3.1.6Mendelian Genetics

Solve monohybrid crosses with Punnett squares

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Core Concepts (the 20% that explains 80%)


HOW to build a Punnett square — derivation from first principles

We rely on Mendel's Law of Segregation: the two alleles of a gene separate during gamete formation, so each gamete gets exactly one.

Step-by-step method:

  1. Write each parent's genotype.
  2. List the possible gametes (split the pair) for each parent.
  3. Draw a grid: one parent's gametes label the columns, the other's the rows.
  4. Fill each cell by combining the column allele + row allele.
  5. Count genotype ratios, then convert to phenotype ratios using dominance.
Figure — Solve monohybrid crosses with Punnett squares

Worked Examples


Forecast-then-Verify

Recall Predict before you compute

A pure-breeding tall plant (TTTT) is crossed with a short plant (tttt). The F1F_1 is self-crossed. Forecast: What phenotype ratio in F2F_2? Verify: F1=TtF_1 = Tt. Tt×Tt1TT:2Tt:1ttTt \times Tt \Rightarrow 1\,TT:2\,Tt:1\,tt \Rightarrow 3 tall : 1 short.


Common Mistakes (Steel-manned)


Flashcards

What does a monohybrid cross study?
Inheritance of a single gene/trait across generations.
State Mendel's Law of Segregation.
The two alleles of a gene separate during gamete formation; each gamete receives exactly one allele.
Genotype ratio of Aa×AaAa \times Aa?
1AA:2Aa:1aa1\,AA : 2\,Aa : 1\,aa.
Phenotype ratio of Aa×AaAa \times Aa (complete dominance)?
3 dominant : 1 recessive.
Why is AaAa phenotype identical to AAAA?
One dominant allele produces enough functional product to show the dominant trait.
What is a test cross and why use aaaa?
Crossing an unknown dominant with homozygous recessive (aaaa); offspring phenotypes directly reveal the unknown's gametes.
Phenotype ratio of test cross Aa×aaAa \times aa?
1 dominant : 1 recessive.
Result of AA×aaAA \times aa?
All offspring AaAa → 100% dominant phenotype (F1F_1 uniform).
Each cell in a 2×2 Punnett square represents what probability?
14\tfrac14 (equally likely fertilization outcome).
Difference between genotype and phenotype?
Genotype = allele pair (e.g., YyYy); phenotype = observable trait (e.g., yellow).
How many gamete types does a homozygote produce?
One.
How many gamete types does a heterozygote produce?
Two (each ~50%).

Recall Feynman: explain to a 12-year-old

Imagine each parent has two "trait cards" but can only hand ONE card to a baby. Dad shuffles his two cards and gives one; Mom does the same. The Punnett square is a tiny table listing every way Dad's card can meet Mom's card. Some cards are "loud" (dominant) — if a baby gets even one loud card, that's what you see. A "quiet" (recessive) trait only appears when the baby gets two quiet cards. Count the boxes, and you can predict how the babies will probably look!


Connections

Concept Map

has versions

pair forms

expressed as

dominant capital

recessive lowercase

explains

shows only if yy

one allele per

combine randomly

uses

gives

with dominance

counted in

Gene one trait

Alleles Y or y

Genotype

Phenotype

Dominant masks other

Recessive needs two copies

Law of Segregation

Gametes

Punnett Square grid

Product and sum rules

1 AA : 2 Aa : 1 aa

3 dominant : 1 recessive

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, monohybrid cross ka matlab hai hum sirf ek hi trait (jaise pea ka seed color) ko track kar rahe hain. Har parent ke paas us gene ke do allele hote hain, lekin Law of Segregation ke according har parent apne baby ko sirf ek allele deta hai. Punnett square bas ek chhoti si table hai jisme hum dad ke possible gametes ko upar (columns) aur mom ke gametes ko side me (rows) likhte hain, aur har box me combine karke baby ka genotype nikalte hain.

Sabse important baat: dominant allele (capital letter, jaise YY) sirf ek copy se hi apna effect dikha deta hai, kyunki wo ek working protein banata hai. Recessive trait (yyyy) tabhi dikhta hai jab dono copies recessive ho. Isiliye YyYy bhi yellow dikhta hai, YYYY ki tarah — ye "paint mixing" jaisa nahi hota, blend nahi hota (complete dominance me).

Classic result yaad rakho: Yy×YyYy \times Yy karne par genotype ratio aata hai 1YY:2Yy:1yy1\,YY:2\,Yy:1\,yy, aur phenotype ratio aata hai 3 yellow : 1 green. Test cross (Yy×yyYy \times yy) me ratio 1:11:1 aata hai — ye trick se hum pata kar sakte hain ki koi yellow plant YYYY hai ya YyYy. Exam me dhyan rakho: genotype ratio aur phenotype ratio alag-alag cheez hain, jo question pooche wahi do!

Har box ka probability 14\tfrac14 hota hai. Do boxes me YyYy aaya, isliye YyYy ka chance 24=12\tfrac24=\tfrac12 ho gaya. Bas yahi product rule aur sum rule chhupa hua hai Punnett square ke peeche. Samajh gaye toh genetics ke aadhe numericals yahin se ban jayenge!

Test yourself — Mendelian Genetics

Connections