1.2.6 · Hardware › Circuit Analysis Fundamentals
Current divider tab hota hai jab ek akela current kisi junction pe pahunchta hai aur uske paas do ya zyada parallel paths hote hain flow karne ke liye. Current split ho jaata hai, lekin equally nahi — woh least resistance wali path prefer karta hai.
YEH kyun matter karta hai: real circuits mein branches baar baar aate hain. Current kaisa split hota hai yeh jaanne se tum resistors size kar sakte ho, LEDs protect kar sakte ho, aur poora network solve kiye bina meters padh sakte ho.
Definition Current divider
Ek aisa network jahan total current I T ek node mein enter karta hai aur parallel branches mein divide ho jaata hai. Kyunki parallel branches same voltage share karti hain, branch currents purely har branch ki resistance (ya conductance) se decide hoti hain.
Do facts saara kaam karte hain:
KCL (Kirchhoff's Current Law): current in = current out, toh I T = I 1 + I 2 .
Parallel branches ek hi voltage V share karti hain.
Do resistors R 1 aur R 2 parallel mein, I T se fed hain.
Step 1 — Same voltage.
Kyun? Dono resistors same do nodes ke beech connect hain, isliye unhe identical voltage V milta hai.
V = I 1 R 1 = I 2 R 2
Step 2 — Equivalent resistance pe Ohm's law se total current.
Kyun? Poora bundle ek resistor R ∥ ki tarah behave karta hai jo I T ko voltage V par carry karta hai.
V = I T R ∥ , R ∥ = R 1 + R 2 R 1 R 2
Step 3 — I 1 nikalo.
Kyun? I 1 = V / R 1 , aur hum V = I T R ∥ substitute karte hain:
I 1 = R 1 V = R 1 I T R ∥ = R 1 I T ⋅ R 1 + R 2 R 1 R 2
R 1 cancel ho jaata hai:
Sanity check: dono jodo.
I 1 + I 2 = I T R 1 + R 2 R 2 + R 1 = I T ✓
Intuition Conductance kyun cleaner hai
Resistance kehta hai "push karna kitna hard hai"; conductance G = 1/ R kehta hai "flow karna kitna easy hai." Current easy paths se pyaar karta hai, toh woh conductance ke direct proportion mein split hota hai — koi confusing swaps nahi.
Kyunki I k = V G k aur I T = V ∑ G j , divide karo:
Exactly do resistors ke liye yeh wapas boxed formula mein collapse ho jaata hai (try karo — Verify dekho).
Worked example 1 — Simple do-resistor split
I T = 12 mA , R 1 = 2 k Ω , R 2 = 4 k Ω .
I 1 = 12 ⋅ R 1 + R 2 R 2 = 12 ⋅ 6 4 = 8 mA
R 2 upar kyun? I 1 bada hai kyunki R 1 (2 k) easier path hai — zyaada tar current usi se guzarta hai.
I 2 = 12 ⋅ 6 2 = 4 mA . 8 + 4 = 12 ✓
Worked example 2 — Pehle forecast, phir verify
I T = 9 mA , R 1 = 1 k Ω , R 2 = 8 k Ω .
Forecast: R 1 8 guna easier hai, toh zyaada tar current wahi jaana chahiye.
I 1 = 9 ⋅ 9 8 = 8 mA , I 2 = 9 ⋅ 9 1 = 1 mA
Yeh step kyun? Ratio R 1 + R 2 R 2 = 9 8 literally hai "9 total mein se 8 parts." Forecast se match karta hai: low-resistance branch current hog kar leta hai. ✅
Worked example 3 — Teen branches (conductance form)
I T = 30 mA , R 1 = 10 Ω , R 2 = 20 Ω , R 3 = 20 Ω .
G 1 = 0.1 , G 2 = 0.05 , G 3 = 0.05 , ∑ G = 0.2 S.
I 1 = 30 ⋅ 0.2 0.1 = 15 mA
Kyun? R 1 ke paas total conductance ka aadha hai, toh woh aadha current leta hai.
I 2 = I 3 = 30 ⋅ 0.2 0.05 = 7.5 mA . 15 + 7.5 + 7.5 = 30 ✓
Common mistake "Current bade resistor se zyaada jaata hai —
I 1 ke liye R 1 upar rakho."
Kyun sahi lagta hai: voltage divider mein tum jis resistor ki parwah karte ho usse total ke upar rakhte ho, toh log wahi pattern copy karte hain. Aisa bhi lagta hai "bada resistor, bada share."
Fix: current iska ulta hai — woh bade resistors se bachta hai. I 1 ke liye doosra resistor R 2 upar rakho. Physically: I 1 = V / R 1 , toh bada R 1 chhota I 1 deta hai.
Common mistake "3+ resistors ke liye main phir
I 1 = I T R 2 / ( R 1 + R 2 ) use karunga."
Kyun sahi lagta hai: do-resistor formula yaadgar hai aur har jagah milta hai.
Fix: "doosra resistor swap karo" trick sirf do branches ke liye kaam karti hai. N ≥ 3 ke liye conductances use karo: I k = I T G k / ∑ G j .
Common mistake "Series mein resistors ek current divider banate hain."
Kyun sahi lagta hai: series aur parallel ek messy schematic par similar dikhte hain.
Fix: series current share karta hai (har jagah same current) aur voltage divide karta hai. Sirf parallel branches current divide karti hain.
Recall Feynman: 12-saal ke bacche ko samjhao
Socho paani ek fork pe pahunchta hai jahan do pipes hain. Agar ek pipe wide hai (low resistance) aur ek skinny hai (high resistance), toh zyaada paani wide pipe se bahega. Total paani same rehta hai, bas split ho jaata hai — aur wide, easy pipe bada hissa le jaati hai. Wire mein current exactly yahi karta hai: woh sabse zyaada easiest path se bahta hai.
"CROSS to find your current." I 1 ke liye, cross over karo aur R 2 upar use karo. Aur: "Current takes the easy road" — low-R branch = high current.
Parallel branches same voltage kyun share karti hain?
I 1 = I T R 2 / ( R 1 + R 2 ) mein R 2 (R 1 nahi) upar kyun hai?
3+ branches ke liye kaun sa form use karna padega, aur kyun?
Current divider ke liye branches kaisi honi chahiye — series ya parallel? Parallel (woh same voltage share karti hain).
Do-resistor current divider formula I 1 ke liye I 1 = I T R 2 / ( R 1 + R 2 ) — doosra resistor upar jaata hai.
Current divider mein "doosra" resistor upar kyun hota hai? Kyunki I 1 = V / R 1 = I T R ∥ / R 1 , aur R ∥ mein R 2 hai; R 1 cancel ho jaata hai aur R 2 upar reh jaata hai. Current badi resistance se bachta hai.
General N-branch current divider formula I k = I T G k / ∑ j G j jahan G = 1/ R ; current conductance ke proportion mein split hota hai.
Parallel network mein current ya voltage divide hota hai? Current divide hota hai; voltage saari branches mein common hota hai.
Divider mein kaun si branch sabse zyaada current carry karti hai? Sabse kam resistance (sabse zyaada conductance) wali branch.
Branch currents sahi se sum hoti hain yeh check karo I 1 + I 2 = I T ( R 2 + R 1 ) / ( R 1 + R 2 ) = I T — KCL satisfy karta hai.
I_k = I_T times G_k / sum G_j
Junction with parallel branches
R_parallel = R1 R2 / (R1+R2)
I_1 = I_T times R2/(R1+R2)
Other resistor sits on top
N-branch conductance form
Worked examples verify sum = I_T