Step 1 — Why do only the eg d-orbitals interact with σ-ligands?
The dz2 and dx2−y2 lobes point directly at the 6 ligands along ±x,±y,±z.
The t2g (dxy,dyz,dxz) lobes point between the axes.
Why this step? Overlap integral S=⟨d∣LGO⟩ is large only when lobes
point at each other; zero by symmetry for t2g with σ-ligands.
Step 2 — Build the σ-MO diagram.
The two eg LGO/metal combinations form a bondingeg (mostly ligand) and an
antibondingeg∗ (mostly metal). The a1g and t1u similarly form bonding/antibonding pairs.
The metal t2g stays non-bonding in the middle.
Step 3 — Identify the frontier gap.
The electrons we care about (the metal d electrons) occupy the t2g (non-bonding) and
the eg∗ (antibonding) sets.
MO theory applied to coordination complexes (CFT + covalency).
In σ-only Oh, which metal d-set is non-bonding?
t2g (dxy,dyz,dxz) — they point between the ligands.
Which metal d-set forms σ-antibonding MOs and why?
eg (dz2,dx2−y2); lobes point straight at the ligands.
Define Δo in MO terms.
Δo=E(eg∗)−E(t2g).
What symmetry do the 6 σ-LGOs span in Oh?
a1g+eg+t1u.
Effect of a π-donor ligand on Δo?
Raises t2g → Δo decreases (weak field).
Effect of a π-acceptor ligand on Δo?
Lowers t2g via back-bonding → Δo increases (strong field).
Why is CO strong-field despite being neutral?
Empty π* orbitals accept metal t2g electrons (back-bonding), widening Δo.
Why can't CFT explain the spectrochemical series?
It ignores covalent π-bonding; point charges would rank negative ligands highest, contradicting CO.
Nephelauxetic effect indicates what?
Covalency — metal d-electron cloud expands onto ligands, lowering electron repulsion.
Recall Feynman: explain to a 12-year-old
Imagine a metal atom holding hands with 6 friends (ligands) in a cube-cross shape. Two of the
metal's "hand-orbitals" point straight at the friends, so they bump into them and get pushed
high up — those are the eg∗. Three other hand-orbitals point into the empty corners, so
they don't bump — they stay low (t2g). The height difference between "bumped" and "not
bumped" is the splitting Δo. Some friends (like CO) also have an empty pocket where the
metal can secretly tuck spare electrons (back-bonding); that secret sharing makes the friendship
stronger and the gap bigger. The size of that gap decides the colour of the complex!
Dekho, CFT (Crystal Field Theory) mein hum maan lete hain ki ligands sirf point charges hain jo
metal ke d-orbitals ko electrostatically upar push karte hain. Yeh kaam to chalta hai, par yeh ek
half-truth hai. Reality mein metal aur ligand ke beech proper covalent bond banta hai. Ligand
Field Theory (LFT) isi reality ko MO theory se describe karti hai — metal ke orbitals aur ligand
ke orbitals mix hote hain aur bonding/antibonding molecular orbitals bante hain.
Octahedral complex mein, metal ke eg orbitals (dz2,dx2−y2) seedhe ligands ki taraf
point karte hain, isliye yeh ligand orbitals se overlap karke antibonding eg∗ banate hain
(energy upar chadh jaati hai). Magar t2g orbitals (dxy etc.) ligands ke beech point
karte hain, to σ-only case mein yeh non-bonding rehte hain. Ab famous Δo ka matlab hai:
Δo=E(eg∗)−E(t2g). Yani gap automatically MO diagram se nikal aaya, koi fudge nahi!
Sabse mast baat — π-bonding. Agar ligand π-donor hai (jaise F−), to woh t2g ko
upar push karta hai, gap chhota ho jaata hai (weak field). Agar ligand π-acceptor hai (jaise CO,
CN⁻), to metal apne t2g electrons unke empty π* mein de deta hai (back-bonding), jisse
t2g neeche aata hai aur gap bada ho jaata hai (strong field). Isliye neutral CO bhi sabse
strong field ligand hai — yeh baat CFT kabhi explain nahi kar sakti, sirf LFT karti hai.
Yeh matter isliye karta hai kyunki yahi gap complex ka colour, magnetism (high-spin vs low-spin) aur
stability decide karta hai. Exam mein spectrochemical series, back-bonding aur high/low spin ke
"kyun" wale questions seedhe is concept se aate hain.