Intuition The one core idea
A collection of arrows is linearly independent when each arrow points in a genuinely new direction that none of the others could reach by stretching and adding. Everything in this topic — vectors, scalars, the equation A c = 0 , rank, determinant — is just machinery to answer the single yes/no question: "is any arrow a leftover copy of the others?"
This page builds every piece of notation the parent note uses, from absolute zero. Read it top to bottom: each item is used by the next.
A vector is an arrow with a length and a direction , drawn from a starting point (the origin). We also write it as a list of numbers — its coordinates — telling us how far to go along each axis.
The two views are the same object. The list ( 3 , 2 ) means "go 3 steps East (the x -axis) and 2 steps North (the y -axis)", and the arrow is what you get when you actually walk there.
list of numbers ?
Drawing arrows is fine for a picture, but to compute we need numbers. The list is the arrow written in a language a calculator understands. In this topic we stack these lists side by side to build a table (a matrix), so the number-list view is essential.
We write vectors in bold : v 1 , v 2 , … . The little number below is just a name tag (vector number 1, number 2), not a power or a coordinate.
v 2 means v squared."
Why it feels right: subscripts look like exponents.
The fix: v 2 is a label — the second vector in our list. It has nothing to do with multiplying v by itself.
A scalar is an ordinary single number (like 2 , − 2 1 , 0 ). "Scalar" comes from scale : multiplying a vector by a scalar stretches or shrinks it, and a negative scalar flips it to point the opposite way.
The parent note uses letters c 1 , c 2 , … , c n for scalars. Each c i is the amount of vector v i we take.
Intuition Why we need scalars for this topic
"Can vector A be built from the others?" means "can I scale the others and add them up to land on A?" Scaling is half the recipe. The scalars c i are the dials we are allowed to turn.
Watch the special values:
c = 1 : leaves the vector unchanged.
c = 0 : crushes it to a point — you take none of it.
c = − 1 : flips it exactly backward, same length.
c = 2 : doubles the length, same direction.
Definition Vector addition (tip-to-tail)
To add two vectors, place the tail of the second at the tip of the first. The arrow from the very start to the very end is the sum . In coordinates you just add matching entries: ( a , b ) + ( c , d ) = ( a + c , b + d ) .
Now combine scaling and adding:
Definition Linear combination
A linear combination of v 1 , … , v n is any vector you can build by scaling each one and adding the results:
c 1 v 1 + c 2 v 2 + ⋯ + c n v n .
The word linear means we only ever scale and add — no bending, no multiplying vectors together.
Intuition Why this is the heart of everything
The entire definition of independence is a sentence about linear combinations : "the only linear combination that lands on the origin is the boring one where every dial is zero." If you understand "scale each arrow, add them up," you already understand the machinery. This connects to Span and spanning sets — the span is the set of all linear combinations you can reach.
The zero vector 0 is the arrow of length zero — it starts and ends at the origin, pointing nowhere. Its coordinate list is all zeros: ( 0 , 0 ) or ( 0 , 0 , 0 ) .
0 is the target of the whole test
The independence question asks: "which combinations bring me back to where I started?" Landing back on the origin means the arrows perfectly cancel. If the only way to cancel is to take none of anything (c 1 = ⋯ = c n = 0 ), no arrow is a leftover. Any other way to cancel exposes a redundant arrow.
0 (number) when you mean 0 (vector).
Why it feels right: they look almost identical.
The fix: 0 (bold) is an arrow of zero length — a point. Plain 0 is a scalar . In c 1 v 1 + ⋯ = 0 the right side must be the vector.
R n
R n is the collection of all number-lists of length n . R 2 is the flat plane (lists of 2 numbers); R 3 is 3D space (lists of 3 ). The little n counts how many coordinates — the dimension , the number of independent directions available.
Intuition Why dimension matters for the topic
There are only n genuinely different directions in R n . So you can never have more than n independent arrows there. The parent's rule "4 vectors in R 3 are always dependent" is exactly this: you asked for 4 new directions in a room that only has 3. See Basis and dimension for the full story.
