1.5.6 · D1 · Physics › Rotational Mechanics › Parallel axis theorem — I = I_CM + Md² — proof
Kisi object ko spin karna sabse aasaan hota hai uss axis ke baare mein jo uske balance point (center of mass) se guzarti hai; kisi bhi doosri parallel line ke baare mein spin karna zyada mushkil hota hai — bilkul utna jitna poori mass ko ek dot ki tarah distance d par swing karne mein lagta. Yeh page — bilkul scratch se — har ek symbol (m i , r i , Σ , ∫ , I , CM, d , x i , y i ) build karta hai jo proof I = I C M + M d 2 silently assume karta hai.
Parent proof follow karne se pehle, tumhe uska alphabet already pata hona chahiye. Neeche, har symbol ke saath plain words → ek picture → yeh topic ko kyun chahiye — is order mein taaki har naya symbol sirf pehle wale pe hi lean kare.
Plain words: ek solid object jinke parts kabhi ek doosre ke relative move nahi karte — yeh poori tarah spin aur slide kar sakta hai, lekin squeeze ya bend nahi ho sakta.
Picture: ek metal spanner, ek wooden rod, ek disc — ek frozen shape.
Topic ko kyun chahiye: poora theorem ek spinning shape ke baare mein hai. Agar shape deform ho sakti, toh "moment of inertia" badle rahegi aur prove karne ke liye kuch fixed hi nahi hoga.
Kisi bhi shape ke saath physics karne ke liye, hum pretend karte hain ki woh tiny bricks se bani hai.
m i
Plain words: imagine karo ki body ko bahut saare tiny chunks mein kaata gaya hai. i -wa tiny chunk ka mass m i hai. Chhota subscript i sirf ek name tag hai — chunk 1, chunk 2, chunk 3, … — taaki hum ek waqt mein ek ke baare mein baat kar sakein.
Picture: body ek grid of dots mein bikhar gayi, har dot ek chhota mass m i carry kar raha hai.
Topic ko kyun chahiye: spinning inertia "object as a blob" ki property nahi hai — yeh depend karta hai har bit of mass kahan baith rahi hai . Isliye hum mass ko piece by piece track karte hain.
Saare chunk masses add karo toh poora recover ho jaata hai:
∑ i m i = M
Definition Summation symbol
∑
Plain words: ∑ i ka matlab hai "har chunk i ke liye is quantity ko add karo." Yeh sirf ( chunk 1 ) + ( chunk 2 ) + ( chunk 3 ) + … likhne ka compact tarika hai.
Picture: ek conveyor belt jo har dot ko ek running total mein feed kar rahi hai.
Topic ko kyun chahiye: object mein millions of chunks hain; hum million plus-signs nahi likh sakte, isliye ∑ unhe ek symbol mein pack kar deta hai.
M
Plain words: har chunk ke mass ka sum — woh number jo ek kitchen scale read karta.
Picture: saare dots ek scale par daale gaye.
Topic ko kyun chahiye: correction term M d 2 poori mass ko ek lump ki tarah treat karta hai, isliye hum yeh grand total chahiye.
Yeh batane ke liye ki chunk kahan hai, hum ek address system chahiye.
( x i , y i )
Plain words: ek fixed reference point (origin ) aur do perpendicular measuring directions chuno (x -axis, horizontal; y -axis, vertical). Phir x i = chunk i kitna right mein hai, y i = kitna upar hai. Milke ( x i , y i ) chunk ka address hai.
Picture: body ke upar graph paper bikhaaya; har dot do numbers read karta hai.
Topic ko kyun chahiye: axis-tak-ki-distance (aage aayegi) inhi coordinates se compute hoti hai. Address nahi → distance nahi.
z i ko kyun ignore kar sakte hain
Proof mein spin axis seedha "page se bahar" point karta hai (z direction). Kisi chunk ki ek vertical line tak distance is baat pe depend nahi karti ki woh us line ke along kitna upar ya neeche hai — sirf is baat pe depend karta hai ki woh sideways kitna dur hai. Isliye sirf x i aur y i matter karte hain, aur z i quietly nikal jaata hai. Isliye proof flat x y -plane mein kaam karta hai.
Definition Axis tak perpendicular distance,
r i
Plain words: ek chunk ko spin axis (ek seedhi vertical line) ke paas khado. Chunk se us line tak ki sabse chhoti distance — seedhe across, right angle pe naapi gayi — woh r i hai.
