1.8.10 · Physics › Electromagnetism
Ek equipotential surface woh sheet hoti hai jis par har point ka same electric potential V hota hai. Sabse important fact geometric hai: ==electric field E hamesha ek equipotential surface ke perpendicular hota hai==.
YEH INEVITABLE KYUN LAGTA HAI? Agar E ka koi bhi component surface ke along hota, toh woh component kisi charge ko surface ke andar push karta — kaam karta — aur ek charge ko do same-potential points ke beech move karne mein zero kaam lagta hai. Contradiction hai. Toh E ka surface-ke-andar wala component zero hona chahiye, sirf perpendicular part bachta hai.
Definition Equipotential surface
Ek surface (points ka locus) jis par electric potential ka ek hi constant value hota hai:
V ( x , y , z ) = constant .
Jab koi charge aise surface ke along move karta hai toh electric force koi bhi kaam nahi karta.
Definition "Iske along kaam kyun nahi hota"
Charge q ko point A se B tak move karne mein kiya gaya kaam:
W A B = q ( V A − V B ) .
Agar A , B same equipotential par hain, toh V A = V B , isliye W A B === 0 == surface par kisi bhi path ke liye.
Hum field aur potential ke beech sabse fundamental relation se shuru karte hain.
Step 1 — Work–potential link.
Ek chhoti displacement d l ke liye, kaam per unit charge hai
d V = − E ⋅ d l .
Yeh step kyun? Yeh potential difference ki definition hai: V girta hai jab tum field ke along move karte ho, isliye minus sign "potential E ki direction mein girta hai" track karta hai.
Step 2 — d l ko surface ke andar restrict karo.
Ek equipotential par, V change nahi hota, toh d V = 0 kisi bhi in-surface step ke liye:
0 = − E ⋅ d l (tangent) .
Yeh step kyun? Hum deliberately woh displacements choose karte hain jo surface par rehti hain, kyunki wahi moves hain jo V ko constant rakhti hain.
Step 3 — Dot product ko interpret karo.
E ⋅ d l (tangent) = 0 har tangent d l ke liye.
Dot product zero hota hai (jab dono vectors nonzero hon) sirf tab jab woh perpendicular hoon. Kyunki d l kisi bhi tangent direction mein point kar sakta hai, E ko sabhi ke perpendicular hona chahiye — yaani surface ke hi perpendicular.
E ⊥ equipotential surface
Yeh step kyun? "Har in-surface direction ke perpendicular" — yahi toh "surface ka normal" ki definition hai.
Intuition Magnitude bonus: spacing strength batata hai
Do equipotentials ke beech ek tiny perpendicular distance d n move karo, jo d V se differ karti hain:
E = − d n d V .
Jahan equipotentials paas paas packed hain, E bada hota hai (steep potential hill); jahan woh door door hain, E weak hota hai. Map par contour lines ke baare mein socho: closely bunched contours = steep slope = strong "force."
Worked example 1. Point charge — concentric spheres
Origin par + Q ke liye, V = 4 π ε 0 1 r Q .
V = const ⇒ r = const, toh equipotentials Q par centred spheres hain.
Field radial hai: E = 4 π ε 0 1 r 2 Q r ^ .
Perpendicular kyun? r ^ bilkul har sphere ka outward normal hai — toh E har sphere ko 9 0 ∘ par pierce karta hai. ✓
Uneven spacing kyun? Equal Δ V wale spheres r badhne par door hote jaate hain (kyunki V ∼ 1/ r ), jo E ∼ 1/ r 2 ke weak hone se match karta hai. ✓
Worked example 2. Uniform field (parallel plates)
E = E x ^ (constant). Tab V = − E x + C , toh V = const ⇒ x = const: equipotentials flat planes hain x ^ ke ⊥ .
Equal Δ V steps se equally spaced planes milti hain (kyunki V , x mein linear hai), jo confirm karta hai E uniform hai.
Yeh kyun matter karta hai: yeh explain karta hai ki charged parallel-plate capacitor ke andar evenly-spaced equipotential sheets kyun hoti hain.
Worked example 3. Electrostatics mein conductor ki surface
Conductor ke andar E = 0 , toh V poore andar constant hai — poora conductor ek equipotential hai, uski surface bhi.
Isliye bahar, E ko surface ke perpendicular hona chahiye. Agar nahi hota, toh tangential component free electrons ko push karta jab tak woh rearrange hokar use cancel na kar dete.
