Level 1 — RecognitionOrdinary Differential Equations

Ordinary Differential Equations

20 minutes30 marksprintable — key stays hidden on paper

Level: 1 — Recognition (MCQ + Matching + True/False with justification) Time Limit: 20 minutes Total Marks: 30


Section A — Multiple Choice (1 mark each) [10 marks]

Choose the single best answer.

Q1. The order and degree of the ODE (d2ydx2)3+(dydx)5+y=0\left(\dfrac{d^2y}{dx^2}\right)^3 + \left(\dfrac{dy}{dx}\right)^5 + y = 0 are: (a) 3 and 2 (b) 2 and 3 (c) 2 and 5 (d) 3 and 5

Q2. Which of the following equations is linear? (a) y+y2=xy' + y^2 = x (b) yy=xyy' = x (c) y+xy=sinxy' + xy = \sin x (d) y+cosy=0y' + \cos y = 0

Q3. The integrating factor of dydx+2xy=x\dfrac{dy}{dx} + 2xy = x is: (a) ex2e^{x^2} (b) e2xe^{2x} (c) x2x^2 (d) ex2/2e^{x^2/2}

Q4. The characteristic equation of y5y+6y=0y'' - 5y' + 6y = 0 has roots: (a) 2,32, 3 (b) 2,3-2, -3 (c) 1,61, 6 (d) 1,6-1, -6

Q5. The general solution of y+4y=0y'' + 4y = 0 is: (a) c1e2x+c2e2xc_1 e^{2x} + c_2 e^{-2x} (b) c1cos2x+c2sin2xc_1\cos 2x + c_2\sin 2x (c) (c1+c2x)e2x(c_1 + c_2 x)e^{2x} (d) c1e2xcosxc_1 e^{2x}\cos x

Q6. The Laplace transform L{eat}\mathcal{L}\{e^{at}\} (for s>as>a) equals: (a) 1s+a\dfrac{1}{s+a} (b) 1sa\dfrac{1}{s-a} (c) as2+a2\dfrac{a}{s^2+a^2} (d) ss2a2\dfrac{s}{s^2-a^2}

Q7. The equation Mdx+Ndy=0M\,dx + N\,dy = 0 is exact if and only if: (a) Mx=NyM_x = N_y (b) My=NxM_y = N_x (c) My=NxM_y = -N_x (d) MN=1MN = 1

Q8. A Bernoulli equation y+P(x)y=Q(x)yny' + P(x)y = Q(x)y^n is reduced to linear form by the substitution: (a) v=ynv = y^n (b) v=y1nv = y^{1-n} (c) v=eyv = e^y (d) v=lnyv = \ln y

Q9. For the linear system x=Ax\mathbf{x}' = A\mathbf{x}, if the eigenvalues of AA are complex with positive real part, the critical point at the origin is a: (a) stable spiral (b) unstable spiral (c) centre (d) saddle

Q10. The Cauchy–Euler equation x2y+axy+by=0x^2 y'' + a x y' + b y = 0 is solved by trying: (a) y=emxy = e^{mx} (b) y=xmy = x^m (c) y=sinmxy = \sin mx (d) y=mxy = m^x


Section B — Matching (1 mark each) [8 marks]

Match each item in Column X with the correct entry in Column Y.

# Column X Column Y
Q11 L{sinat}\mathcal{L}\{\sin at\} P ss2+a2\dfrac{s}{s^2+a^2}
Q12 L{cosat}\mathcal{L}\{\cos at\} Q n!sn+1\dfrac{n!}{s^{n+1}}
Q13 L{tn}\mathcal{L}\{t^n\} R as2+a2\dfrac{a}{s^2+a^2}
Q14 L{1}\mathcal{L}\{1\} S 1s\dfrac{1}{s}
# Column X (equation) Column Y (name/type)
Q15 (1x2)y2xy+n(n+1)y=0(1-x^2)y'' - 2xy' + n(n+1)y = 0 P Bessel's equation
Q16 x2y+xy+(x2ν2)y=0x^2y'' + xy' + (x^2-\nu^2)y = 0 Q Separable equation
Q17 dydx=g(x)h(y)\dfrac{dy}{dx} = g(x)h(y) R Legendre's equation
Q18 L{fg}\mathcal{L}\{f * g\} S F(s)G(s)F(s)G(s)

Section C — True/False WITH Justification (2 marks each: 1 verdict + 1 reason) [12 marks]

Q19. An autonomous ODE is one in which the independent variable does not appear explicitly. (T/F + justify)

Q20. The Picard–Lindelöf theorem guarantees a unique solution provided f(x,y)f(x,y) is merely continuous. (T/F + justify)

Q21. If y1y_1 and y2y_2 are solutions of a homogeneous linear ODE, then c1y1+c2y2c_1y_1 + c_2y_2 is also a solution. (T/F + justify)

Q22. The second shift (Heaviside) theorem states L{u(ta)f(ta)}=easF(s)\mathcal{L}\{u(t-a)f(t-a)\} = e^{-as}F(s). (T/F + justify)

Q23. The Dirac delta function δ(t)\delta(t) satisfies δ(t)dt=0\int_{-\infty}^{\infty}\delta(t)\,dt = 0. (T/F + justify)

Q24. For a repeated characteristic root mm, the second independent solution is xemxx e^{mx}. (T/F + justify)


Answer keyMark scheme & solutions

Section A (1 mark each)

Q1 — (b) 2 and 3. Highest derivative is d2y/dx2d^2y/dx^2 → order 2. Its highest power (after clearing radicals; none here) is 3 → degree 3.