Picture: dot se axis tak ek seedha rope, axis se 9 0 ∘ pe milta hua.
Topic ko kyun chahiye: jab body spin karti hai, har chunk r i radius ke circle mein travel karta hai. Woh radius hi chunk ki position ki ek maatra cheez hai jo spin ko affect karti hai.
Address ( x i , y i ) pe Pythagoras rule se, jab axis origin se guzarti hai:
r i 2 = x i 2 + y i 2
Square kyun, aur yeh exact combination kyun?
Address ( x i , y i ) par ek chunk origin se r i straight-line distance par baith a hai. Pythagoras kehta hai (horizontal leg)² + (vertical leg)² = (hypotenuse)², yaani x i 2 + y i 2 = r i 2 . Hum ise r i 2 ke roop mein rakhte hain (square root lene ki takleef nahi karte) kyunki — jaise agli section dikhayegi — inertia ko waise bhi squared distance chahiye. Kaam ki coincidence hai, isliye hum ise squared chhodde hain.
Definition Moment of inertia
I
Plain words: ek akela number jo measure karta hai ki kisi chosen axis ke baare mein ek body ko start ya stop karna kitna mushkil hai — spin-laziness. Bada I = spin karne mein zyada stubborn.
Picture: axis se dur baithe mass (bada r i ) ki tarah hai ek bachcha see-saw ke dur wale end par — swing karna mushkil. Axis se chipki mass barely resist karti hai.
Topic ko kyun chahiye: poora theorem I ke baare mein ek statement hai — jab axis shift hoti hai toh yeh kaise badalta hai.
I = ∑ i m i r i 2
Intuition Is formula ko loud padhna
Har chunk ke liye, uski mass m i ko uske distance-squared r i 2 se multiply karo, phir saare chunks mein add karo. r 2 hi poori wajah hai ki distance itna violently matter karta hai: do guna dur baithe chunk ki inertia chaar guna hoti hai. Yahi squaring exact wajah hai ki correction M d 2 hai na ki M d .
Is quantity ki poori kahani ke liye dekho Moment of inertia — definition .
∫ r 2 d m
Plain words: agar chunks infinitely tiny aur infinitely many ho jaayein, toh sum ∑ smooth symbol ∫ ("integral") mein badal jaata hai, aur m i ban jaata hai d m ("mass ka ek infinitesimal scrap"). Matlab waahi hai — r 2 ko saari mass pe add karo — bas ek continuous body ke liye.
Picture: dots ki grid ek smooth cloud mein shrink ho jaati hai; conveyor belt hamesha chalti rehti hai.
Topic ko kyun chahiye: real bodies smooth hoti hain, isliye parent note dono ∑ m i r i 2 aur ∫ r 2 d m likhta hai. Yeh ek idea ke discrete aur continuous roop hain. Har ∫ ko tum "bahut baareek ∑ " padh sakte ho.
Definition Center of mass (CM)
Plain words: woh akela point jahan body ek ungali par perfectly balance karegi — saare chunks ki mass-weighted "average position."
Picture: ek spanner ek ungali par flat balanced; ungali CM ke neeche hai.
Topic ko kyun chahiye: theorem tabhi kaam karta hai jab ek axis is point se guzarti hai. Yeh woh privileged reference hai jis se har doosri axis naapi jaati hai.
CM ka address saare chunk addresses ka mass-se-weighted average hai:
x C M = M ∑ i m i x i , y C M = M ∑ i m i y i
Ise compute karne ke liye dekho Center of mass — definition and computation .
Intuition Woh trick jo proof ko clean banati hai
Proof mein hum origin ko bilkul CM par rakhte hain . Tab x C M = 0 aur y C M = 0 , jo force karta hai ki
∑ i m i x i = 0 , ∑ i m i y i = 0.
Yeh woh "cross terms" hain jo parent derivation mein vanish ho jaate hain. Note karo yeh magic nahi hai — yeh CM ki definition ulti padhna hai: mass-weighted position average theek tab zero hoti hai jab tum balance point se hi measure karo.
Plain words: do seedhi lines jo same direction mein point karti hain aur kabhi nahi miltin — jaise ek train track ki do rails, dono "page se bahar" ja rahi hain.
Picture: do vertical pins side by side khade; ek CM se guzarta hua, ek kahin aur.
