1.8.17 · Physics › Electromagnetism
Intuition Core picture kya hai
Resistors bas flowing charge ke liye "obstacles" hain. Poora game do sawaalon par tika hai:
Series: "Kya same current ko har resistor se ek ke baad ek guzarna padta hai?" → resistances add hote hain.
Parallel: "Kya resistors apne ends par same voltage share karte hain kyunki woh same do nodes ke beech wire hue hain?" → unki conductances (1/R) add hoti hain.
WHY ye matter karta hai: koi bhi ulajha hua network ek single equivalent resistor mein collapse ho sakta hai, toh tum ek hi step mein battery se total current nikaal sakte ho.
Definition Equivalent resistance
Kisi combination ki equivalent resistance R e q woh single resistance hai jo same applied voltage ke liye source se same current kheenchegi. Formally R e q ≡ V / I jahaan V poore combination ke across voltage hai aur I usme enter karne wali current.
Hum sab kuch sirf do laws se derive karte hain:
Ohm's law: V = I R (WHAT: ek resistor ke across voltage = current × uski resistance).
Kirchhoff's laws:
KVL (loop): ek loop mein voltages ka sum zero hota hai → ek single line mein, applied V resistors mein split hoti hai.
KCL (node): current in = current out → ek junction par currents split/recombine hoti hain.
Intuition Series mein current kyun SAME hoti hai har jagah
Sirf ek hi path hai. Charge pile up ya vanish nahi ho sakti (KCL), toh jo bhi current pehle resistor mein enter karti hai woh aakhri se nikalni chahiye. Sabmein same I .
Setup: R 1 , R 2 , … , R n ek single line mein, chain ke across total voltage V , current I .
HOW (derive): Har ek ke across voltage (Ohm se): V k = I R k .
KVL se applied voltage drops ke sum ke barabar hai:
V = V 1 + V 2 + ⋯ + V n = I R 1 + I R 2 + ⋯ + I R n = I ∑ k R k
Kyunki R e q = V / I :
R ser i es = R 1 + R 2 + ⋯ + R n
Intuition Parallel resistors ke across voltage kyun SAME hoti hai
Har parallel resistor ke dono ends same do nodes se tied hain. Voltage nodes ke beech ka difference hota hai, toh har resistor ko identical V feel hoti hai.
Setup: R 1 , … , R n sab node A aur node B ke beech connected hain. Common voltage V , total current I jo A mein enter karti hai.
HOW (derive): Har ek se current (Ohm se): I k = V / R k .
KCL se total current branches mein split hoti hai:
I = I 1 + I 2 + ⋯ + I n = R 1 V + R 2 V + ⋯ + R n V = V ∑ k R k 1
Kyunki R e q 1 = V I :
R p a r a l l e l 1 = R 1 1 + R 2 1 + ⋯ + R n 1
Worked example 1 — Do series mein
R 1 = 3 Ω , R 2 = 6 Ω , battery V = 9 V.
R e q = 3 + 6 = 9 Ω . Kyun? Same current path → add karo.
I = V / R e q = 9/9 = 1 A. Kyun? Poori chain par Ohm.
Drops: V 1 = 1 ⋅ 3 = 3 V, V 2 = 1 ⋅ 6 = 6 V. Kyun? Har ek I R k hai; note karo 3 + 6 = 9 ✓ (KVL check).
Worked example 2 — Do parallel mein
Same R 1 = 3 , R 2 = 6 , same V = 9 V.
R e q = 3 + 6 3 ⋅ 6 = 9 18 = 2 Ω . Kyun? Product over sum.
I = 9/2 = 4.5 A battery se. Kyun? Equivalent par Ohm.
Branches: I 1 = 9/3 = 3 A, I 2 = 9/6 = 1.5 A. Kyun? Dono ko poora 9 V milta hai; 3 + 1.5 = 4.5 ✓ (KCL check).
Note karo R e q = 2 Ω < 3 Ω (sabse chota) ✓.
Worked example 3 — Mixed network (step by step collapse)
R 1 = 4 Ω series mein ek parallel pair R 2 = 6 , R 3 = 12 ke saath. V = 10 V.
Step A: parallel pair = 6 + 12 6 ⋅ 12 = 18 72 = 4 Ω . Kyun? Woh do nodes share karte hain.
Step B: ab 4 Ω (series) + 4 Ω = 8 Ω . Kyun? Same current R 1 se aur phir combined block se guzarti hai.
I = 10/8 = 1.25 A battery se.