Yeh killer application kyun hai: isliye field lines metal surfaces ko exactly 9 0 ∘ par hit karti hain.
Common mistake "Equipotentials aur field lines parallel hain."
Kyun sahi lagta hai: dono diagrams mein "lines" dikhti hain, aur field lines clearly kaheen jaati hain , toh aap imagine karte ho ki equipotential saath-saath chal rahi hai.
Fix: woh perpendicular hain, parallel nahi. Field lines equipotentials ke across point karti hain (V mein downhill). Mantra: field lines neeche jaati hain, equipotentials wrap karti hain.
Common mistake "Kaam surface ke along path par depend karta hai."
Kyun sahi lagta hai: roz ki zindagi mein lambe paths par zyada kaam hota hai.
Fix: electric force conservative hai; W = q ( V A − V B ) sirf endpoints par depend karta hai. Ek equipotential par V A = V B toh W = 0 path length se independent hai.
Common mistake "Do alag equipotential surfaces touch/cross kar sakti hain."
Kyun sahi lagta hai: contour lines saddle par milti hui lag sakti hain.
Fix: crossing point par ek saath do values of V honge — yeh impossible hai. Alag V ki equipotentials kabhi intersect nahi karti .
Common mistake "Equally spaced equipotentials ka matlab hamesha equal field hota hai."
Kyun sahi lagta hai: map ka intuition.
Fix: sirf tab sach hai jab unhe equal Δ V increments par draw karo. Equal Δ V + equal spacing ⇒ uniform E ; equal Δ V + closer spacing ⇒ stronger E .
Recall Feynman: ek 12-saal ke bachche ko explain karo
Ek pahaad imagine karo. Zameen ki height voltage jaisi hai. Woh curved lines jo "sab points same height par" trace karti hain, woh hiking map par wali contour lines hain — woh equipotentials hain. Ek ball hamesha seedha sabse steep raaste se neeche ludkti hai , jo exactly un same-height lines ke right angles par hoti hai. Woh steepest-downhill arrow electric field hai. Toh field aur equal-height lines hamesha ek + sign jaisi cross karti hain. Aur jahan contour lines crowd ho jaati hain (cliff), slope steep hota hai — wahan strong field hoti hai.
"E cuts V at 90, downhill all the time."
( E lectric field equiV potentials ko right angles par cuts karta hai, lower potential ki taraf point karta hai. )
Equipotential surface kya hoti hai? Woh surface jis par electric potential V har point par same hota hai.
Equipotential ke along charge move karne mein kaam kyun nahi hota? Kyunki W = q ( V A − V B ) aur surface par V A = V B , toh W = 0 kisi bhi path ke liye.
E aur equipotential surface ke beech angle kya hota hai?9 0 ∘ — field hamesha uske perpendicular (normal) hota hai.
Derive karo kyun E ⊥ equipotential. Tangent step
d l ke liye,
d V = − E ⋅ d l = 0 ; nonzero vectors ka dot product sabhi tangent directions ke liye zero ⇒
E surface ka normal hai.
Field aur potential ka relation (vector form)? E = − ∇ V ; gradient constant-
V surfaces ke perpendicular hota hai aur higher
V ki taraf point karta hai, toh
E lower
V ki taraf point karta hai.
Equipotential spacing se field ka magnitude? E = − d n d V ; closely spaced equipotentials (equal Δ V ke liye) strong field matlab hain.
Point charge ke liye equipotentials ki shape? Charge par centred concentric spheres.
Uniform field mein equipotentials ki shape? E ke perpendicular flat planes, equal
Δ V ke liye equally spaced.
Conductor ki surface equipotential kyun hoti hai? Andar
E = 0 toh
V poore andar constant hai; isliye surface bhi equipotential hai aur
E bahar uske perpendicular hota hai.
Kya alag V ki do equipotentials cross kar sakti hain? Nahi — crossing point par ek saath do potential values honge, jo impossible hai.
E potential ke relative kis direction mein point karta hai?Higher potential se lower potential ki taraf (V mein downhill).
along move karne mein koi kaam nahi
tangent tak restrict karo
gradient constant V ka normal
spacing strength deta hai
Equipotential surface V constant
W_AB = q times V_A minus V_B = 0
Koi in-surface E component nahi
E surface ke perpendicular