Key word hai same point — τ aur L dono ek hi origin ke baare mein measure hone chahiye (aur woh origin inertial ya non-accelerating hona chahiye, ya phir centre of mass).
Hum Newton's second law se shuru karte hain aur rotational law build karte hain — koi memorising nahi.
Step 1 — Ek particle ke angular momentum se shuru karo.L=r×pYeh step kyun? Yeh definition hai; sab kuch ise differentiate karne se nikalega.
Step 2 — Time ke saath differentiate karo (cross products ke liye product rule):
dtdL=dtdr×p+r×dtdpYeh step kyun?L time ke through r aur p dono se depend karta hai, isliye dono differentiate hote hain.
Step 3 — Pehla term khatam karo.dtdr×p=v×(mv)=m(v×v)=0Yeh step kyun? Kisi bhi vector ka cross product khud apne aap se zero hota hai (sin0°=0). Toh velocity-with-momentum kuch contribute nahi karta.
Step 4 — Doosre term par Newton's law use karo.dtdp=F⇒r×dtdp=r×F=τYeh step kyun? Newton's 2nd law deta hai F=dp/dt; aur r×F torque ki definition hai.
Bahut saare particles ke liye, sab par sum karo: Ltot=∑Li, toh
dtdLtot=∑iτi=τext+=0τint
Ek rigid body ke liye jo fixed axis ke around spin kar rahi hai, L=Iω ke saath (jahan I us axis ke baare mein moment of inertia hai):
τext=dtd(Iω)=Idtdω=Iα(if I constant)
Yahi famous τ=Iα hai — rotational F=ma. Lekin τ=dL/dtzyada general hai: yeh tab bhi hold karta hai jab I change ho (jaise ek spinning skater apne arms andar kheench le).
Socho tum ek spinning office chair par ho aur haath bahar nikal ke bhari books pakde ho. Jab tum books ek jhatkay mein apni chest ke paas kheechte ho, tum achanak tezi se spin karne lagte ho — whee! Kisine tumhe push nahi kiya. "Spinning-amount" (angular momentum) same rehna chahta hai, isliye jab tum khud ko chhota karte ho (kam spread out), tumhe balance rakhne ke liye tezi se spin karna padta hai. Ek torque hi ek aisi cheez hai jo us spinning-amount ko badal sakti hai, aur torque bas ek off-centre twist hai — jaise darwaza handle ke paas push karna, hinge ke paas nahi.
Newton's second law ka fundamental rotational form kya hai?
τext=dL/dt (net external torque = same point ke baare mein angular momentum ka rate of change).
τ=dL/dt derive karte waqt, dtdr×p term kyun vanish ho jaata hai?
Kyunki yeh v×mv=m(v×v)=0 ke barabar hai — kisi vector ka cross product khud se zero hota hai.
Particles ke system ke liye internal torques kyun cancel hote hain?
Internal forces Newton's-3rd-law pairs hain jo joining line ke along act karte hain; unke torques equal, opposite, aur collinear hote hain, isliye sum zero ho jaata hai.
τ=Iα kab valid hai lekin τ=dL/dt hamesha valid kyun hai?
τ=Iα ke liye I = constant chahiye; τ=dL/dt=d(Iω)/dt changing I ko bhi handle karta hai.
Ek skater ka I 6 se 2 kg·m² ho jaata hai jab woh 2 rad/s par spin kar rahi thi. Naya ω?
I1ω1=I2ω2⇒ω2=12/2=6 rad/s.
Kya straight line mein chal rahe particle ka off-line point ke baare mein angular momentum hota hai?
Haan: L=mvd jahan d perpendicular distance hai; yeh constant hai kyunki torque zero hai.
Agar net external torque zero hai, toh kya conserve hota hai?
Angular momentum L (magnitude aur direction dono mein constant).
Kya angular momentum conserve hone par kinetic energy bhi conserve hoti hai?
Zaroori nahi — internal work (jaise skater ke muscles) KE change kar sakte hain jabki L fixed rahe.