This page assumes you have seen nothing. We name every mark on the page, draw the picture it stands for, and say why the topic can't live without it. Read top to bottom; each item leans on the one above.
Picture. Look at figure s01. Slide a pointer along the horizontal axis (that's x). The height of the curve above that spot is the value y. The whole curve is the function.
Why the topic needs it. An "ordinary differential equation" (ODE) is a puzzle whose answer is a whole function y(x), not a single number. So before anything else we must be comfortable that the unknown is a curve.
Picture. Look at figure s02. At any point the little tangent line touches the curve; its tilt is y′. Now watch that tilt as you slide right: on a curve that bends upward (a valley shape) the tangent starts tilting down, flattens, then tilts up — the tangent line rotates counter-clockwise. The speed of that rotation is y′′. A bigger y′′ means the tangent swings faster, i.e. the curve bends more sharply.
Why the topic needs it. The whole equation y′′+py′+qy=g is built entirely from y,y′,y′′. Without the prime we cannot even write the problem.
"Second-order" because the highest prime is y′′ (two primes).
"Linear" because y,y′,y′′ appear only to the first power — no y2, no siny.
Why the topic needs it. This is the very equation variation of parameters solves. The left side is the machine; the right side is what we want it to print.
Picture. See figure s03. Left panel: a pendulum swinging freely — homogeneous. Right panel: a hand periodically nudging it — that nudge is g(x), non-homogeneous.
Related, faster-but-narrower tool: Method of Undetermined Coefficients handles only special pushes.
Why "two"? Second-order ⇒ two independent choices to make (like choosing a starting position and a starting speed). Getting these is the job of Second-order linear homogeneous ODE, often via Reduction of Order when you already know one.
Why the topic needs it. The whole answer is built out ofy1,y2. They are the raw lumber.
Plain meaning.W is a "fairness scale." If W=0, y1 and y2 are truly different building blocks; if W=0, one is secretly a copy of the other and the method jams (you'd divide by zero). Full story: Wronskian.
Why the topic needs it.W sits in the denominator of the final formula — it is literally the divisor when we solve for the strengths.
Why the topic needs it. Cramer's rule gives us the ratesu1′,u2′. To get the actual strengths u1,u2 we must undo the prime — that is exactly integration:
u1=∫u1′dx,u2=∫u2′dx.
The slope (steepness) at each point; y′′ is how fast that slope changes (how sharply the curve bends).
In y′′+py′+qy=g, which piece is "the push"?
g(x), the forcing on the right-hand side.
What makes an equation homogeneous?
Its right-hand side is 0 (no external push).
Why do we need exactly two solutions y1,y2?
A second-order equation has two independent free choices, so its free motion is a blend of two building blocks.
What is the single swap that defines variation of parameters?
Replace the constant strengths c1,c2 with varying functions u1(x),u2(x).
Compute the 2×2 determinant acbd.
ad−bc.
How do you tell determinant bars from absolute-value bars?
Absolute value wraps a single number (∣−3∣=3, never negative); a determinant wraps a grid of four numbers (ad−bc, may be negative).
Write the Wronskian of y1,y2.
W=y1y2′−y2y1′.
What does W=0 warn you about, and why does one check suffice?
The two solutions are not independent and the method breaks down; Abel's identity W=W(x0)e−∫pdx shows W is either zero everywhere or nowhere on the interval.
Cramer's rule gives u1′ and u2′ as?
u1′=−y2g/W and u2′=+y1g/W.
Why integrate after Cramer's rule, and why drop the +C?
Integrating undoes the prime to recover u1,u2; the constants would only add C1y1+C2y2, a homogeneous piece already counted in c1y1+c2y2.
Write the final formula for yp.
yp=−y1∫(y2g/W)dx+y2∫(y1g/W)dx.
What must you check before reading off g?
Put the ODE in standard form (leading coefficient 1) by dividing through.