Before you can read the parent note, you must be able to read every squiggle it writes. Below is every symbol and idea it uses, built from the ground up. Nothing is assumed. If the parent leaned on it, we build it here first.
We will keep every example in 2D so you can see it. Our running pair of clusters — the ones the parent uses for single, complete, and average linkage — are:
A={(0,0),(1,1)} — two dots near the bottom-left corner
B={(5,5),(6,6)} — two dots up in the top-right
Look at the picture: four chalk dots. Two are huddled near the origin (that's cluster A, pale yellow), two are huddled far away (that's cluster B, chalk blue). This one image is the stage for the min/max/sum linkage examples. (Ward's linkage in §6 needs a different, clearly-announced pair — watch for it.)
Recall
What does the pair (6,6) mean as a picture? ::: A dot 6 units to the right and 6 units up from the origin.
The parent writes d(a,b) everywhere. It means: how far apart are two dots? We measure it with a ruler laid straight between them — the Euclidean distance.
Why the square root of squares? Because of the right triangle. Walk right by (a1−b1), then up by (a2−b2): those are the two legs of a right triangle whose hypotenuse is the direct path. Pythagoras says (leg)² + (leg)² = (hypotenuse)², so the straight distance is the square root of the two squared legs.
Recall
Why square each coordinate difference before adding? ::: To kill the sign (so −4 counts the same as +4) and to make Pythagoras hold, giving a true straight-line length.
The Ward example's cluster (introduced later in §6) A′={(0,0),(2,0),(1,1)} has ∣A′∣=3.
Why the topic needs this: Average and Ward's linkage divide by counts like ∣A∣⋅∣B∣. If you don't know ∣A∣ just means "how many dots in A," those formulas are unreadable.
The parent writes things like mina∈A,b∈Bd(a,b). In plain words: look at every dot a taken from bag A, paired with every dot b taken from bag B. With the running clusters ∣A∣=2 and ∣B∣=2 there are 2×2=4 such pairs — exactly the four distances the parent lists.
The picture shows all four pairing-lines drawn between the two clusters. Every linkage method is just a different way of choosing which of these lines to report.
Single linkage = min of the four lines → the closest pair. Picture: the shortest of the four chalk lines in figure s03.
Complete linkage = max of the four lines → the farthest pair.
Recall
Single linkage uses min; which pair of dots does that correspond to in the picture? ::: The closest dot in A to the closest dot in B — the shortest connecting line.
Cutting the tree with a horizontal line at height h chops the tree into pieces: the number of vertical lines the cut crosses is the number of clusters you keep. Cut low → many tiny clusters; cut high → few big clusters.
Each node below matches a heading above: "cluster A and size bars" is §2, "all pairs a in A b in B" is §3, and so on.
Read it as: points give distances; distances over all pairs feed the min/max/sum rules; sizes and centroids feed Ward; and all four rules feed the merge heights of the dendrogram.