Topic ko kyun chahiye: theorem CM-axis ke baare mein I aur same tilt ki ek doosri axis ke baare mein I compare karta hai. Agar axes parallel nahi hote, toh simple + M d 2 hold nahi karta.
d
Plain words: do parallel axes ke beech ka perpendicular gap — CM-axis se doosri axis tak ki sabse chhoti, straight-across distance.
Picture: do pins ko bridge karta hua ek ruler right angles par rakha.
Topic ko kyun chahiye: d measure karta hai ki tum axis ko aasaan CM position se kitna door le gaye ho, aur extra spin-laziness M d 2 hai.
Agar doosri axis x y -plane mein address ( a , b ) par pierce karti hai jabki CM-axis origin par hai, tab Pythagoras se:
d 2 = a 2 + b 2
Common mistake Sabse common
d ki galti
d pins par chosen koi bhi do points ke beech koi bhi distance nahi hai. Yeh perpendicular gap hai — us line ke along naapa gaya jo dono axes se 9 0 ∘ par milti hai. Ek slanted distance lo aur har number galat ho jaayega. (Parent note mein Mistake B dekho.)
Rigid body one fixed shape
Mass element mi with name tag i
Summation symbol adds over all chunks
Coordinates xi yi address of a chunk
Perpendicular distance ri squared
Moment of inertia I = sum mi ri squared
Center of mass balance point
Origin at CM makes sum mi xi = 0
Two parallel axes distance d apart
Upar se neeche padho: chunks se mass aur addresses milte hain → addresses se distances milti hain → distances se I milta hai → CM cross terms ko khatam karta hai → parallel-axis geometry d supply karta hai → theorem nikal aata hai.
Worked example Kya squared distance sach mein aisa behave karta hai?
Do equal point masses m ek light rod par, ek x = + 1 par, ek x = − 1 par (units: metres, kg). Origin se guzarne wali vertical axis ke baare mein spin karo (unka CM).
I C M = m ( 1 ) 2 + m ( 1 ) 2 = 2 m .
Ab axis ko x = 3 par shift karo (toh d = 3 ). Direct sum: distances hain ∣3 − 1∣ = 2 aur ∣3 − ( − 1 ) ∣ = 4 .
I = m ( 2 ) 2 + m ( 4 ) 2 = 4 m + 16 m = 20 m .
Theorem prediction total mass M = 2 m , d = 3 ke saath:
I C M + M d 2 = 2 m + ( 2 m ) ( 3 ) 2 = 2 m + 18 m = 20 m ✓
Dono agree karte hain — foundations parent ke I = I C M + M d 2 ke saath consistent hain.
Recall Self-test: kya tum har ek ko ek plain sentence mein explain kar sakte ho?
Rigid body kya hai? ::: Ek solid jinke parts kabhi ek doosre ke relative move nahi karte — yeh ek frozen shape ki tarah poori tarah spin karta hai.
m i ka kya matlab hai? ::: Body ko jis i -we tiny chunk mein kaata gaya hai uski mass — uski kalpna ki gayi hai.
∑ i kya karta hai? ::: Har chunk i ke liye ek quantity add karta hai — bahut saare plus-signs ki chain ka shorthand.
M kya hai? ::: Total mass, ∑ i m i — jo scale read karta hai.
x i , y i kya represent karte hain? ::: Ek chosen origin se chunk i ka sideways aur upward address.
z i ko kyun ignore kar sakte hain? ::: Ek vertical axis tak ki distance sirf sideways position par depend karti hai, axis ke along height par nahi.
r i kya hai aur square kyun? ::: Ek chunk se axis tak ki perpendicular distance; r i 2 = x i 2 + y i 2 , aur inertia square use karta hai isliye door ki mass bahut zyada count hoti hai.
Moment of inertia I kya hai? ::: Ek number, ∑ i m i r i 2 , jo measure karta hai ki body ko ek axis ke baare mein start ya stop karna kitna mushkil hai.
∫ r 2 d m kya hai? ::: Ek smooth body ke liye ∑ m i r i 2 ka continuous version — same idea, infinitely baareek chunks.
Center of mass kya hai? ::: Mass-weighted average position — woh point jahan body balance hoti hai.
Proof mein ∑ m i x i aur ∑ m i y i kyun vanish ho jaate hain? ::: Kyunki origin CM par rakha jaata hai, jahan mass-weighted position average zero hoti hai.
Parallel axes kya hain? ::: Do lines jo same direction mein point karti hain aur kabhi nahi miltin.
d kya hai? ::: Do parallel axes ke beech ki perpendicular (sabse chhoti, right-angle) distance.