2.5.12 · Chemistry › Thermodynamics (Chemical)
Ek spontaneous process woh hota hai jo apne aap hota hai, bina continuously push kiye. Ball apne aap neeche roll karti hai; kabhi apne aap upar nahi jaati. Lekin "energy mein neeche" poori kahani NAHI hai — ice room temperature par spontaneously melt hoti hai chahe melting energy absorb karta hai!
Jo cheez missing hai woh hai entropy (disorder/energy ka spread). Nature spontaneously un states ki taraf move karta hai jahan energy aur matter zyada spread out hote hain, yaani jahan accessible microscopic arrangements ki sankhya zyada hoti hai.
Definition Spontaneous process
Ek process jo, ek baar shuru hone ke baad, bina continuous external intervention ke aage barhta hai. Iska speed se koi lena-dena nahi — rusting spontaneous hai lekin slow hai; diamond → graphite spontaneous hai lekin ages lagte hain.
Common mistake "Spontaneous = fast" ← Steel-man
Kyun sahi lagta hai: aam zindagi mein "spontaneous" ka matlab achanak/jaldi hota hai. Fix yeh hai: thermodynamics mein spontaneity direction ke baare mein hai (process kis taraf jaane ki ijazat hai), rate ke baare mein NAHI. Rate kinetics ka kaam hai. Ek spontaneous reaction infinitely slow ho sakti hai.
S
Ek state function jo microscopic tareekon ki sankhya (W ) ko measure karta hai jisme ek macroscopic state realize ho sakta hai — energy aur matter ka dispersal .
S = k B ln W
jahan k B = 1.38 × 1 0 − 23 J K − 1 (Boltzmann constant) aur W = number of microstates.
W ki jagah ln W KYUN?
Entropy additive honi chahiye: do independent systems ka S = S 1 + S 2 hota hai. Lekin microstates multiply karte hain: W = W 1 × W 2 . Woh akela function jo multiplication ko addition mein badalta hai woh logarithm hai:
ln ( W 1 W 2 ) = ln W 1 + ln W 2
Yeh sirf ek requirement hi log form ko force karti hai. Yeh hai "scratch se derivation" ki formula aisa kyun dikhta hai.
Isothermal process (constant T) ke liye ΔS derive karna: T ko integral se bahar nikalo:
Δ S = T 1 ∫ d q r e v = T q r e v
q r e v kyun, sirf q kyun nahi? Heat ek path function hai. Ek state function paane ke liye (ΔS sirf start aur end par depend karta hai), hume reversible path pe exchange hua heat use karna padta hai — woh unique, "sabse gentle" path jo heat ko maximize karta hai. Koi bhi real (irreversible) path kam useful heat deta hai, isliye neeche inequality hai.
Definition Second law (entropy statement)
Kisi bhi process ke liye, ek isolated system (ya universe) ki entropy kabhi nahi ghatti:
Δ S u ni v = Δ S sy s + Δ S s u r r ≥ 0
> 0 : irreversible / spontaneous
= 0 : reversible / equilibrium par
< 0 : apne aap impossible
Intuition Universe kyun, sirf system kyun nahi?
System akele entropy kho sakta hai (paani freeze hona → zyada ordered). Lekin phir woh surroundings mein heat dump karta hai, unki entropy aur bhi zyada badhata hai. Sum hamesha barhta hai. Isliye spontaneity test hamesha total ka hona chahiye.
Surroundings term derive karna: surroundings constant T par ek bade reservoir ki tarah kaam karte hain. System se nikli heat, q sy s , surroundings mein − q sy s ke roop mein temperature T par jaati hai:
Δ S s u r r = T q s u r r = T − q sy s = T − Δ H sy s ( const P )
Last step mein q P = Δ H use kiya hai.
Worked example 1. Exothermic reaction ke liye surroundings ki entropy
Ek reaction Δ H = − 200 kJ release karta hai T = 300 K par. Δ S s u r r nikalo.
Δ S s u r r = T − Δ H sy s = 300 K − ( − 200000 J ) = + 667 J K − 1
Yeh step kyun? Exothermic → heat surroundings mein bahar flow karti hai → woh zyada disordered ho jaate hain → Δ S s u r r > 0 . Bada negative Δ H surroundings ke through spontaneity drive karta hai.
Worked example 2. 0 °C par ice ka melting (equilibrium)
Δ H f u s = 6.01 kJ mol − 1 , T = 273 K . Melting ke liye Δ S sy s nikalo.
Isothermal, melting point par reversible:
Δ S sy s = T q r e v = T Δ H f u s = 273 6010 = + 22.0 J K − 1 mol − 1
Positive kyun? Solid (ordered lattice) → liquid (mobile) → zyada microstates → S barhta hai.
Second law check: exactly 273 K par, Δ S s u r r = − 6010/273 = − 22.0 , isliye Δ S u ni v = 0 → equilibrium . Ice aur paani saath mein exist karte hain.
