Entry, Exit & Trade Management
Level 1: Recognition
Time Limit: 20 minutes | Total Marks: 30
Section A — Multiple Choice (1 mark each)
Choose the single best answer.
Q1. The minimum acceptable risk-reward ratio commonly recommended for a trade is:
- (a) 1:0.5
- (b) 1:1
- (c) 1:2
- (d) 2:1
Q2. An ATR-based stop-loss places the stop at a distance determined by:
- (a) A fixed dollar amount
- (b) A multiple of the Average True Range
- (c) The previous day's close
- (d) The broker's margin requirement
Q3. "1R" in R-multiple terminology refers to:
- (a) Total account balance
- (b) The initial risk (entry minus stop) per unit
- (c) The reward target only
- (d) The number of shares traded
Q4. A break-even stop is defined as moving the stop-loss to:
- (a) A level below entry to allow room
- (b) The entry price so the trade risks nothing further
- (c) The profit target
- (d) The day's low
Q5. Scaling out of a position means:
- (a) Adding units as price moves in your favour
- (b) Exiting the entire position at once
- (c) Closing part of the position while letting the rest run
- (d) Increasing leverage on the trade
Q6. A trading setup with clear rules primarily helps a trader to:
- (a) Guarantee profits
- (b) Remove ambiguity and act consistently
- (c) Avoid paying commissions
- (d) Predict news events
Q7. Expectancy of a trading system is best described as:
- (a) The largest winning trade
- (b) The average R (or currency) gained per trade over many trades
- (c) The win rate alone
- (d) The stop-loss distance
Q8. A structure-based stop is placed:
- (a) At a fixed percentage from entry
- (b) Beyond a swing high/low or support/resistance level
- (c) Randomly to avoid detection
- (d) At the ATR midpoint
Q9. "Cutting losers quickly" is important because:
- (a) It maximises the number of trades
- (b) It limits losses to the planned risk and preserves capital
- (c) It guarantees the next trade wins
- (d) It reduces brokerage fees
Q10. A trailing stop is used mainly to:
- (a) Lock in profits as price moves favourably while giving room to run
- (b) Increase position size
- (c) Set the initial entry
- (d) Determine the risk-reward ratio
Section B — Matching (1 mark each)
Match each term in Column X to its correct description in Column Y.
| # | Column X | Column Y | |
|---|---|---|---|
| Q11 | Fixed stop | A | Stop set X × ATR from entry |
| Q12 | ATR stop | B | Adding to a position in stages |
| Q13 | Scaling in | C | Stop at a fixed % / point distance |
| Q14 | Entry confirmation | D | Exit signal reducing further risk |
| Q15 | Profit booking | E | A second signal validating the primary entry trigger |
(Write answers as Q11–?, etc.)
Section C — True/False WITH Justification (2 marks each: 1 for T/F, 1 for justification)
Q16. A trade with a 1:3 risk-reward ratio can be profitable overall even if it wins only 40% of the time.
Q17. Moving a stop to break-even removes all risk of loss but also guarantees a profit.
Q18. A system with 60% win rate and average winner = average loser has positive expectancy.
Q19. Scaling out always produces more total profit than holding the full position to the final target.
Q20. A structure stop below a swing low is generally more logical than an arbitrary fixed-percentage stop because it respects market context.
Answer keyMark scheme & solutions
Section A (10 marks)
Q1 — (c) 1:2. Why: The standard minimum RR ensures the reward is at least twice the risk, so a sub-50% win rate can still be profitable. (1)
Q2 — (b) A multiple of the Average True Range. Why: ATR measures volatility; the stop adapts to current market movement (e.g. 2×ATR). (1)
Q3 — (b) The initial risk (entry − stop) per unit. Why: R normalises trades so outcomes are measured in multiples of the risk taken. (1)
Q4 — (b) The entry price. Why: At break-even, if stopped out the loss is zero (excluding costs). (1)
Q5 — (c) Closing part of the position while letting the rest run. Why: Scaling out books partial profit and reduces exposure. (1)
Q6 — (b) Remove ambiguity and act consistently. Why: Defined rules produce repeatable, testable behaviour. (1)
Q7 — (b) The average R per trade over many trades. Why: Expectancy = (Win% × AvgWin) − (Loss% × AvgLoss). (1)
Q8 — (b) Beyond a swing high/low or S/R level. Why: Structure stops invalidate the trade thesis when key levels break. (1)
Q9 — (b) It limits losses to planned risk and preserves capital. Why: Small controlled losses keep the account able to recover. (1)
Q10 — (a) Lock in profits while giving room to run. Why: Trailing stops follow price to protect open gains. (1)
Section B (5 marks)
Q11 → C (Fixed stop = fixed % / point distance) Q12 → A (ATR stop = X × ATR) Q13 → B (Scaling in = adding in stages) Q14 → E (Confirmation = second validating signal) Q15 → D (Profit booking = exit reducing risk) 1 mark each; all-or-nothing per line.
Section C (10 marks)
Q16 — TRUE (1). Justification (1): Expectancy = (0.40 × 3R) − (0.60 × 1R) = 1.2R − 0.6R = +0.6R per trade > 0, so profitable long-term.
Q17 — FALSE (1). Justification (1): Break-even removes downside loss risk but does not guarantee profit — price can hit the break-even stop and exit at zero gain (or a small cost-related loss).
Q18 — TRUE (1). Justification (1): Expectancy = (0.60 × 1R) − (0.40 × 1R) = 0.6R − 0.4R = +0.2R > 0, positive.
Q19 — FALSE (1). Justification (1): If a big winner runs to full target, holding the full position yields more than a partially-exited one. Scaling out reduces variance/drawdown but not necessarily maximises total profit.
Q20 — TRUE (1). Justification (1): A structure stop is placed where the trade idea is invalidated (below support), respecting price action, whereas a fixed % is arbitrary relative to volatility/structure.
[
{"claim":"Q16: 40% win at 1:3 RR gives +0.6R expectancy","code":"E = 0.40*3 - 0.60*1; result = (E == Rational(6,10))"},
{"claim":"Q18: 60% win, 1R:1R gives +0.2R expectancy","code":"E = 0.60*1 - 0.40*1; result = (E == Rational(2,10))"},
{"claim":"Q1: minimum RR 1:2 means reward is twice risk","code":"risk=1; reward=2; result = (reward == 2*risk)"},
{"claim":"Total marks sum to 30","code":"secA=10; secB=5; secC=5*2; result = (secA+secB+secC == 30)"}
]