhi karta hai (double duty). Yeh ek classic mistake hai jo students karte hain.
Mutual inductance M tab aata hai jab do coils paas-paas hoti hain. Coil 1 ka current coil 2 mein flux bhejta hai; agar I1 change ho to coil 2 mein EMF aata hai: ε2=−MdI1/dt. Ek important fact: M12=M21, chahe coils chhoti-badi kuch bhi ho (reciprocity). Aur M=kL1L2, jahan k coupling batata hai — k=1 matlab perfect coupling, jaise ideal transformer mein.
Practical importance: transformers, ignition coils, induction cooktops, aur RL circuits sab inhi ideas par chalte hain. Exam mein zyada marks isi se aate hain: L=μ0N2A/ℓ, ε=−LdI/dt, U=21LI2, aur M=kL1L2 — yeh chaar formule pakke kar lo, baaki sab inhi se nikal aata hai.