Level 3 — ProductionOptions Basics

Options Basics

45 minutes60 marksprintable — key stays hidden on paper

Level: 3 (Production — from-scratch derivations, explain-out-loud) Time limit: 45 minutes Total marks: 60


Instructions: Answer all questions. Show full working. Use ...... for math. State assumptions where relevant. Round currency to two decimals.


Question 1 — Payoff derivation from first principles (12 marks)

A trader buys one call option on stock XYZ with strike K=100K = 100, paying a premium c=4.50c = 4.50.

(a) Derive, from first principles, the payoff-at-expiry function P(ST)P(S_T) for the long call, and separately the profit function including premium. Write both as piecewise expressions. (4)

(b) Compute the breakeven spot price and explain out loud (in words) why the intrinsic value is zero below the strike. (3)

(c) The seller of this same call has what maximum profit and maximum loss? Derive the seller profit function and show it is the mirror image of the buyer's. (5)


Question 2 — Intrinsic vs time value decomposition (10 marks)

A put option has strike K=250K = 250. The underlying trades at S=242S = 242. The put's market premium is 13.0013.00.

(a) Compute the intrinsic value and time value. Show the formula for a put's intrinsic value from scratch. (4)

(b) Classify the moneyness (ITM/ATM/OTM) and justify. (2)

(c) At expiry, all else equal, what happens to time value and why? If ST=244S_T = 244 at expiry, what is the put buyer's total profit? (4)


Question 3 — Option chain reading & PCR (10 marks)

From memory, given the following extract of an option chain for a Nifty-style index at spot =20,000= 20{,}000:

Strike Call OI Put OI
19800 12,000 45,000
19900 18,000 38,000
20000 40,000 40,000
20100 55,000 20,000
20200 60,000 11,000

(a) Compute the Put-Call Ratio (PCR) by open interest across these strikes. Show the formula. (3)

(b) Interpret the PCR value: is the aggregate positioning bullish or bearish, and what is the standard reasoning? (3)

(c) Identify the likely support and resistance strikes from the OI, and explain out loud why maximum put OI acts as support. (4)


Question 4 — Moneyness, exercise & assignment (10 marks)

(a) Define ITM, ATM, OTM for both calls and puts using a single moneyness condition each (from memory). (3)

(b) Explain the mechanics of exercise vs assignment: who initiates each, and what happens to the counterparty. (3)

(c) A trader holds a European call, strike 500, on a stock now trading at 540 two weeks before expiry. It is deeply ITM. Can they capture the gain now? Contrast with an American call and explain the practical consequence. (4)


Question 5 — Combined-position payoff (from scratch) (10 marks)

A trader buys a put (strike 100, premium 3) and sells a call (strike 110, premium 2) on the same stock, same expiry.

(a) Write the combined profit function Π(ST)\Pi(S_T) as a piecewise expression over the three regions defined by the strikes. (6)

(b) Compute the net premium (paid/received) and the profit if ST=105S_T = 105. (2)

(c) State the maximum profit and identify the region of STS_T where the position is loss-making without bound (if any). (2)


Question 6 — Explain out loud (8 marks)

In your own words (2–4 sentences each):

(a) Why does an option buyer have limited loss but a naked call seller has theoretically unlimited loss? (4)

(b) Why does time value decay accelerate as expiry approaches, and how does moneyness affect the magnitude of time value? (4)

Answer keyMark scheme & solutions

Question 1 (12)

(a) Long call payoff at expiry: the holder exercises only if ST>KS_T > K, gaining STKS_T - K; otherwise lets it expire (payoff 0). P(ST)=max(STK,0)={0ST100ST100ST>100P(S_T) = \max(S_T - K, 0) = \begin{cases} 0 & S_T \le 100 \\ S_T - 100 & S_T > 100 \end{cases} (2) Profit subtracts premium c=4.50c=4.50: Π(ST)=max(ST100,0)4.50\Pi(S_T) = \max(S_T - 100, 0) - 4.50 (2)

(b) Breakeven: Π=0ST1004.50=0ST=104.50\Pi = 0 \Rightarrow S_T - 100 - 4.50 = 0 \Rightarrow S_T = 104.50. (2) Below strike, the right to buy at 100 is worthless because you could buy cheaper in the market, so intrinsic value = 0. (1)

(c) Seller profit = premium received minus payoff obligation: Πsell(ST)=4.50max(ST100,0)\Pi_{sell}(S_T) = 4.50 - \max(S_T - 100, 0) (2) Max profit = +4.50+4.50 (when ST100S_T \le 100). (1) Max loss = unlimited (as STS_T \to \infty). (1) It is the mirror: Πsell=Πbuy\Pi_{sell} = -\Pi_{buy} (zero-sum, ignoring fees). (1)


Question 2 (10)

(a) Put intrinsic value =max(KS,0)=max(250242,0)=8= \max(K - S, 0) = \max(250 - 242, 0) = 8. (2) Time value = premium − intrinsic = 138=513 - 8 = 5. (2)

