3.4.9 · D1Coordination Chemistry

Foundations — Crystal Field Stabilization Energy (CFSE) — high-spin vs low-spin; spectrochemical series

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Before we can count anything, we must earn every symbol the parent note throws at you. Below, each item gives its plain meaning → the picture → why the topic needs it, ordered so each one leans on the one before.


1. The atom's core cast: metal ion, ligand, -orbital

Figure — Crystal Field Stabilization Energy (CFSE) — high-spin vs low-spin; spectrochemical series

2. Energy, "up" and "down", and repulsion


3. The two split groups: and

Figure — Crystal Field Stabilization Energy (CFSE) — high-spin vs low-spin; spectrochemical series

4. The gap and the barycentre

Recall Why the numbers are 0.4 and 0.6, not 0.5 and 0.5

Three orbitals drop by , two rise by . Balance: . Gap: . Solving gives (down for each of the three) and (up for each of the two). Because there are more orbitals below, each one only needs to sink a little to balance the two that rise a lot.


5. Electrons, pairing, and pairing energy

Figure — Crystal Field Stabilization Energy (CFSE) — high-spin vs low-spin; spectrochemical series

6. High-spin, low-spin, and the fork


7. The output: CFSE


Prerequisite map

metal ion + oxidation state

ligands as point charges

repulsion pushes orbitals

five d-orbital shapes

split into t2g and e_g

gap Delta_o

barycentre balance 3 vs 2

-0.4 and +0.6 energies

electron count d-n

pairing energy P

CFSE formula

high-spin vs low-spin fork


Equipment checklist

I can say what a ligand is and why we model it as a point negative charge.
A lone-pair donor that sticks to the metal; its electron-rich end repels the metal's -electrons, so we treat it as a point of negative charge.
I can name which three -orbitals point between the axes and which two point along them.
Between: (→ ). Along: (→ ).
I know what "higher energy" means for an electron.
Less stable, less comfortable — drawn higher on the energy ruler.
I can define in one sentence.
The energy gap between the lower group and the upper group in an octahedral field.
I can explain why the split energies are and , not .
Barycentre balance with 3 orbitals down and 2 up: and give , .
I know what pairing energy is and when it is charged.
The energy cost of forcing two electrons into one orbital; charged only for new pairs the field creates ( of them).
I can state the high-spin / low-spin rule.
→ high-spin (spread out); → low-spin (pair up).
I can read the CFSE formula term by term.
Lower electrons save each, upper cost each, plus for forced pairs.