2.3.13 · Chemistry › Chemical Bonding
Jab do atoms paas aate hain, unke atomic orbitals (AOs) overlap karte hain aur mix ho jaate hain. Do AOs andar jaate hain to do molecular orbitals (MOs) bante hain — ek energy mein neeche (bonding , yahan ke electrons atoms ko jodte hain) aur ek upar (antibonding , yahan ke electrons atoms ko alag dhakelte hain). Hum bas in MOs mein electrons sabse neeche se bharte hain (Aufbau, Pauli, Hund) aur do cheezein padhte hain:
Bond order = kitne net bonds molecule ko thaam ke rakhte hain.
Magnetism = paramagnetic agar koi unpaired electrons hain, warna diamagnetic.
MO kya hai: ek molecule-wide electron wavefunction jo atomic wavefunctions ko combine karke banti hai — yani Linear Combination of Atomic Orbitals (LCAO).
Do AOs se do MOs kyun: waves do tarah se add ho sakti hain — in phase (constructive → electron density nuclei ke beech mein ikatti hoti hai → stabilizing) ya out of phase (destructive → nuclei ke beech ek node → destabilizing). Do inputs se do combinations milte hain.
ψ bonding = ψ A + ψ B ψ antibonding = ψ A − ψ B
Definition Bonding vs antibonding
Bonding MO (σ, π) : energy mein neeche, nuclei ke beech zyada electron density, unke beech koi node nahi.
Antibonding MO (σ*, π*) : energy mein upar, nuclei ke beech ek nodal plane; asterisk ise mark karta hai.
AOs 1 s , 2 s , 2 p se MOs ka order:
B₂, C₂, N₂ ke liye (Z ≤ 7) — s–p mixing σ2p ko π2p ke upar dhakelta hai:
σ 1 s < σ 1 s ∗ < σ 2 s < σ 2 s ∗ < π 2 p x = π 2 p y < σ 2 p z < π 2 p x ∗ = π 2 p y ∗ < σ 2 p z ∗
O₂, F₂ ke liye (Z ≥ 8) — koi significant mixing nahi, σ2p π2p ke neeche :
⋯ < σ 2 p z < π 2 p x = π 2 p y < π 2 p x ∗ = π 2 p y ∗ < σ 2 p z ∗
Intuition O₂ par order kyun palat jaata hai
Pehle elements mein 2s aur 2p ki energies paas paas hoti hain, isliye σ2s aur σ2p ek doosre ko repel karte hain (mix hote hain); σ2p upar dhakela jaata hai π se bhi upar. Oxygen tak 2s–2p gap bada ho jaata hai, mixing kamzor ho jaati hai, aur natural order (σ neeche π ke) wapas aa jaata hai.
Config: σ 1 s 2 . Kyun: dono electrons sabse neeche wale ek bonding MO mein girte hain, paired.
BO = 2 2 − 0 = 1 . Sab paired → diamagnetic . Ek real H–H single bond. ✔
Worked example He₂ (4 e⁻)
Config: σ 1 s 2 σ 1 s ∗ 2 . Kyun: extra pair ko antibonding MO mein jaana padta hai.
BO = 2 2 − 2 = 0 → koi bond nahi , He₂ exist hi nahi karta. Diamagnetic. ✔
Worked example N₂ (14 e⁻) —
mixed order use karo
σ 1 s 2 σ 1 s ∗ 2 σ 2 s 2 σ 2 s ∗ 2 π 2 p 4 σ 2 p 2 .
N b = 10 , N a = 4 . BO = 2 10 − 4 = 3 → triple bond (bahut chhota, bahut strong).
Diamagnetic kyun: π2p⁴ aur σ2p² sab paired hain, koi half-filled MO nahi. ✔
Worked example O₂ (16 e⁻) — star example,
unmixed order
… σ 2 s 2 σ 2 s ∗ 2 σ 2 p 2 π 2 p 4 π 2 p ∗ 2 .
Last 2 electrons do degenerate π* orbitals mein jaate hain — Hund's rule se ek ek, parallel spins .
BO = 2 10 − 6 = 2 (double bond). Do unpaired e⁻ → paramagnetic.
Yeh famous kyun hai: Lewis structures sab-paired O=O predict karte hain, lekin liquid O₂ magnet se chipakta hai. MO theory paramagnetism predict karta hai — yahi iski jeet hai. ✔
Worked example F₂ (18 e⁻)
… σ 2 p 2 π 2 p 4 π 2 p ∗ 4 .
N b = 10 , N a = 8 . BO = 2 10 − 8 = 1 → single bond. Sab paired → diamagnetic . ✔
Worked example NO (15 e⁻) — heteronuclear, odd electron
N₂-type order use karo (average Z < 8 wali side theek hai yahan). 15 bharo:
… π 2 p 4 σ 2 p 2 π 2 p ∗ 1 . 15th electron π* mein akela unpaired hai.
N b = 10 , N a = 5 . BO = 2 10 − 5 = 2.5 . Ek unpaired e⁻ → paramagnetic.