(b) S=242<K=250S=242 < K=250, so put is ITM by 8 points (right to sell at 250 above market). (2)

(c) At expiry time value 0\to 0; the option is worth only intrinsic since no time remains for further favourable moves. (2) At ST=244S_T=244: intrinsic =max(250244,0)=6=\max(250-244,0)=6; profit =613=7.00= 6 - 13 = -7.00 (loss of 7.00). (2)


Question 3 (10)

(a) PCR=Put OICall OI\text{PCR} = \dfrac{\sum \text{Put OI}}{\sum \text{Call OI}}. Put OI sum =45,000+38,000+40,000+20,000+11,000=154,000= 45{,}000+38{,}000+40{,}000+20{,}000+11{,}000 = 154{,}000. Call OI sum =12,000+18,000+40,000+55,000+60,000=185,000= 12{,}000+18{,}000+40{,}000+55{,}000+60{,}000 = 185{,}000. PCR=154,000185,0000.832\text{PCR} = \frac{154{,}000}{185{,}000} \approx 0.832 (3)

(b) PCR <1< 1 means more call OI than put OI, indicating aggregate bearish/cautious positioning (more call writing/interest above). Standard contrarian view: very low PCR can signal excessive bullishness (overbought); here mildly bearish tilt. (3)

(c) Highest put OI at 19,800 (45,000) → support; highest call OI at 20,200 (60,000) → resistance. (2) Max put OI = heavy put writers who profit if price stays above that strike; they defend it, and put buyers' hedging keeps price from falling below — acting as support. (2)


Question 4 (10)

(a) Using moneyness (SS vs KK): (3, 1 each pair)

  • Call: ITM if S>KS>K, ATM if SKS\approx K, OTM if S<KS<K.
  • Put: ITM if S<KS<K, ATM if SKS\approx K, OTM if S>KS>K.

(b) Exercise is initiated by the option buyer/holder invoking their right. Assignment is imposed on a seller/writer (chosen, often randomly) who must fulfil the obligation — deliver/buy the underlying at strike. (3)

(c) A European call cannot be exercised early — only at expiry. But the trader can sell (close) the option in the market to capture the current value (intrinsic + remaining time value). (2) An American call can be exercised anytime; practically, however, selling is usually better than early exercise because it also captures time value (early exercise forfeits it). (2)


Question 5 (10)

(a) Long put (K=100): max(100ST,0)3\max(100-S_T,0)-3. Short call (K=110): 2max(ST110,0)2-\max(S_T-110,0). Combined Π(ST)\Pi(S_T):

  • ST<100S_T < 100: (100ST)3+2=99ST(100-S_T) - 3 + 2 = 99 - S_T (2)
  • 100ST110100 \le S_T \le 110: 03+2=10 - 3 + 2 = -1 (2)
  • ST>110S_T > 110: 3+2(ST110)=109ST-3 + 2 - (S_T-110) = 109 - S_T (2)

(b) Net premium =3+2=1= -3 + 2 = -1 (net paid 1). At ST=105S_T=105 (middle region) Π=1\Pi = -1. (2)

(c) Max profit occurs as ST0S_T \to 0: 990=9999 - 0 = 99 (bounded by 99 in practice since stock 0\ge 0). Loss unbounded as STS_T \to \infty (from short call): region ST>110S_T > 110, Π=109ST\Pi = 109 - S_T \to -\infty. (2)


Question 6 (8)

(a) A buyer pays a premium and can at most lose that premium — payoff is floored at 0, so loss is capped. A naked call seller must deliver at strike regardless of how high price rises; since STS_T has no upper bound, the obligation (STK)-(S_T-K) grows without limit → unlimited loss. (4)

(b) Time value (theta decay) accelerates near expiry because the probability window for further favourable moves shrinks rapidly and non-linearly. ATM options carry the most time value (greatest uncertainty about final moneyness); deep ITM/OTM options carry little time value. (4)


[
  {"claim":"Long call breakeven at 104.50","code":"K=100; c=4.5; result = (K+c==104.5)"},
  {"claim":"Put profit at S_T=244 is -7","code":"intrinsic=max(250-244,0); profit=intrinsic-13; result=(profit==-7)"},
  {"claim":"PCR approx 0.832","code":"puts=45000+38000+40000+20000+11000; calls=12000+18000+40000+55000+60000; pcr=Rational(puts,calls); result=(abs(float(pcr)-0.832)<0.005)"},
  {"claim":"Straddle-like combo profit at S_T=105 is -1","code":"S=105; longput=max(100-S,0)-3; shortcall=2-max(S-110,0); result=(longput+shortcall==-1)"},
  {"claim":"Combo profit at S_T=115 equals -6","code":"S=115; longput=max(100-S,0)-3; shortcall=2-max(S-110,0); result=(longput+shortcall==-6)"}
]