4.1.3 · D5Calculus I — Limits & Derivatives
Question bank — One-sided limits — left-hand, right-hand
Pictures to keep in mind
The two figures below are the mental images every item on this page leans on: a number-line "approach from both sides" picture, and the – band picture that shows why one inequality secretly carries two sides.


Look at the second figure: the horizontal band of half-width around is what we want to land in; the vertical strip of half-width around is where is allowed to roam. That strip straddles — points to its left and to its right are both inside . That is the geometric reason a single inequality demands agreement from both sides.
True or false — justify
For a claimed one-sided limit : "" means we approach using only .
True or false: means takes negative values.
False. It means approaches through numbers smaller than (like ), which are all positive; the minus is a direction, not a sign.
True or false: If , the two-sided limit exists and equals that common value.
True. Equal one-sided limits are exactly the condition the boxed rule requires; the shared value is the two-sided limit.
True or false: If both one-sided limits exist, the two-sided limit must exist.
False. They must also be equal. For at both sides exist ( and ) but disagree, so no two-sided limit.
True or false: The value is needed to compute .
False. A limit only reads the neighbourhood; the point itself is never plugged in and can even be undefined.
True or false: is an existing (real-valued) limit.
False. is not a real number; we say the limit diverges to — it names a behaviour, not an existing limit.
True or false: If and , then .
True in the sense that both sides "agree" on diverging to (like at ); we write the two-sided divergence as , though it is still a non-existent finite limit.
True or false: A continuous function can have unequal one-sided limits at a point in its domain.
False. Continuity at demands both one-sided limits equal ; unequal sides are exactly what breaks continuity (a jump).
True or false: If is defined only for , then can still exist two-sided.
False. With no domain on the left the left-hand limit is undefined, so the two-sided limit cannot exist; only the right-hand limit is meaningful.
True or false: .
False. Just below , values like floor to , so the left-hand limit is , not ; the floor jumps at the integer.
Spot the error
Each line states a flawed piece of reasoning. Name what went wrong.
", and is defined there, so ." (piecewise from the parent note)
Error: the limit ignores . The one-sided rules and both approach , so the limit is ; the point value is irrelevant.
" at : since always, on both sides, so the limit is ."
Error: only for . For , , giving , so the sides disagree and no two-sided limit exists.
"Both sides of at blow up, so the two-sided limit is ."
Error: the sides go to opposite infinities ( from the right, from the left), so they disagree; the limit does not exist and cannot be labelled a single .
" at : left-hand limit is which is imaginary, so the limit is imaginary."
Error: over the reals has no left domain at all, so the left-hand limit is undefined (not imaginary); only exists.
" picks the smaller root/branch of ."
Error: the minus is purely a direction of approach (); it says nothing about which branch or value of to choose.
"Since , the floor is right-continuous and hence continuous at ."
Error: right-continuity alone is not continuity. The left-hand limit is , so is discontinuous at despite matching from the right.
Why questions
Why must a two-sided limit require the sides not just to exist but to be equal?
A limit is a promise of a single destination reachable from every approach; if left heads to and right to , no single can honour the promise, so it fails.
Why does the – condition automatically encode "both sides"?
Picture the -strip around (second figure): it extends to the left of and to the right, so covers and ; the two-sided limit is the logical AND of these two halves.
Why is deliberately excluded (via , not )?
The strict punches a hole exactly at , so the limit describes where is heading near and stays meaningful even when is undefined or an outlier.
Why can a limit be written "" yet still be called non-existent?
The symbol faithfully records that outputs grow past every bound, but since is not a real number, there is no real value to equal — so no finite limit exists; "diverges to " is the honest phrasing.
Why does the floor function fail to have a two-sided limit at every integer but succeed everywhere else?
At an integer the floor value jumps by , so left and right limits differ; strictly between integers is constant, so both sides agree and the limit exists.
Why does approaching a vertical asymptote from the left of give but the right give ?
Tiny negative denominators make hugely negative, tiny positive ones make it hugely positive; the sign of the shrinking denominator flips the output's sign.
Edge cases
at : which one-sided limit is even meaningful, and what is the two-sided verdict?
Only the right-hand limit is meaningful, ; the left has no real domain, so the two-sided limit does not exist.
A function defined only on : what is the status of and ?
Only and can exist (approach from inside the domain); the two-sided limits at the endpoints do not exist since one side has no points.
at : do the sides agree, and does the two-sided limit "exist"?
Both sides diverge to , so they agree in behaviour and we write ; it is still a non-existent finite limit but a genuine two-sided divergence.
A removable discontinuity where both sides equal but : does exist?
Yes, the two-sided limit is because both sides agree; the mismatched only means is discontinuous, not that the limit fails.
as : does the right-hand limit exist?
No — near the input races through infinitely many cycles, so oscillates between and without settling; no single approach value, hence no one-sided limit.
An isolated point of the domain (say defined at but nowhere in a punctured neighbourhood): can any one-sided limit exist?
No. With no domain points approaching from either side, neither one-sided nor two-sided limit is defined; only as a plain value exists.
Both one-sided limits equal and as well — is discontinuous, and is there any jump here?
No to both. All three agree, so is continuous at ; there is no jump — a jump discontinuity requires the two one-sided limits to differ, which does not happen here.
Connections
- One-sided Limits — Left-hand & Right-hand
- Limit of a function — intuitive & ε-δ definition
- Continuity at a point
- Jump, removable & infinite discontinuities
- Vertical asymptotes
- Greatest integer / floor function
- Differentiability — left & right derivatives