Ek point z=a+bi ko Argand plane par plot karo. Origin O se us point tak arrow draw karo. Uski length r rakho aur positive real axis se jo angle banta hai usse θ rakho.
Step 1 — right triangle banao. Point se real axis par ek perpendicular drop karo. Horizontal leg =a, vertical leg =b, hypotenuse =r.
Ye step kyun? Trigonometry sirf right triangles par kaam karti hai, isliye hum ek manually bana lete hain.
Step 2 — trig ratios padho.cosθ=hypadjacent=ra,sinθ=hypopposite=rbYe step kyun? Ye literally angle θ ke liye cos aur sin ki definitions hain.
Step 3 — a aur b ke liye solve karo.a=rcosθ,b=rsinθYe step kyun? Hum a,b ko r,θ se replace karna chahte hain, isliye unhe subject banao.
Step 4 — z=a+bi mein substitute karo.z=rcosθ+i(rsinθ)=r(cosθ+isinθ)
Ho gaya — yahi polar form hai, purely Pythagoras + trig se derive kiya. ∎
Calculator ka tan−1(b/a) sirf (−90°,90°) mein angles return karta hai. Lekin arrows 360° mein kahin bhi point kar sakte hain. Isliye tumhe dekhna hoga ki (a,b) kis quadrant mein hai aur accordingly adjust karna hoga.
| Quadrant | Signs (a,b) | Reference angle α=tan−1ab se argument |
|---|---|---|
| I | (+,+) | θ=α |
| II | (−,+) | θ=π−α |
| III | (−,−) | θ=−(π−α) ya π+α |
| IV | (+,−) | θ=−α |
Principal argument(−π,π] mein choose kiya jaata hai.
arg(−1) aur arg(−i) kya hai?
Forecast:−1 negative real axis par baitha hai; −i seedha neeche point karta hai.
Verify:arg(−1)=π (arrow left point karta hai). arg(−i)=−2π (principal value; neeche point karta hai). Dono ka modulus 1 hai. Toh −1=cisπ aur −i=cis(−2π).
Argument ke liye sirf tan−1(b/a) kyun use nahi kar sakte?
Ye quadrant ignore karta hai; tan ka period π hai, isliye 180° apart points same value dete hain. Tumhe (a,b) ke quadrant se adjust karna hoga.
1+i ko polar form mein convert karo.
2cis4π
2cis32π ko Cartesian mein convert karo.
−1+i3
Kya modulus r negative ho sakta hai?
Nahi, r≥0 hamesha; direction θ mein carry hota hai.
Polar form mein do complex numbers multiply karne ka rule?
Moduli multiply karo, arguments add karo.
−i ka argument (principal value)?
−2π
Quadrant II mein, reference angle α se θ kaise milta hai?
θ=π−α
z=a+bi kaunsa geometric object represent karta hai?
Argand (complex) plane mein ek point/arrow.
Recall Feynman: ek 12-saal ke bacche ko samjhao
Socho tum ek bade maidan ke beech mein khade ho. Kahin khazana gada hua hai. Apne dost ko batane ka ek tarika: "3 kadam East, phir 4 kadam North chalo" — ye 3+4i jaisa hai. Doosra tarika: "5 kadam chalo, us direction mein" — tum sahi angle par ghoomte ho aur chalte ho. Ye "5 kadam + ek direction" polar form hai. Kadam ki sankhya modulusr hai, aur jo direction tum face kar rahe ho wo angleθ hai. Sama khazana, do alag tarike se describe kiya. Polar form tab kaam aata hai jab arrows ko spin aur stretch karna ho — sirf angles add karo aur lengths multiply karo.