1.8.23 · Physics › Electromagnetism
Intuition The big picture
Ek steady current apne aas-paas ke magnetic field ko "stir" karta hai. Agar tum ek closed loop mein chalo aur add karo ki field B tumhe tumhari path ke along kitna push karti hai, toh total sirf uss current par depend karta hai jo tumhare loop se guzar rahi hai — loop ki shape par nahi . Yeh Gauss's law ka magnetic cousin hai: ek symmetry shortcut jo ek mushkil integral ko algebra ki ek line mein badal deta hai.
Definition Ampère's circuital law (magnetostatic form)
Steady (time-independent) currents ke liye, kisi bhi closed loop C ke around B ka line integral, μ 0 times woh net current ke barabar hota hai jo C se bounded kisi bhi surface se guzarti hai:
∮ C B ⋅ d l = μ 0 I enc
Yahan == I enc == enclosed current hai (current jo loop ko pierce karti hai), μ 0 = 4 π × 1 0 − 7 T⋅m/A , aur C ko Amperian loop kehte hain.
WHAT it gives you: B ki magnitude — agar geometry mein kaafi symmetry ho.
WHAT it is NOT: jaise likha hai waise sirf magnetostatics ke liye valid hai (koi changing electric fields nahi). Full Maxwell version mein displacement-current term μ 0 ϵ 0 d Φ E / d t bhi add hoti hai.
Hum isse postulate nahi karte — hum isse simplest case ke liye derive karte hain aur generality ka argument dete hain.
Intuition Deeper "why" (field ka twist)
Differential form: ∇ × B = μ 0 J . Ek current curl (circulation) ka source hai, jaise charge E ke liye divergence (flux) ka source hai. Ampère's law is par Stokes' theorem apply karna hai: ∮ B ⋅ d l = ∫ ( ∇ × B ) ⋅ d A = μ 0 ∫ J ⋅ d A = μ 0 I enc .
Worked example Strategy — the 80/20 core
Symmetry pehchano (kya B sirf ek coordinate par depend karta hai?).
Ek Amperian loop choose karo jiske along B ya toh constant-aur-parallel ho ya perpendicular ho (jo 0 contribute kare).
Likho ∮ B ⋅ d l = B ( length ) .
Nikalo I enc loop se.
Solve karo B ke liye.
Worked example Worked example 2 — Inside a thick wire (radius
R , uniform J )
s < R par B nikalo.
J = π R 2 I . Kyun? current uniformly cross-section par spread hai.
Loop: circle radius s . Enclosed current sirf woh part hai jo s ke andar hai:
I enc = J ⋅ π s 2 = I R 2 s 2
Yeh step kyun? Sirf woh current count hoti hai jo loop ko thread kare; fraction = area R area s .
B ( 2 π s ) = μ 0 I R 2 s 2 ⇒ B = 2 π R 2 μ 0 I s — andar linearly badhta hai, phir bahar ∝ 1/ s .
Worked example Worked example 3 — Long solenoid (
n turns/length, current I )
Loop: rectangle, ek lamba side (L ) andar axis ke parallel, doosra bahar (jahan B ≈ 0 ), chhote sides B ke perpendicular (0 contribute karte hain).
∮ B ⋅ d l = B L . Kyun? sirf andar wala side contribute karta hai.
I enc = n L I . Kyun? loop n L turns cross karta hai, har ek I carry karta hai.
B L = μ 0 n L I ⇒ B = μ 0 n I — uniform, andar position se independent ✓.
Worked example Worked example 4 — Toroid (
N turns)
Loop: circle radius r toroid ke andar.
B ( 2 π r ) = μ 0 N I ⇒ B = 2 π r μ 0 N I . Toroid ke bahar I enc = 0 ⇒ B = 0 .
Recall Predict before checking
Ek doosri wire 2 I carry karti hui tumhare circular Amperian loop ke bahar hai. Kya ∮ B ⋅ d l change hoga?
