4.9.10 · Maths › Probability Theory & Statistics
Jab ek saath do random quantities ho — jaise kisi insaan ki height X aur weight Y — tab aap sirf P ( X = x ) aur P ( Y = y ) alag-alag nahi chahte. Aap dekhna chahte ho ki wo saath-saath kaise chalte hain . Ek joint distribution ek akela object hai jo X aur Y ke baare mein saari probabilistic information ek saath store karta hai.
Joint = dono variables ke upar poori table/surface.
Marginal = ek variable ko hata do (sum/integrate karke) taaki akele ek variable wapas mile.
Conditional = ek variable ko kisi value par "freeze" karo aur us slice ko apni valid distribution mein re-normalize karo.
Definition Joint PMF (discrete)
Discrete random variables X , Y ke liye, joint probability mass function hai
p X , Y ( x , y ) = P ( X = x and Y = y ) .
Isko satisfy karna chahiye ==p X , Y ( x , y ) ≥ 0 aur ∑ x ∑ y p X , Y ( x , y ) = 1 ==.
Definition Joint PDF (continuous)
Continuous X , Y ke liye, joint probability density function f X , Y ( x , y ) satisfy karta hai
P ( ( X , Y ) ∈ A ) = ∬ A f X , Y ( x , y ) d x d y ,
jahan ==f X , Y ≥ 0 aur ∬ R 2 f X , Y d x d y = 1 ==.
Density kyun, probability kyun nahi? Continuous case mein kisi bhi single point ke liye P ( X = x , Y = y ) = 0 hota hai (ek point ka area zero hota hai). Toh hum probability per unit area describe karte hain; real probability tabhi milti hai jab kisi region A par integrate karo.
Intuition Sum/integrate kyun kaam karta hai
P ( X = x ) ka matlab hai "X = x , aur Y kuch bhi ho sakta hai". "Y kuch bhi ho sakta hai" = saare disjoint events { Y = y } ka union. Disjoint events ke union ki probability = sum. Yahi literally law of total probability hai.
"Marginal" naam isliye aaya kyunki joint PMF ko ek table ki tarah likhte hain aur row/column sums ko margins mein likhte hain .
Intuition "Conditional" ka asli matlab
Jab mujhe pata chal jaaye Y = y hai, toh mujhe sirf joint ka woh slice dekhna chahiye jahan Y = y hai. Lekin woh slice sum/integrate karke 1 nahi deta — woh p Y ( y ) (ya f Y ( y ) ) deta hai. Us slice ko ek legitimate distribution banane ke liye, uske total se divide karo taaki woh phir se 1 par integrate kare.
Worked example Discrete joint table
Coin se related do variables ka joint PMF:
p X , Y
Y = 0
Y = 1
row sum p X
X = 0
0.1
0.2
0.3
X = 1
0.3
0.4
0.7
col sum p Y
0.4
0.6
1.0
(a) X ka Marginal: p X ( 0 ) = 0.1 + 0.2 = 0.3 . Kyun? Row sum karo — Y ko sum out karo.
(b) Conditional P ( X = 1 ∣ Y = 0 ) : p Y ( 0 ) p X , Y ( 1 , 0 ) = 0.4 0.3 = 0.75 . Kyun? Sirf Y = 0 column (0.1 , 0.3 ) dekho aur uske total 0.4 se re-normalize karo.
(c) Independent hain? Check karo p X , Y ( 0 , 0 ) = 0.1 vs p X ( 0 ) p Y ( 0 ) = 0.3 × 0.4 = 0.12 . Barabar nahi ⇒ dependent .
Worked example Continuous joint density
Maano f X , Y ( x , y ) = c x triangle 0 < y < x < 1 par (aur baaki jagah 0 ). c nikalo, marginals nikalo, aur f X ∣ Y nikalo.
Step 1 — c nikalo. Kyun? Total probability = 1.
∫ 0 1 ∫ 0 x c x d y d x = ∫ 0 1 c x ⋅ x d x = c ∫ 0 1 x 2 d x = 3 c = 1 ⇒ c = 3.
Step 2 — X ka marginal. y ko integrate out karo, jahan y ka range 0 se x tak hai:
f X ( x ) = ∫ 0 x 3 x d y = 3 x ⋅ x = 3 x 2 , 0 < x < 1. Limits kyun? Is triangle mein y , 0 se x tak jaata hai.
Step 3 — Y ka marginal. Ab x ka range y se 1 tak hai:
f Y ( y ) = ∫ y 1 3 x d x = 2 3 ( 1 − y 2 ) , 0 < y < 1.
