Level 1 — RecognitionThermodynamics & Statistical Mechanics (Advanced)

Thermodynamics & Statistical Mechanics (Advanced)

20 minutes30 marksprintable — key stays hidden on paper

Level 1 — Recognition Test

Time Limit: 20 minutes Total Marks: 30


Section A — Multiple Choice (1 mark each)

Choose the single best answer.

Q1. The Helmholtz free energy is defined as: (a) F=U+PVF = U + PV (b) F=UTSF = U - TS (c) F=HTSF = H - TS (d) F=U+TSF = U + TS

Q2. The natural variables of the Gibbs free energy GG are: (a) (S,V)(S, V) (b) (S,P)(S, P) (c) (T,V)(T, V) (d) (T,P)(T, P)

Q3. Boltzmann's entropy formula is: (a) S=kBΩS = k_B \Omega (b) S=kBlnΩS = k_B \ln \Omega (c) S=ln(kBΩ)S = \ln(k_B \Omega) (d) S=kB/lnΩS = k_B / \ln \Omega

Q4. In the canonical ensemble, the probability of a microstate with energy EiE_i is proportional to: (a) EiE_i (b) e+βEie^{+\beta E_i} (c) eβEie^{-\beta E_i} (d) 1/Ei1/E_i

Q5. The Clausius–Clapeyron equation describes: (a) the slope of a coexistence curve dP/dTdP/dT (b) the heat capacity ratio (c) partition function scaling (d) Fermi energy

Q6. The equipartition theorem assigns to each quadratic degree of freedom an average energy of: (a) kBTk_B T (b) 32kBT\tfrac{3}{2}k_B T (c) 12kBT\tfrac{1}{2}k_B T (d) 12kBT2\tfrac{1}{2}k_B T^2

Q7. Fermi–Dirac statistics apply to particles that: (a) are bosons (b) obey the Pauli exclusion principle (c) are distinguishable (d) have integer spin

Q8. The Gibbs phase rule is: (a) F=CP+2F = C - P + 2 (b) F=C+P2F = C + P - 2 (c) F=PC+2F = P - C + 2 (d) F=CP2F = C - P - 2

Q9. The average energy in the canonical ensemble is obtained from ZZ via: (a) E=lnZ/β\langle E\rangle = \partial \ln Z/\partial \beta (b) E=lnZ/β\langle E\rangle = -\partial \ln Z/\partial \beta (c) E=kBTlnZ\langle E\rangle = k_B T \ln Z (d) E=Z2\langle E\rangle = Z^2

Q10. The chemical potential is defined as: (a) μ=(G/N)T,P\mu = (\partial G/\partial N)_{T,P} (b) μ=(G/T)N,P\mu = (\partial G/\partial T)_{N,P} (c) μ=(U/S)V,N\mu = (\partial U/\partial S)_{V,N} (d) μ=(F/V)T,N\mu = (\partial F/\partial V)_{T,N}

Q11. The Helmholtz free energy is related to the partition function by: (a) F=kBTlnZF = k_B T \ln Z (b) F=kBTlnZF = -k_B T \ln Z (c) F=lnZF = -\ln Z (d) F=kBT/ZF = k_B T / Z

Q12. Bose–Einstein condensation is the macroscopic occupation of: (a) the highest energy state (b) the single lowest-energy quantum state (c) all states equally (d) the Fermi level


Section B — Matching (2 marks each)

Q13. Match each thermodynamic potential to its natural variables:

Potential Natural Variables
(i) UU (A) (T,P)(T,P)
(ii) HH (B) (S,V)(S,V)
(iii) FF (C) (T,V)(T,V)
(iv) GG (D) (S,P)(S,P)

Q14. Match each distribution/statistics to its feature:

Statistics Feature
(i) Maxwell–Boltzmann (A) n=1/(eβ(ϵμ)+1)\langle n\rangle = 1/(e^{\beta(\epsilon-\mu)}+1)
(ii) Bose–Einstein (B) distinguishable classical particles
(iii) Fermi–Dirac (C) Planck blackbody spectrum
(iv) Photon gas (D) n=1/(eβ(ϵμ)1)\langle n\rangle = 1/(e^{\beta(\epsilon-\mu)}-1)

Section C — True/False WITH Justification (2 marks each: 1 verdict + 1 justification)

Q15. "A Maxwell relation (TV)S=(PS)V\left(\frac{\partial T}{\partial V}\right)_S = -\left(\frac{\partial P}{\partial S}\right)_V can be derived from the internal energy U(S,V)U(S,V)." True or False? Justify.

Q16. "In an isolated system, the equilibrium macrostate corresponds to the smallest number of microstates Ω\Omega." True or False? Justify.

Q17. "The Legendre transform H=U+PVH = U + PV replaces the natural variable VV by PP." True or False? Justify.

Q18. "The Gibbs–Helmholtz equation is ((G/T)T)P=HT2\left(\frac{\partial (G/T)}{\partial T}\right)_P = -\frac{H}{T^2}." True or False? Justify.

Q19. "For a system in contact with a heat and particle reservoir, fermions can occupy the same quantum state without restriction." True or False? Justify.


