Before you can use the parent note Polarity of molecules, you must own every symbol it throws at you. This page builds each one from absolute zero, in the order that each rests on the one before.
Look at figure s01: the electron cloud (the shaded blob) is lopsided toward the right atom. That lopsidedness is what δ− and δ+ record. Which atom hogs the electrons is decided by Electronegativity — the very next foundation.
Why the topic needs it: these partial charges are the two ends of the arrow we are about to draw.
Why the topic needs it: electronegativity difference decides (a) whether a bond has a dipole at all, and (b) which way its arrow points — from the loser (δ+) toward the winner (δ−). See Electronegativity for the full scale.
This is the most important tool on the page, so we build it slowly.
Why the topic needs it: the molecular dipole IS the head-to-tail sum of the bond arrows. If you only know Vectors and the Cosine Rule you already know the maths of polarity — the chemistry just supplies the arrows.
Why the topic needs it: this is literally the parent page's headline formula. Its full derivation and every quadrant lives in Vectors and the Cosine Rule.
Cover the right side and test yourself. If any answer surprises you, reread that section.
What do δ+ and δ− mean, and why "partial"?
Small equal-and-opposite charges on a bond's two ends; "partial" because electrons are only pulled closer, not fully transferred.
What single property decides which atom gets δ−?
Electronegativity — the greedier (higher) atom pulls electrons and becomes δ−.
What makes a quantity a vector, not just a number?
It has both a size AND a direction; drawn as an arrow.
How do you add two vectors?
Head-to-tail: put the second arrow's tail on the first arrow's head; the sum runs from first tail to last head.
Why can two arrows "cancel"?
Equal length + exactly opposite direction returns you to the start, giving a zero-length resultant.
Which way does the chemistry dipole arrow point?
From δ+ to δ− (toward the more electronegative atom).
State μ=qd in words.
Dipole vector = charge size times the separation arrow (from + to −); it points the same way as d.
Roughly how big is a real bond dipole, in Debye?
About 0.5–2D (a full ±1 charge over 1Å would be ≈4.8D).
What is cosθ at 0°, 90°, 180°?
+1, 0, −1 respectively — the dial from "fully add" to "fully cancel."
Write the cosine-rule resultant for two equal dipoles at angle θ.
μnet=2μcos(θ/2).
Why include lone pairs and what does ∑ mean?
Lone pairs are extra charge lumps with their own arrows; ∑ means add up every charge-times-position term head-to-tail.
Recall Ready check
If you can draw a bond as an arrow from δ+ to δ−, add two arrows head-to-tail, and say what cosθ does as θ opens from 0° to 180° — you are fully equipped to read the parent note. Go to the main topic next.