1.1.3Measurement, Vectors & Kinematics

Dimensional analysis — checking equations, deriving relations

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WHAT are dimensions?

Examples built from first principles (always go back to the definition of the quantity):

Quantity Defined as Dimension
Velocity displacement / time [LT1][L T^{-1}]
Acceleration velocity / time [LT2][L T^{-2}]
Force mass × acceleration [MLT2][M L T^{-2}]
Work / Energy force × distance [ML2T2][M L^2 T^{-2}]
Pressure force / area [ML1T2][M L^{-1} T^{-2}]
Power energy / time [ML2T3][M L^2 T^{-3}]

The Principle of Homogeneity (the engine)

WHY does this rule exist? Because addition only makes sense between identical kinds. "5 metres + 3 seconds" has no meaning — there is no number that is both. So if a formula adds two terms, nature forces them to be the same dimension.

Corollaries (memorise the consequences, not the lines):

  • Arguments of sin,cos,ln,ex\sin,\cos,\ln,e^x must be dimensionless (you can't take the sine of "2 metres").
  • Exponents and angles are dimensionless.
  • A pure number has dimension [M0L0T0][M^0L^0T^0].

USE 1 — Checking an equation


USE 2 — Deriving a relation (the powerful trick)


Limitations (know the boundaries)


80/20 — the few things that earn the marks


Flashcards

What does the dimension of a quantity tell you?
How it is built from base quantities M,L,TM,L,T — its kind, independent of the chosen unit.
State the principle of homogeneity.
Every term added or equated in a valid equation must have identical dimensions.
Dimension of force?
[MLT2][M L T^{-2}] (from F=maF=ma).
Dimension of energy/work?
[ML2T2][M L^2 T^{-2}] (force × distance).
Dimension of pressure?
[ML1T2][M L^{-1} T^{-2}] (force / area).
Dimension of power?
[ML2T3][M L^2 T^{-3}] (energy / time).
Why must the argument of sin\sin or exe^x be dimensionless?
These functions equal sums of powers of their argument; adding xx to x2x^2 requires xx to be a pure number.
Can dimensional analysis prove an equation correct?
No — it's blind to pure numbers (like 12\tfrac12), signs in sums, and trig/exp forms; it can only disprove or fail to disprove.
A failed dimensional check means?
The equation is definitely wrong.
Derive how pendulum period scales with \ell and gg.
T=kagcT=k\,\ell^a g^c; matching L,TL,T gives a=12, c=12a=\tfrac12,\ c=-\tfrac12, so T/gT\propto\sqrt{\ell/g}.
Why is the pendulum period independent of mass?
Matching the power of MM gives b=0b=0 since gg and \ell carry no mass.
Three failures of the derivation method?
Can't find numeric constants; fails when unknowns > base dimensions; can't build multi-term (sum) formulas.
Convert 1 N to dyne using dimensions.
[F]=MLT21N=103g102cms2=105[F]=MLT^{-2}\Rightarrow 1N=10^3g\cdot10^2cm\cdot s^{-2}=10^5 dyne.

Recall Feynman: explain to a 12-year-old

Imagine every measurement wears a colored shirt: red for length, blue for time, green for weight. You're only allowed to add things wearing the same shirt — two red lengths give a red length, fine; but a red length plus a blue time is nonsense. When grown-ups write a physics equation, you can check it by looking at the shirts on both sides: if they match, the equation isn't obviously broken; if they clash, it's definitely wrong. The cool bonus: if you know what shirts the ingredients wear, you can often guess the recipe — like guessing a swing's wobble time grows with its length and shrinks with stronger gravity — just by making the shirts match up.

Connections

Concept Map

combine into

contrast with

built from definition

examples

governs

requires

because

forces

USE 1

USE 2

limitation

Base quantities M L T

Dimension of Q

Unit is chosen size

Derived quantities

velocity force energy

Principle of homogeneity

Added terms same dimension

Cannot add unlike kinds

Arguments of sin ln exp dimensionless

Check equations

Derive relations

Blind to pure numbers

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, har physical quantity ka ek "type" hota hai — koi length hai, koi time, koi mass. Inko hum dimensions kehte hain: [L][L], [T][T], [M][M]. Asli rule bahut simple hai — sirf same type ki cheezein add ho sakti hain. 5 metre aur 3 second ko jod nahi sakte, kyunki dono alag-alag kind ke hain. Isi rule ko principle of homogeneity bolte hain: equation ke dono side, aur jo bhi terms plus/minus se jude hain, sabki dimension same honi chahiye.

Pehla use: equation check karna. Jaise v2=u2+2asv^2 = u^2 + 2as — teeno terms ka dimension L2T2L^2T^{-2} nikalta hai, toh equation theek hai. Lekin agar koi term mismatch kare (jaise s=ut+12ats=ut+\frac12 at mein atat ka dimension velocity ban jata hai), toh equation pakka galat hai. Yaad rakho: fail hona matlab definitely wrong, par pass hona matlab "shayad sahi" — kyunki dimensional analysis ko pure numbers (jaise 12\frac12, 2π2\pi) dikhte hi nahi.

Doosra use, jo exam mein points dilata hai: relation derive karna. Maan lo pendulum ka period TT depend karta hai \ell, mm, gg par. Likho T=kambgcT = k\,\ell^a m^b g^c, dono side ki M,L,TM, L, T ki powers match karo, aur tumhe a=12a=\frac12, b=0b=0, c=12c=-\frac12 mil jaata hai — yaani T/gT \propto \sqrt{\ell/g}, aur mass ka koi role nahi! Constant 2π2\pi yeh method nahi dega, woh experiment se aata hai.

Bas limitation samajh lo: numeric constants, plus/minus signs, aur multi-term formulas yeh method nahi de sakta. Toh ise ek fast "sanity check" aur "first guess" tool ki tarah use karo — galti pakadne mein aur quick derivation mein yeh superpower hai.

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