WHY a catalyst:H2 has a strong, non-polar bond; the metal surface adsorbs and splitsH2 into reactive H atoms and holds the alkene close, lowering the activation energy. (Syn addition — both H on same face.)
Mechanism (the three phases — derive, don't memorize):
(i) Initiation — homolysis by light:
Cl2hν2Cl∙Why? Cl–Cl is the weakest bond present; UV supplies exactly its bond energy → splits evenly (each atom keeps one electron).
(ii) Propagation — radical in, radical out:
Cl∙+CH4→CH3∙+HClCH3∙+Cl2→CH3Cl+Cl∙Why? The regenerated Cl∙ keeps the chain alive.
(iii) Termination — two radicals meet (chain dies):
Cl∙+Cl∙→Cl2,CH3∙+CH3∙→C2H6,CH3∙+Cl∙→CH3Cl
What reagents define the Wurtz reaction?
Alkyl halide + Na metal in dry ether → symmetrical alkane.
Why can't Wurtz make methane?
It couples two R groups; methane (1C) has no two halves to join.
Why does mixed Wurtz give poor yields?
Radicals cross-couple → mixture of three alkanes, hard to separate.
At which electrode does the alkane form in Kolbe electrolysis?
At the anode (oxidation of carboxylate).
What gas is released in Kolbe electrolysis?
CO₂ (from decarboxylation of RCOO•).
Number of carbons from a Cₙ acid via Kolbe?
2(n−1) — one C lost as CO₂ per side.
Why is a catalyst needed in hydrogenation?
Metal surface adsorbs and splits H₂, lowers activation energy; gives syn addition.
Why does boiling point increase with chain length?
Larger surface area → stronger van der Waals (London) forces.
Why does branching lower boiling point?
More spherical shape → less surface contact → weaker dispersion forces.
Name the three steps of free-radical halogenation.
Initiation, propagation, termination.
Why is initiation done with UV light?
Photon energy homolyzes the weak Cl–Cl/Br–Br bond into radicals.
Non-polar; cannot hydrogen-bond with water ("like dissolves like").
Recall Feynman: explain to a 12-year-old
Alkanes are like Lego bricks made only of strong, plain straight bonds — nothing sticky sticks to them easily. To build a longer brick chain you can: (1) glue two equal pieces with sodium metal (Wurtz), (2) shock acid-salt with electricity so it burps out CO₂ gas and the leftovers join (Kolbe), or (3) squeeze in hydrogen with a metal helper to fill a double bond (hydrogenation). To decorate an alkane you shine light on it with chlorine: the light snaps the Cl₂ in half, and those halves start a domino chain swapping H's for Cl's — but it never stops cleanly, so you get a messy mix.
Dekho, alkanes (CnH2n+2) bahut "shaant" molecules hote hain — sirf single bonds, koi double bond ya lone pair nahi, isliye normal ionic reagents inhe chhedte nahi. Lambi chain banane ke liye teen famous tareeke hain. Wurtz mein alkyl halide ko dry ether mein sodium ke saath milao — do barabar tukde jud jaate hain. Yaad rakho: alag-alag tukde mat lo, warna mixture ban jaata hai, aur methane to bana hi nahi sakte. Kolbe electrolysis mein carboxylic acid ka sodium salt ka aqueous solution electrolyse karo — anode par CO2 nikalta hai aur bache hue radicals jud kar symmetrical alkane dete hain. Hydrogenation mein alkene par Ni/Pt catalyst ke saath H2 add karke alkane banate hain.
Physical properties simple logic se: chain jitni lambi, surface area utna zyada, van der Waals force utna strong, isliye boiling point badhta hai. Branching karne se molecule gol ho jaata hai, contact kam, isliye boiling point gir jaata hai (n-pentane vs neopentane).
Sabse important exam topic hai free-radical halogenation. UV light Cl2 ko do radicals mein tod deti hai (initiation). Phir propagation mein chain chalti rehti hai — ek radical andar, ek radical bahar. Jab do radical aapas mein mil jaayein to chain khatam (termination). Yaad rakho: yeh reaction clean nahi hoti, CH3Cl se aage CH2Cl2,CHCl3,CCl4 tak ban jaata hai, isliye excess alkane use karo. Aur reactivity F2>Cl2>Br2>I2, par selectivity ulti — bromine picky hota hai aur 3° hydrogen prefer karta hai kyunki 3° radical sabse stable hai.