Before you can even read the theorem rank(T)+nullity(T)=dimV, you need to know what each of those words and squiggles means. This page builds them in order, from the plainest idea up to the full statement. Nothing here is assumed — if the parent note used it, we define it here.
Why do we start here? Because everything — spaces, maps, kernels — is built from arrows. If you cannot picture an arrow, no later symbol will feel real.
The two numbers are the vector's components. Adding two vectors means placing them tip-to-tail; scaling a vector by a number c stretches it (or flips it, if c<0).
The letters V and W in the theorem are just names for two such rooms — the input room and the output room.
Vectors don't have to be arrows! Polynomials like 2x2+x−5 also add and scale like arrows, so the set of all polynomials of degree ≤3 is a vector space too (the parent's Example 3). That is why the theorem works for "abstract" spaces. See Dimension of a Vector Space for the full story.
The symbol n in the proof is just dimV given a short name. "V finite-dimensional" means n is a finite number — you can list a basis and stop.
Recall Why does the proof need finite dimension?
Because the counting argument (n−k)+k=n needs a finiten to add. ::: With infinitely many directions you cannot subtract counts safely — the basis-extension step and the arithmetic both break.
The move "extend a basis of a subspace to a basis of the whole space" is the Basis Extension Theorem, the engine of Step 1.
The picture: T takes the grid of V and stretches, rotates, or flattens it into W — but keeps grid lines straight and evenly spaced (that's what linearity looks like). Some maps flatten a whole direction onto zero — that flattening is the kernel, next.
The image is a subspace of the output room W. Crucial subtlety the parent hammers: rank + nullity sums to dimV (the domain), notdimW — because we are counting how the input directions get sorted.
A matrix like A=(122436)is a linear map: feeding it a column vector x and computing Ax takes a vector from R3 to R2. Solving Ax=0 finds the kernel; the number of free variables in that solution is the nullity — that link is Solving Linear Systems — free variables count. When a map loses no directions (kernel is just {0}) it is an isomorphism, see Invertible Linear Maps and Isomorphisms.
Read top to bottom: arrows are atoms, arrows build spaces and independence, independence builds bases, bases give dimension, and dimension of kernel + image is exactly what the theorem measures.