A matrix is a rectangular grid of numbers. In this topic we build one by standing our vectors up as columns , side by side:
A = ∣ v 1 ∣ ∣ v 2 ∣ ⋯ ∣ v n ∣ .
The vertical bars ∣ are just a picture reminder that each column is a whole vector.
c
c is the list of dials stacked into one column: c = ( c 1 , c 2 , … , c n ) . It stores how much of each column we take.
Intuition Why rewrite it as
A c = 0 ?
The definition "c 1 v 1 + ⋯ + c n v n = 0 " is a system of equations in disguise. Packing it as A c = 0 lets us use one powerful machine — row reduction — to solve it, instead of juggling equations by hand. This is a homogeneous system (the right side is 0 ), and its solutions form the null space .
Definition Trivial and nontrivial
c = 0 (every dial at zero) always solves A c = 0 — take none of anything and you land at the origin. This boring answer is the trivial solution .
A nontrivial solution is any solution where at least one c i = 0 .
Situation
What it means
Verdict
Only c = 0 works
No arrow is redundant
Independent
Some c = 0 works
An arrow is a leftover combo
Dependent
Mnemonic Zero only the boring way
Independent = you can only reach 0 the boring way (all dials off). Any exciting way (a dial left on) means dependent.
After tidying a matrix by row reduction (adding/subtracting rows to make a staircase of leading entries called pivots ), the rank is the number of pivots — the count of genuinely independent columns. See Rank of a matrix .
A column without a pivot corresponds to a free variable — a dial you may set to anything , which instantly produces a nontrivial solution.
Intuition Why counting pivots answers the whole question
Pivot in every column (rank = n ): no free dials, so the only solution is trivial → independent .
A pivot missing (rank < n ): a free dial exists, so a nontrivial solution exists → dependent .
Counting pivots is the mechanical, guaranteed test — no eyeballing required.
The determinant det A is a single number, defined only when A is square (n vectors in R n ), measuring the signed area/volume the columns enclose. See Determinant .
Intuition Why area answers independence
If two arrows in R 2 point the same way (one is a scalar multiple of the other), they enclose zero area — flat, squashed. So:
det A = 0 → squashed → columns dependent.
det A = 0 → genuine area/volume → columns independent → A is invertible .
Common mistake Reaching for
det when A isn't square.
The fix: det doesn't even exist for a 3 × 4 matrix. Non-square? Use rank / row reduction from Section 8.
Vector = arrow = number list
Scalar = stretch or flip number
Vector addition tip to tail
Linear combination scale and add
Vectors as columns matrix A
A times c equals combination
Homogeneous system Ac = 0
Trivial vs nontrivial solution
Test yourself — reveal only after answering aloud.
I can draw the vector ( 3 , 2 ) as an arrow and say what each number means. Go 3 right along x , 2 up along y ; the arrow points from origin to ( 3 , 2 ) .
I know what multiplying a vector by − 2 does to its arrow. Doubles its length and flips it to point the opposite way.
I can write out the linear combination c 1 v 1 + c 2 v 2 in words. Take c 1 copies of v 1 , add c 2 copies of v 2 , tip to tail.
I know the difference between 0 and 0 . 0 is a number (scalar); 0 is the zero-length arrow sitting at the origin.
I can explain why A c equals a linear combination of A 's columns. Each entry c i scales column v i ; summing the scaled columns gives A c .
I know what "trivial solution" means for A c = 0 . The all-zero dial setting c = 0 , which always works.
I know when I'm allowed to use the determinant. Only for square matrices — n vectors in R n .
I can state why a free variable forces dependence. A free dial can be set nonzero, giving a nontrivial solution to A c = 0 .
Span and spanning sets — the set of all linear combinations from Section 3.
Basis and dimension — dimension of R n caps how many independent arrows fit.
Rank of a matrix — pivots counted in Section 8.
Determinant — the area/volume test of Section 9.
Homogeneous systems and null space — the equation A c = 0 .
Invertible matrix theorem — independent columns ⇔ invertible ⇔ det = 0 .
Linear independence — formal definition, testing — the parent this page equips you for.