Answer keyMark scheme & solutions

Section A (1 mark each)

Q1 — (b) F=UTSF = U - TS. Helmholtz free energy Legendre-transforms UU in SS. (1)

Q2 — (d) (T,P)(T,P). dG=SdT+VdPdG = -S\,dT + V\,dP, so G=G(T,P)G=G(T,P). (1)

Q3 — (b) S=kBlnΩS = k_B \ln \Omega. Entropy grows as the logarithm of the multiplicity. (1)

Q4 — (c) eβEie^{-\beta E_i}. Boltzmann factor; higher energy → lower probability. (1)

Q5 — (a) slope dP/dTdP/dT of a phase-coexistence curve. (1)

Q6 — (c) 12kBT\tfrac{1}{2}k_B T per quadratic degree of freedom. (1)

Q7 — (b) Pauli exclusion (half-integer spin fermions). (1)

Q8 — (a) F=CP+2F = C - P + 2. (1)

Q9 — (b) E=lnZ/β\langle E\rangle = -\partial \ln Z/\partial \beta. Sign from eβEe^{-\beta E}. (1)

Q10 — (a) μ=(G/N)T,P\mu = (\partial G/\partial N)_{T,P}. (1)

Q11 — (b) F=kBTlnZF = -k_B T \ln Z. (1)

Q12 — (b) macroscopic occupation of the single lowest-energy quantum state. (1)


Section B (2 marks each)

Q13. (i)→(B), (ii)→(D), (iii)→(C), (iv)→(A). Reason: dU=TdSPdV(S,V)dU=TdS-PdV\Rightarrow(S,V); dH=TdS+VdP(S,P)dH=TdS+VdP\Rightarrow(S,P); dF=SdTPdV(T,V)dF=-SdT-PdV\Rightarrow(T,V); dG=SdT+VdP(T,P)dG=-SdT+VdP\Rightarrow(T,P). All four correct = 2; two–three correct = 1; else 0. (2)

Q14. (i)→(B), (ii)→(D), (iii)→(A), (iv)→(C). MB = distinguishable classical; BE has 1-1 in denominator; FD has +1+1; photons give Planck spectrum. All four correct = 2; two–three correct = 1; else 0. (2)


Section C (2 marks each: verdict 1 + justification 1)

Q15 — TRUE. (verdict 1) From dU=TdSPdVdU=TdS-PdV: T=(U/S)VT=(\partial U/\partial S)_V, P=(U/V)S-P=(\partial U/\partial V)_S. Equality of mixed second partials 2U/VS=2U/SV\partial^2 U/\partial V\partial S=\partial^2 U/\partial S\partial V gives (T/V)S=(P/S)V(\partial T/\partial V)_S=-(\partial P/\partial S)_V. (justification 1)

Q16 — FALSE. (verdict 1) Since S=kBlnΩS=k_B\ln\Omega and the second law maximizes entropy, equilibrium corresponds to the largest Ω\Omega, not the smallest. (justification 1)

Q17 — TRUE. (verdict 1) H=U+PVH=U+PV is the Legendre transform of U(S,V)U(S,V) with respect to VV; since P=(U/V)SP=-(\partial U/\partial V)_S, adding PVPV swaps the conjugate pair so H=H(S,P)H=H(S,P), replacing VV by PP. (justification 1)

Q18 — TRUE. (verdict 1) Using G=HTSG=H-TS and S=(G/T)PS=-(\partial G/\partial T)_P: ((G/T)/T)P=1T(G/T)PGT2=STGT2=TSGT2=HT2\big(\partial(G/T)/\partial T\big)_P=\frac{1}{T}(\partial G/\partial T)_P-\frac{G}{T^2}=\frac{-S}{T}-\frac{G}{T^2}=\frac{-TS-G}{T^2}=\frac{-H}{T^2} (since G+TS=HG+TS=H). (justification 1)

Q19 — FALSE. (verdict 1) Fermions obey the Pauli exclusion principle; each quantum state holds at most one fermion, reflected in the FD occupation n=1/(eβ(ϵμ)+1)1\langle n\rangle=1/(e^{\beta(\epsilon-\mu)}+1)\le 1. (justification 1)


[
  {"claim":"F = U - TS is the Helmholtz definition; check dF = -S dT - P dV structure gives natural vars (T,V)",
   "code":"S,T,U,V,P,Fsym=symbols('S T U V P F'); F=U-T*S; dF=diff(F,T); result=(dF== -S)"},
  {"claim":"Gibbs-Helmholtz: d/dT (G/T) = -H/T**2 with G=H-T*S and S=-dG/dT",
   "code":"T=symbols('T',positive=True); G=Function('G'); H,S=symbols('H S'); Gt=G(T); expr=diff(Gt/T,T); sub=expr.subs(diff(Gt,T),-S); target=(-(Gt+T*S)/T**2); result=simplify(sub-target)==0"},
  {"claim":"Average energy = -d(lnZ)/dbeta for Z=exp(-beta*E) two-level model gives Boltzmann weighted energy",
   "code":"beta,E1,E2=symbols('beta E1 E2',positive=True); Z=exp(-beta*E1)+exp(-beta*E2); Eavg=-diff(ln(Z),beta); check=(E1*exp(-beta*E1)+E2*exp(-beta*E2))/Z; result=simplify(Eavg-check)==0"},
  {"claim":"Gibbs phase rule F=C-P+2 gives F=2 for single component single phase",
   "code":"C,P=1,1; Fphase=C-P+2; result=(Fphase==2)"}
]