Parallel block ke across voltage = I ⋅ 4 = 5 V → I 2 = 5/6 ≈ 0.83 A, I 3 = 5/12 ≈ 0.42 A (sum = 1.25 ✓).
Worked example 4 — Forecast-then-Verify
Forecast: Teen equal R = 12 Ω parallel mein. Compute karne se pehle R e q guess karo.
Verify: R e q 1 = 12 3 ⇒ R e q = 4 Ω . General rule: n equal R parallel mein R / n dete hain. (Aur series mein n R = 36 Ω dete hain.)
Common mistake "Parallel resistance bas resistances ka sum hoti hai."
Kyun sahi lagta hai: series mein add hota hai, toh log pattern-match karke phir add kar dete hain. Sach yeh hai: parallel mein tum conductances 1/ R add karte ho, R nahi. R add karne se R e q bada hota — lekin zyada paths add karne se current ke liye easier hona chahiye → chota R e q . Fix: "zyada raaste = kam total resistance."
Common mistake End mein reciprocal lena bhool jaana.
Kyun sahi lagta hai: tumne sahi likha R e q 1 = R 1 1 + R 2 1 aur phir us sum ko hi answer bata diya. Fix: woh sum 1/ R e q hai; R e q paane ke liye tumhe use flip karna hoga.
Common mistake Same dikhne wali wires ko series treat karna jab ek junction current split kar raha ho.
Kyun sahi lagta hai: diagram "ek line jaisi lagti hai." Fix: poochho "kya koi node hai jahaan current divide hoti hai?" Agar current split ho → parallel branches; sirf ek unbranched single path series hai.
Common mistake Yeh assume karna ki har parallel branch mein equal current hoti hai.
Kyun sahi lagta hai: sab same voltage share karte hain. Fix: same V hai, lekin I k = V / R k — chota resistor ZYADA current leta hai .
Recall Feynman: ek 12-saal ke bachche ko explain karo
Paani ke pipes socho. Series = ek lamba pipe jisme kai tange choke ek ke baad ek hain; paani ko har choke se squeeze hona padta hai, toh chokes ki "difficulty" pile up hoti hai — total mushkil ho jaata hai. Parallel = same paani ek aise jagah pahunchta hai jahaan woh kai side-by-side pipes mein split ho sakta hai; zyada pipes matlab paani overall asaan se bahta hai, toh total difficulty sabse asaan single pipe se bhi neeche aa jaati hai. Series chain mein har jagah same paani-per-second; har side-by-side pipe ke across same paani-pressure.
Mnemonic Yaad karo kaun sa kaun sa hai
"S eries = S ame current, resistances S um."
"P arallel = P otential same, P ieces 1/ R add karo (reciprocals)."
Picture: series = soldiers ek line mein; parallel = doors side by side (zyada doors, tezi se crowd, "kam blockage").
Series mein, har resistor ke liye kaun si quantity identical hoti hai? Current I (single path, KCL).
Parallel mein, har resistor ke liye kaun si quantity identical hoti hai? Voltage V (same do nodes).
Series equivalent resistance formula? R e q = R 1 + R 2 + ⋯ + R n .
Parallel equivalent resistance formula? R e q 1 = R 1 1 + ⋯ + R n 1 .
Do-resistor parallel shortcut? R e q = R 1 + R 2 R 1 R 2 (product over sum).
Kya series R e q har resistor se bada hota hai ya chota? Kisi bhi single se bada.
Kya parallel R e q har resistor se bada hota hai ya chota? Sabse chote se bhi chota.
n equal resistors R parallel mein kya dete hain?R / n .
Parallel mein, kaun sa resistor zyada current leta hai? Chota resistance (I k = V / R k ).
Ye formulas kaun si do laws se derive hoti hain? Ohm's law + Kirchhoff's (KVL for series, KCL for parallel).
Series chain mein voltages kaise relate karte hain? Woh applied voltage mein add hote hain (KVL).
Parallel junction par currents kaise relate karti hain? Woh total current mein add hoti hain (KCL).
Ohm's Law — woh V = I R jo har step par use hoti hai.
Kirchhoff's Laws — KVL (series) aur KCL (parallel) in rules ka asli source hain.
Resistivity and Resistance — jahaan se ek single R aata hai (R = ρ L / A ).
EMF and Internal Resistance — internal resistance battery ke saath series mein hoti hai.
Wheatstone Bridge — aisi networks jo purely series ya parallel nahi hain.
Power in Circuits — P = I 2 R = V 2 / R combination mein distribute hoti hai.
Equivalent resistance Req=V/I
Req larger than any resistor
Req smaller than smallest
Two-resistor shortcut product over sum