Ordinary Differential Equations
Level: 1 — Recognition (MCQ + Matching + True/False with justification) Time Limit: 20 minutes Total Marks: 30
Section A — Multiple Choice (1 mark each) [10 marks]
Choose the single best answer.
Q1. The order and degree of the ODE are: (a) 3 and 2 (b) 2 and 3 (c) 2 and 5 (d) 3 and 5
Q2. Which of the following equations is linear? (a) (b) (c) (d)
Q3. The integrating factor of is: (a) (b) (c) (d)
Q4. The characteristic equation of has roots: (a) (b) (c) (d)
Q5. The general solution of is: (a) (b) (c) (d)
Q6. The Laplace transform (for ) equals: (a) (b) (c) (d)
Q7. The equation is exact if and only if: (a) (b) (c) (d)
Q8. A Bernoulli equation is reduced to linear form by the substitution: (a) (b) (c) (d)
Q9. For the linear system , if the eigenvalues of are complex with positive real part, the critical point at the origin is a: (a) stable spiral (b) unstable spiral (c) centre (d) saddle
Q10. The Cauchy–Euler equation is solved by trying: (a) (b) (c) (d)
Section B — Matching (1 mark each) [8 marks]
Match each item in Column X with the correct entry in Column Y.
| # | Column X | Column Y | |
|---|---|---|---|
| Q11 | P | ||
| Q12 | Q | ||
| Q13 | R | ||
| Q14 | S |
| # | Column X (equation) | Column Y (name/type) | |
|---|---|---|---|
| Q15 | P | Bessel's equation | |
| Q16 | Q | Separable equation | |
| Q17 | R | Legendre's equation | |
| Q18 | S |
Section C — True/False WITH Justification (2 marks each: 1 verdict + 1 reason) [12 marks]
Q19. An autonomous ODE is one in which the independent variable does not appear explicitly. (T/F + justify)
Q20. The Picard–Lindelöf theorem guarantees a unique solution provided is merely continuous. (T/F + justify)
Q21. If and are solutions of a homogeneous linear ODE, then is also a solution. (T/F + justify)
Q22. The second shift (Heaviside) theorem states . (T/F + justify)
Q23. The Dirac delta function satisfies . (T/F + justify)
Q24. For a repeated characteristic root , the second independent solution is . (T/F + justify)
Answer keyMark scheme & solutions
Section A (1 mark each)
Q1 — (b) 2 and 3. Highest derivative is → order 2. Its highest power (after clearing radicals; none here) is 3 → degree 3.
Q2 — (c) . Linear means and its derivatives appear to first power, no products/nonlinear functions. (a) has , (b) has , (d) has — all nonlinear.
Q3 — (a) . IF .
Q4 — (a) . .
Q5 — (b) . Roots ⇒ oscillatory solution with .
Q6 — (b) . , .
Q7 — (b) . Exactness condition (equality of mixed partials of the potential).
Q8 — (b) . Standard Bernoulli substitution linearizes the equation.
Q9 — (b) unstable spiral. Complex eigenvalues ⇒ spiral; positive real part ⇒ trajectories spiral outward ⇒ unstable.
Q10 — (b) . Equidimensional form; substituting gives an indicial (auxiliary) equation in .
Section B (1 mark each)
- Q11 → R
- Q12 → P
- Q13 → Q
- Q14 → S
- Q15 → R Legendre's equation
- Q16 → P Bessel's equation
- Q17 → Q Separable equation
- Q18 → S (convolution theorem)
Section C (2 marks each: 1 verdict + 1 justification)
Q19 — TRUE. Autonomous: ; the independent variable (or ) does not appear explicitly on the RHS. (+1 verdict, +1 reason)
Q20 — FALSE. Continuity of gives existence (Peano) but uniqueness requires to also be Lipschitz in (or continuous). (+1/+1)
Q21 — TRUE. By the superposition principle, linear combinations of solutions to a homogeneous linear ODE are solutions (linearity of the operator : ). (+1/+1)
Q22 — TRUE. Second shift theorem: for , derived by substitution in the transform integral. (+1/+1)
Q23 — FALSE. (unit impulse), not . (+1/+1)
Q24 — TRUE. For repeated root , reduction of order yields the second solution ; general solution . (+1/+1)
[
{"claim":"Q4 roots of m^2-5m+6 are 2 and 3","code":"m=symbols('m'); sol=solve(m**2-5*m+6,m); result=(set(sol)=={2,3})"},
{"claim":"Q3 integrating factor exp(integral 2x)=exp(x^2)","code":"x=symbols('x'); IF=exp(integrate(2*x,x)); result=(simplify(IF-exp(x**2))==0)"},
{"claim":"Q6 Laplace of e^{at} is 1/(s-a)","code":"t,s,a=symbols('t s a',positive=True); F=integrate(exp(a*t)*exp(-s*t),(t,0,oo)); result=(simplify(F-1/(s-a))==0)"},
{"claim":"Q5 y=c1 cos2x+c2 sin2x solves y''+4y=0","code":"x,c1,c2=symbols('x c1 c2'); y=c1*cos(2*x)+c2*sin(2*x); result=(simplify(diff(y,x,2)+4*y)==0)"}
]