Kuch functions mein ek "hole" ya "0/0 trap" hoti hai kisi point par. Hum seedha x=a plug nahi kar sakte kyunki ya toh zero se divide ho jaayega ya kuch undefined aa jaayega. Lekin function us point ke aas-paas bilkul theek behave kar sakta hai. Limit hume us approached value ke baare mein baat karne deta hai bina us toote hue spot ko touch kiye.
Ek table banao jahan x dono sides se a ki taraf creep kare aur outputs dekho.
x→1limx−1x2−1 ke liye:
x (from left)
f(x)
x (from right)
f(x)
0.9
1.9
1.1
2.1
0.99
1.99
1.01
2.01
0.999
1.999
1.001
2.001
0.9999
1.9999
1.0001
2.0001
Pehle forecast karo: right column padhne se pehle predict karo ki kahan ja raha hai. Dono sides 2 ki taraf squeeze ho rahi hain.
limx→1x−1x2−1=2Yeh kyun kaam karta hai? Jitna x1 ke paas aata hai, f(x) utna tightly 2 ke around clamp hota jaata hai — exactly definition ke according.
fx=a par kar sakta hai jabki limit phir bhi L equal kare?
(1) f(a)=L (continuous), (2) f(a) undefined (hole), (3) f(a)=L (stray dot). Limit sirf approach ki parwah karta hai.
Recall
limx→af(x) kab exist NAHI karta?
Jab left-hand aur right-hand limits alag hon (jump), ya function blow up kare / wildly oscillate kare toh koi single value approach nahi hoti.
Recall Hum
x−1(x−1)(x+1) mein limit ke andar (x−1) cancel kyun kar sakte hain?
Kyunki x→1 ka matlab hai x=1, isliye x−1=0 hai aur usse divide karna valid hai.
Recall (Feynman, 12 saal ke bachche ko explain karo)
Socho tum ek wall ki taraf chal rahe ho lekin ek baal ki chadaai pe ruk jaate ho — aur aur paas ruk sakte ho, aur paas, hamesha ke liye. Limit puchta hai: wall par exactly kaun sa spot hai jis par tum aim kar rahe the? Chahe wahan ek choti missing tile (hole) bhi ho jahan tum touch karte, tum phir bhi exactly dekh sakte ho ki tum kis spot ki taraf ja rahe the. Woh spot limit hai. Koi fark nahi padta us ek tile par kya painted hai — sirf yeh matter karta hai ki tum kahan ja rahe the.