BO 2.5 kyun: woh antibonding e⁻ nikaal do (→ NO⁺) to BO 3 ho jaata hai, isliye NO⁺ zyada strong/chhota hota hai — ek achha check hai.
Worked example CO (14 e⁻) — N₂ ke saath isoelectronic
N₂ jaisa hi 14 electrons: … π 2 p 4 σ 2 p 2 .
BO = 3 , diamagnetic . Kyun matter karta hai: CO ka strong triple bond aur C par lone pair explain karta hai ki yeh metals se itna tight kyun bind karta hai (aur haemoglobin ke liye toxic kyun hai).
Common mistake Classic galtiyon ko steel-man karna
1. "O₂ diamagnetic hai (Lewis kehta hai O=O, sab paired)." Sahi lagta hai kyunki dot structure sab kuch pair kar deta hai. Fix: do π* orbitals degenerate hain, isliye Hund do parallel unpaired electrons force karta hai. Experiment (magnet) MO confirm karta hai, Lewis nahi.
2. "Sab molecules ke liye same MO order use karo." Sahi lagta hai — ek rule aasaan hota hai. Fix: B₂–N₂ ke liye σ2p π2p ke upar hota hai (s–p mixing) lekin O₂, F₂ ke liye neeche . Galat order use karne se unka magnetism galat aata hai.
3. "Bond order integer hona chahiye." Sahi lagta hai Lewis single/double/triple se. Fix: odd-electron species (NO, O₂⁺, superoxide O₂⁻) half-integer bond orders dete hain — bilkul valid hain.
4. "Zyada bond order ⇒ zyada electrons ⇒ bhaari zyada strong hota hai." Fix: bond order N b − N a hai; antibonding electrons add karne se kamzori aati hai. F₂ (18 e⁻), N₂ (14 e⁻) se kamzor hai.
Recall Feynman: 12 saal ke bacche ko samjhao
Socho do magnets-on-springs (atoms) paas aa rahe hain. Unke "clouds" ek aisi shape mein mil sakte hain jo unke beech chipakti hai (glue = bonding) ya ek aisi shape mein jinke beech gap hai jo unhe dhakelta hai (anti-glue = antibonding). Tumhare paas chhote chhote log (electrons) hain aur tum unhe sabse neechi kursi pehle dete ho, do per kursi, aur agar do barabar-unchai wali kursiyan khaali hain to pehle ek ek baithao phir double up karo. Count karo kitne "glue" kursiyon mein baithe minus "anti-glue" kursiyon mein, do se divide karo — utne bonds hain. Agar koi akela baitha hai (unpaired), molecule magnet feel karta hai.
"Sober Physicists Don't Find Giraffes Hiding In Kitchens" order flip ke liye? Aasaan:
"Bade atoms Boron→Nitrogen: π σ se pehle (pi popular hai, pehle aata hai)." O aur F: "Oxygen Flip karta hai — sigma neeche jaata hai."
O₂ = "Oxygen is Odd on the magnet" → paramagnetic, 2 unpaired.
Bond order chain: N₂(3) > O₂(2) > F₂(1) — antibonding mein e⁻ chadne se bonds toot jaate hain.
MO theory mein bond order ka formula? B O = 2 N b − N a (bonding minus antibonding electrons, 2 se divide).
O₂ paramagnetism kyun dikhata hai? Uske last 2 electrons do degenerate π*2p orbitals mein alag alag baithte hain (Hund's rule) → 2 unpaired electrons.
O₂ ka bond order aur magnetism? BO = 2; paramagnetic (2 unpaired).
N₂ ka bond order aur diamagnetic kyun? BO = 3; sab electrons paired hain (π2p⁴ σ2p² full) → diamagnetic.
Kin molecules mein σ2p π2p ke UPAR hota hai? B₂, C₂, N₂ (Z ≤ 7) — s–p mixing ki wajah se.
Kin molecules mein σ2p π2p ke NEECHE hota hai? O₂, F₂ (Z ≥ 8) — negligible s–p mixing.
NO ka bond order aur magnetism? BO = 2.5; paramagnetic (π* mein 1 unpaired electron).
He₂ exist kyun nahi karta? Config σ1s² σ*1s²; BO = (2−2)/2 = 0, koi net bond nahi.
F₂ ka bond order? 1 (single bond), diamagnetic.
CO kis molecule ke saath isoelectronic hai; uska BO? N₂ ke saath (14 e⁻); BO = 3, diamagnetic.
N₂ vs O₂ vs F₂ ka bond order comparison? 3 > 2 > 1 (extra electrons antibonding MOs mein jaate hain, bond kamzor hota hai).
NO → NO⁺ jaane par bond order ka kya hota hai? 2.5 se 3 ho jaata hai (ek antibonding π* electron nikal jaata hai).
MO par asterisk (*) ka matlab? Antibonding orbital: nuclei ke beech node hota hai, energy zyada hoti hai, destabilizing hota hai.
Bond Order = Nb minus Na over 2