Q2 — (c) y+xy=sinxy' + xy = \sin x. Linear means yy and its derivatives appear to first power, no products/nonlinear functions. (a) has y2y^2, (b) has yyyy', (d) has cosy\cos y — all nonlinear.

Q3 — (a) ex2e^{x^2}. IF =e2xdx=ex2= e^{\int 2x\,dx} = e^{x^2}.

Q4 — (a) 2,32,3. m25m+6=(m2)(m3)=0m^2 - 5m + 6 = (m-2)(m-3)=0.

Q5 — (b) c1cos2x+c2sin2xc_1\cos 2x + c_2\sin 2x. Roots m=±2im=\pm 2i ⇒ oscillatory solution with ω=2\omega=2.

Q6 — (b) 1sa\dfrac{1}{s-a}. 0e(sa)tdt=1/(sa)\int_0^\infty e^{-(s-a)t}dt = 1/(s-a), s>as>a.

Q7 — (b) My=NxM_y = N_x. Exactness condition (equality of mixed partials of the potential).

Q8 — (b) v=y1nv = y^{1-n}. Standard Bernoulli substitution linearizes the equation.

Q9 — (b) unstable spiral. Complex eigenvalues ⇒ spiral; positive real part ⇒ trajectories spiral outward ⇒ unstable.

Q10 — (b) y=xmy = x^m. Equidimensional form; substituting gives an indicial (auxiliary) equation in mm.

Section B (1 mark each)

  • Q11 → R   as2+a2\;\dfrac{a}{s^2+a^2}
  • Q12 → P   ss2+a2\;\dfrac{s}{s^2+a^2}
  • Q13 → Q   n!sn+1\;\dfrac{n!}{s^{n+1}}
  • Q14 → S   1s\;\dfrac{1}{s}
  • Q15 → R Legendre's equation
  • Q16 → P Bessel's equation
  • Q17 → Q Separable equation
  • Q18 → S F(s)G(s)F(s)G(s) (convolution theorem)

Section C (2 marks each: 1 verdict + 1 justification)

Q19 — TRUE. Autonomous: y=f(y)y' = f(y); the independent variable xx (or tt) does not appear explicitly on the RHS. (+1 verdict, +1 reason)

Q20 — FALSE. Continuity of ff gives existence (Peano) but uniqueness requires ff to also be Lipschitz in yy (or f/y\partial f/\partial y continuous). (+1/+1)

Q21 — TRUE. By the superposition principle, linear combinations of solutions to a homogeneous linear ODE are solutions (linearity of the operator LL: L[c1y1+c2y2]=c1L[y1]+c2L[y2]=0L[c_1y_1+c_2y_2]=c_1L[y_1]+c_2L[y_2]=0). (+1/+1)

Q22 — TRUE. Second shift theorem: L{u(ta)f(ta)}=easF(s)\mathcal{L}\{u(t-a)f(t-a)\}=e^{-as}F(s) for a0a\ge0, derived by substitution τ=ta\tau=t-a in the transform integral. (+1/+1)

Q23 — FALSE. δ(t)dt=1\int_{-\infty}^{\infty}\delta(t)\,dt = 1 (unit impulse), not 00. (+1/+1)

Q24 — TRUE. For repeated root mm, reduction of order yields the second solution xemxxe^{mx}; general solution (c1+c2x)emx(c_1+c_2x)e^{mx}. (+1/+1)

[
  {"claim":"Q4 roots of m^2-5m+6 are 2 and 3","code":"m=symbols('m'); sol=solve(m**2-5*m+6,m); result=(set(sol)=={2,3})"},
  {"claim":"Q3 integrating factor exp(integral 2x)=exp(x^2)","code":"x=symbols('x'); IF=exp(integrate(2*x,x)); result=(simplify(IF-exp(x**2))==0)"},
  {"claim":"Q6 Laplace of e^{at} is 1/(s-a)","code":"t,s,a=symbols('t s a',positive=True); F=integrate(exp(a*t)*exp(-s*t),(t,0,oo)); result=(simplify(F-1/(s-a))==0)"},
  {"claim":"Q5 y=c1 cos2x+c2 sin2x solves y''+4y=0","code":"x,c1,c2=symbols('x c1 c2'); y=c1*cos(2*x)+c2*sin(2*x); result=(simplify(diff(y,x,2)+4*y)==0)"}
]