Step 4 — conditional f X ∣ Y ( x ∣ y ) :
f X ∣ Y ( x ∣ y ) = 2 3 ( 1 − y 2 ) 3 x = 1 − y 2 2 x , y < x < 1.
Yeh step kyun? Joint ko conditioning variable ke marginal se divide karo; support shift hokar x ∈ ( y , 1 ) ho jaata hai.
Common mistake "Marginal = sirf doosre variable ka column delete karo."
Kyun sahi lagta hai: marginal word sunne mein "ignore Y " jaisa lagta hai. Kyun galat hai: Y ko ignore karne ka matlab hai uski saari values par average karna, yani summing/integrating , koi ek choose nahi karna. Fix: p X ( x ) = ∑ y p X , Y ( x , y ) — collapse karo, drop mat karo.
Common mistake "Conditional density bas
Y = y par joint hai."
Kyun sahi lagta hai: aap joint ko slice kar rahe ho. Kyun galat hai: woh slice 1 par integrate nahi karta. Fix: re-normalize karne ke liye marginal f Y ( y ) se divide karo.
Common mistake "Agar marginals barabar hain toh wo independent hain."
Kyun sahi lagta hai: independence aur equal-marginals dono "koi special relationship nahi" jaisa lagte hain. Kyun galat hai: independence ek statement hai ki joint factor hota hai, f X , Y = f X f Y — akele marginals yeh kabhi nahi bata sakte. Fix: hamesha joint par factorization test karo.
Common mistake Support bhool jaana (integration ke limits).
Kyun sahi lagta hai: integrand ka algebra complete lagta hai. Kyun galat hai: region (jaise triangle y < x ) bounds change karta hai; constant bounds se galat marginals aate hain. Fix: pehle support sketch karo.
Recall Feynman: 12-saal ke bachche ko samjhao
Socho ek badi bucket ki grid hai. Har bucket mein kuch marbles hain ek pair (height, weight) ke liye. Joint yeh hai ki har bucket mein kitne marbles hain. Agar aap har row ke saare marbles ek saath push karo aur totals side mein likho, toh woh side-total height ka marginal hai. Ab maano main bolta hoon "weight exactly 50 kg hai" — aap ek column ko chhod kar baaki saari buckets phenk dete ho. Lekin bache hue marbles phir bhi ek poori bag ke barabar add up hone chahiye, toh aap unhe scale up karte ho. Yahi scaled-up column conditional hai.
Mnemonic Teen M's→C path yaad rakho
"Joint hai JAR; Marginals hain MARGINS (sums); Conditionals ek slice CUT karte hain aur re-NORMALIZE karte hain."
Formula shortcut: Conditional = Joint ÷ Marginal ("slice uske weight se divide").
Ek valid joint PMF ke liye kaun si do conditions honi chahiye? p X , Y ( x , y ) ≥ 0 for all x , y , aur ∑ x ∑ y p X , Y ( x , y ) = 1 .
Joint se marginal PMF p X kaise nikalte hain? Doosre variable ko sum out karo: p X ( x ) = ∑ y p X , Y ( x , y ) .
Joint PDF se marginal PDF f X kaise nikalte hain? Doosre variable ko integrate out karo: f X ( x ) = ∫ − ∞ ∞ f X , Y ( x , y ) d y .
Conditional PDF f X ∣ Y ( x ∣ y ) define karo. f X ∣ Y ( x ∣ y ) = f X , Y ( x , y ) / f Y ( y ) for f Y ( y ) > 0 .
Conditional paane ke liye marginal se kyun divide karte hain? Raw slice marginal tak integrate/sum hoti hai, 1 tak nahi; divide karna use valid distribution mein re-normalize karta hai.
X , Y ke independent hone ki condition batao.f X , Y ( x , y ) = f X ( x ) f Y ( y ) for all x , y (equivalently f X ∣ Y = f X ).
Continuous variables ke liye P ( X = x , Y = y ) = 0 kyun hota hai? Ek single point ka area zero hota hai; sirf positive area wale regions probability carry karte hain density ke under.
Joint PDFs ka chain rule batao. f X , Y ( x , y ) = f X ∣ Y ( x ∣ y ) f Y ( y ) = f Y ∣ X ( y ∣ x ) f X ( x ) .
f X , Y = 3 x ke liye 0 < y < x < 1 par, f X ( x ) kya hai?f X ( x ) = ∫ 0 x 3 x d y = 3 x 2 , 0 < x < 1 .
Equal marginals — kya yeh independence imply karta hai? Nahi; independence joint ke factoring ke baare mein hai, jo akele marginals se determine nahi ho sakti.
Conditional Probability Def
Probability over region A