Hum sirf F=−kx se start karte hain aur bina koi answer memorize kiye x(t) tak pahunchte hain.
Step 1 — Newton's law likho.mdt2d2x=−kx.Yeh step kyon? Force = mass × acceleration, aur acceleration position ka second time-derivative hota hai.
Step 2 — ω2=k/m define karo taaki clean ho jaye.dt2d2x=−ω2x.Yeh step kyon? Ab yeh ek pure math question hai: "kaunsa function do derivatives ke baad minus ek constant times itself ke equal hota hai?"
Step 3 — Ek aisi function guess karo jiska 2nd derivative sign flip kar de.
Try karo x=Acos(ωt+ϕ).
dtdx=−Aωsin(ωt+ϕ),dt2d2x=−Aω2cos(ωt+ϕ)=−ω2x.✓Yeh step kyon? Sine aur cosine sirf wohi smooth functions hain jo do baar differentiate karne ke baad khud mein (sign ke saath) return karte hain — isliye yeh zaroor SHM describe karte hain.
Step 4 — Physics padhlo.
A = amplitude (max displacement), initial conditions se set hota hai.
ϕ = phase constant, yeh set hota hai ki woh kahan se shuru hua.
SHM define karne wali do conditions kya hain? → equilibrium ki taraf restoring force aur∝ displacement.
Speed max kahan hai / acceleration max kahan hai? → speed max x=0 par; acceleration max x=±A par.
Kya T, A par depend karta hai? → Nahi.
F=−kx aur F=ma se ω derive karo. → ω=k/m.
Recall Feynman: 12-saal ke bacche ko explain karo
Socho ek ball ek smooth bowl ke bottom mein rakh rakhi hai. Agar tum use nudge karo, woh roll karke wapas aati hai. Jitna zyada tum use side mein push karo, utna zyada bowl use ghar push karta hai — do guna door, do guna push. Kyunki push itne neatly badhta hai, ball bilkul steady rhythm mein aage-peeche rock karti hai, jaise ek clock. Choti nudge aur badi nudge dono aage-peeche jaane mein same time lete hain — yahi steady rhythm "simple harmonic motion" hai. Ek spring ke saath weight bhi exactly yahi dance karta hai.