∣f(x)−L∣<ε : output target tube mein hai, jiska half-width ε hai L ke around.
0<∣x−a∣<δ : input a ki ek punctured neighborhood mein hai (hum x=a ko ignore karte hain — limit neighbourhood ke baare mein hai, point ke baare mein nahi).
Quantifiers ka order sacred hai: ε pehle aata hai (challenge), phir δ depend kar sakta hai ε pe.
Q:limx→4x=2 ke liye, ek kaam karne wala δ(ε) predict karo.
Verify:∣x−2∣=x+2∣x−4∣≤2∣x−4∣ (kyunki x≥0). Toh ∣x−4∣<2ε kaam karta hai: δ=2ε. Divide kyun?x−2 ko rationalise karo x+2x+2 se multiply karke taaki ∣x−4∣ expose ho.
Kaun sa quantifier pehle aata hai, ε ya δ, aur kyun
ε pehle; δ depend kar sakta hai ε pe (challenge phir response)
Limit mein "0<∣x−a∣" (punctured) kyun hota hai
Limit x=a ko ignore karti hai; yeh a ke paas ke behaviour ke baare mein hai, a par value ke baare mein nahi
δ find karne ki general recipe
∣f(x)−L∣=∣x−a∣⋅M factor karo, ∣x−a∣<1 se cap karo, phir δ=min(1,ε/M)
limx→3x2=9 ke liye δ
δ=min(1,ε/7)
Difference: continuity vs uniform continuity
Continuity mein δ point pe depend kar sakta hai; uniform continuity ko sab points ke liye ek δ chahiye
Teen metric axioms
d(x,y)=0⟺x=y; symmetry; triangle inequality
Discrete metric
d(x,y)=0 agar x=y, warna 1
Open ball B(a,r) ki definition
{x:d(x,a)<r}
Metric space mein limit
∀ε∃N:n≥N⇒d(xn,L)<ε
Euclidean triangle inequality prove karne wali inequality
Cauchy–Schwarz, x⋅y≤∥x∥∥y∥
Recall Feynman: ek 12-saal ke bacche ko explain karo
Ek dartboard imagine karo. Ek dost kehta hai "main bet lagata hoon ki tum bullseye ke 1 cm ke andar nahi maar sakte." Tum kehte ho "theek hai, bas mujhe board ke paas khadha hone do." Agar har distance ke liye jo woh pick kare — 1 cm, 1 mm, yahan tak ki ek baal ki chaurai — tum hamesha ek aisi jagah dhundh sako jahan khade hone se guarantee ho ki itne paas maaro, toh hum kehte hain tumhare darts sach mein bullseye approach karte hain. Yahi limit hai. ε hai kitna close woh demand karte hain; δ hai tum kitna paas khade hote ho. "Metric" bas koi bhi fair ruler hai do cheezein kitni door hain yeh measure karne ke liye, jab tak ruler honest ho: zero distance sirf identical cheezein ke liye, dono taraf same, aur koi shortcut seedha jaane se behtar nahi (triangle inequality).