This page assumes you know nothing beyond arithmetic and reading a graph. We build every tool the parent uses, in the order it needs them, so no symbol appears before you own it.
Picture: think of a dart landing somewhere on a ruler. Before the throw, the landing spot is X. After the throw, "it landed at 0.3" is a value x=0.3.
Why the topic needs it. All three distributions describe what number is likely to come out: a random weight, a random waiting time, a random probability. Without X there is nothing to describe.
X∼U(a,b) — the little "∼" reads "is distributed as". It says: "the box X follows the recipe on the right." So X∼U(a,b) = "X is a Uniform box between a and b."
For a continuous box (one that can land on any real number, not just whole numbers), asking "what is the chance X equals exactly 0.3000…?" is hopeless — there are infinitely many points, so any single one has chance 0. Instead we measure how densely packed the belief is near each point.
Look at the figure: the shaded amber region between x=1 and x=2is the probability that X lands in [1,2]. Its area — not the curve's height — is the number between 0 and 1.
The moment we said "probability = area," we needed a machine that computes area under a curved top. That machine is the integral. We chose it — not multiplication — because the blanket's height changes as x moves, so we can't just do "height × width."
dx = an infinitely thin sliver of width along the ruler.
∫ab = "sum the strips from the left edge a to the right edge b."
The bar rule[g(x)]ab=g(b)−g(a) means "plug in the top edge, subtract the bottom edge." The parent uses this in every derivation.
Why the topic needs it. The Uniform mean ∫abxb−a1dx, the Beta normaliser ∫01xα−1(1−x)β−1dx, and the check "∫cdx=1" are all this same summing machine.
Instead of "area over a middle stretch," often we want "area from the far left up to a point x" — the total belief that X came out at most x.
The staircase-smooth curve in the figure only ever rises. Its height at x equals the shaded area to its left in the PDF picture.
Why the topic needs it. The Exponential's F(t)=1−e−λt and Uniform's F(x)=b−ax−a are CDFs. Percentile questions ("95th percentile wait time") solve the CDF equation for x.
Why the parent uses E[X2]−(E[X])2. It's the same variance, rearranged so you only need two integrals (∫xf and ∫x2f) instead of expanding (x−μ)2 by hand. See Maximum Likelihood Estimation for where means and variances get estimated from data.
The Exponential distribution is named after this. We need it before the parent uses e−λt.
λ (Greek "lambda") controls how fast it decays: bigger λ = steeper drop.
e−λt answers "what fraction of belief is still to the right of time t?" — that's exactly P(T>t), the chance you're still waiting.
ln (natural log) is the undo button for e: ln(ex)=x. The parent uses it to solve e−0.5t=0.05 for t — take ln of both sides to bring t down from the exponent.
Why the topic needs it. Every Exponential formula (f=λe−λt, F=1−e−λt, memorylessness) rides on this decaying curve. It flows from the Poisson Process, which counts events happening at steady rate λ.
Why the topic needs it. Beta lives on [0,1] to model a probability of a probability. This is the engine of Bayesian Inference and Conjugate Priors and powers Thompson Sampling.