Answer: Nahi — ∮ B ⋅ d l sirf enclosed current par depend karta hai, isliye yeh unchanged rahega (= μ 0 I ). Lekin note karo: loop ke points par local B zaroor change hoga (bahari wire field add karti hai); integral ke contributions bas cancel out ho jaate hain. Yahi subtlety hai jo log miss karte hain.
∮ B ⋅ d l = 0 hai, toh loop par har jagah B = 0 hai."
Kyun sahi lagta hai: zero total matlab zero har jagah lagta hai.
Fix: Zero sum ≠ zero har jagah — positive aur negative contributions cancel ho sakte hain. B bada ho sakta hai; sirf circulation zero hai (jaise loop wire ke paas ho lekin enclose na kare).
I enc matlab picture mein saari current."
Kyun sahi lagta hai: har current ek field banata hai.
Fix: Sirf woh current count hoti hai jo chosen surface ko pierce kare . External currents local B ko affect karte hain lekin integral mein cancel ho jaate hain.
Common mistake "Ampère's law se main kisi bhi geometry ke liye
B nikaal sakta hoon."
Kyun sahi lagta hai: law hamesha sahi hai (magnetostatics mein).
Fix: Yeh hamesha sahi hai lekin B solve karne ke liye sirf tabhi useful hai jab symmetry se B ko integral se bahar nikala ja sake (infinite wire, solenoid, toroid, planes/cylinders). Warna yeh ek equation hai bahut saare unknowns ke saath — Biot–Savart use karo.
Common mistake Isse changing currents/fields ke saath use karna.
Kyun sahi lagta hai: yeh general lagta hai.
Fix: Magnetostatic form tab fail karta hai jab ∂ E / ∂ t = 0 ; tumhe Maxwell's displacement current chahiye. Isi tarah Maxwell ne EM waves discover ki thi.
Ampère's law (integral magnetostatic form) I enc ka precise matlab kya hai?Loop C se bounded kisi bhi surface ko pierce karne wali net steady current (external currents excluded).
Ampère's law se infinite straight wire ka field B = 2 π s μ 0 I , wire ke around circular.
Wire ke liye radius cancel kyun hota hai? B ∝ 1/ s lekin loop length ∝ s ; product s -independent hota hai.
Uniform thick wire (radius R ) ke andar s < R par field B = 2 π R 2 μ 0 I s (s mein linear).
Long solenoid ke andar field B = μ 0 n I , uniform, axial.
Radius r , N turns wale toroid ke andar field B = 2 π r μ 0 N I ; bahar zero.
Ampère's law ka differential form Magnetostatic form GALAT kab hota hai? Jab electric fields time ke saath change hon; displacement current μ 0 ϵ 0 ∂ t Φ E chahiye.
Kya ∮ B ⋅ d l = 0 ho sakta hai jab loop par B = 0 ho? Haan — contributions cancel hote hain; circulation ≠ pointwise value.
Ampère's law USEFUL kab hai (sirf sahi nahi)? Jab symmetry se
B chosen loop ke along constant aur parallel (ya zero) ho.
Recall Feynman: explain to a 12-year-old
Socho ek pipe mein river current beh rahi hai (yahi electric current hai). Yeh apne aas-paas ke paani ko circles mein swirl karti hai (yahi magnetic field hai). Ampère ka rule kehta hai: agar tum pipe ke around ek full lap chalo aur track karo ki swirling tumhe tumhare steps ke along kitna push kar rahi hai, toh total push sirf iss par depend karta hai ki tumhare lap ke andar river kitni strong hai — koi farq nahi padta ki tum bada circle chalo ya wobbly weird loop, jab tak tum pipe ke around ek baar ghum lo. Agar tum ek khaali jagah ke around ghum lo (andar koi current nahi), toh pushes cancel ho jaate hain aur tumhe zero total milta hai.
"CLIME" — C irculation of B = μ 0 × L oop-I ntegral's M agnetic source = μ 0 I enc . Aur: "Sirf woh matter karta hai jo threaded ho."
generalize by polar split
B of infinite wire B=u0 I / 2 pi s
2 pi s cancels 1 / 2 pi s
Displacement current term