Worked example 3. Ideal gas ka isothermal expansion
n mol reversibly aur isothermally V 1 se V 2 tak expand karte hain. Ideal gas ke liye Δ U = 0 (T change nahi), isliye first law se q r e v = − w r e v = ∫ V 1 V 2 P d V = n R T ln V 1 V 2 .
Δ S = T q r e v = n R ln V 1 V 2
Yeh step kyun? Gas bade volume mein spread hota hai → har molecule ke liye zyada positions available → W ↑ → S ↑ . Expansion (V 2 > V 1 ) Δ S > 0 deta hai: matter dispersal.
Worked example 4. Reaction ke liye ΔS ka sign predict karna
CaCO 3 ( s ) → CaO ( s ) + CO 2 ( g ) . Δ S sy s ka sign predict karo.
Reasoning: hum ek solid se ek gas create kar rahe hain. Gas ke paas vastly zyada microstates hote hain. Isliye Δ S sy s > 0 . (Rule of thumb: Δ n g a s > 0 ⇒ Δ S > 0 .)
Common mistake "Exothermic ⇒ hamesha spontaneous" ← Steel-man
Kyun sahi lagta hai: zyatar spontaneous reactions exothermic HAIN, aur energy ghataana usually jeet jaata hai. Fix yeh hai: spontaneity Δ S u ni v = Δ S sy s − Δ H sy s / T se decide hoti hai. Endothermic reactions (Δ H > 0 ) phir bhi spontaneous ho sakti hain agar Δ S sy s itna bada aur positive ho (jaise NH 4 NO 3 ka dissolving — thanda lagta hai, phir bhi khushi se dissolve hota hai).
Δ S sy s < 0 matlab impossible"
Kyun sahi lagta hai: second law kehta hai entropy nahi ghat sakti. Fix yeh hai: Δ S u ni v woh hai jo nahi ghat sakta. System apne aap ko order kar sakta hai jab tak surroundings zyada entropy gain karein.
Recall Feynman: 12-saal ke bachche ko explain karo
Ek saaf Lego ka dabbe ki kalpana karo jo colour ke hisaab se sort kiya gaya hai. Ek baar hilao — mess ho jaata hai. Dobara hilao — woh kabhi magically sort nahi hoga. "Messy" arrangements ke lakhon tarike hain lekin "tidy" ones ke sirf kuch hi, isliye hilane se hamesha mess mein hi aaoge. Entropy count karta hai ki kisi cheez ke paas kitne arrangements hain. Nature hilata rehta hai, isliye poora universe us arrangement ki taraf drift karta hai jiske sabse zyada tarike hain — mess. Isliye heat spread hoti hai, gases rooms bharte hain, aur cheezein theek hone se zyada aasaani se tootti hain. Cheezein "apne aap" sirf uss direction mein hoti hain jo total mess ko bada karti hain.
"S = Spread" aur "UNIverse UP" : Entropy = energy aur matter ka S pread; ek process spontaneous hota hai jab UNI verse ki entropy UP jaati hai (Δ S u ni v > 0 ).
Do-term formula ke liye: "Sys minus H over T" → Δ S u ni v = Δ S sy s − T Δ H sy s .
Recall Examples padhne se pehle, forecast karo:
Gas compress hone par Δ S ka sign? → negative (kam positions).
Endothermic reaction ke liye Δ S s u r r ka sign? → negative (surroundings heat kho dete hain).
Boiling point par, Δ S u ni v = ? → zero (equilibrium).
Thermodynamically spontaneous process kya define karta hai? Woh jo bina continuous external intervention ke aage barhta hai; direction ke baare mein hai, speed ke nahi.
Second law ka entropy form batao. Δ S u ni v = Δ S sy s + Δ S s u r r ≥ 0 ; >0 spontaneous, =0 equilibrium, <0 impossible.
Boltzmann ka entropy equation? S = k B ln W , W = number of microstates.
W ki jagah ln W kyun?Entropy additive honi chahiye jabki microstates multiply karte hain; log products ko sums mein badalta hai.
dS ki thermodynamic definition? d S = T d q r e v (reversible heat over temperature).
Entropy definition mein reversible heat kyun? Heat ek path function hai; sirf reversible path ΔS ke liye ek state-function value deta hai.
Constant P par surroundings ke ΔS ka formula? Δ S s u r r = − T Δ H sy s .
Isothermal reversible ideal-gas expansion ke liye ΔS? Δ S = n R ln V 1 V 2 .
ΔH_fus se ΔS of fusion? Δ S = T m e l t Δ H f u s .
Kya ek exothermic reaction non-spontaneous ho sakta hai? Haan, agar Δ S sy s bahut negative ho to Δ S u ni v < 0 .
Kya ek endothermic reaction spontaneous ho sakta hai? Haan, agar Δ S sy s bada positive ho (jaise NH4NO3 ka dissolving).
Reaction mein gas ke moles badhne par ΔS ka sign? Positive.
Energy and matter dispersal
Additive from multiplying microstates
q_rev makes S a state function
ΔS_univ = ΔS_sys + ΔS_surr ≥ 0