Complex Numbers
Chapter: 3.5 Complex Numbers Level: 1 — Recognition (MCQ, Matching, True/False with justification) Time limit: 20 minutes Total marks: 30
Section A — Multiple Choice (1 mark each) — 10 marks
Q1. The value of is: (a) (b) (c) (d)
Q2. The real and imaginary parts of are: (a) (b) (c) (d)
Q3. The modulus of is: (a) (b) (c) (d)
Q4. The complex conjugate of is: (a) (b) (c) (d)
Q5. Euler's formula states that equals: (a) (b) (c) (d)
Q6. In the Argand plane, the number lies on: (a) the positive real axis (b) the negative imaginary axis (c) the positive imaginary axis (d) the origin
Q7. De Moivre's theorem gives equal to: (a) (b) (c) (d)
Q8. The number of distinct th roots of a non-zero complex number is: (a) (b) (c) (d)
Q9. The product equals: (a) (b) (c) (d)
Q10. The polar (exponential) form of a complex number with modulus and argument is: (a) (b) (c) (d)
Section B — Matching (1 mark each) — 5 marks
Q11. Match each expression in Column X with its value in Column Y.
| Column X | Column Y | |
|---|---|---|
| (i) | (P) | |
| (ii) | (Q) | |
| (iii) | (R) | |
| (iv) | (S) | |
| (v) | (T) |
Write the matches, e.g. (i)–(?).
Section C — True/False WITH justification (2 marks each: 1 verdict + 1 reason) — 15 marks
Q12. The sum of a complex number and its conjugate is always real.
Q13. for all complex numbers.
Q14. The three cube roots of unity are equally spaced on the unit circle at angles apart.
Q15. The equation has no solutions in the complex number system.
Q16. For , the argument is .
Q17. Dividing complex numbers is carried out by multiplying numerator and denominator by the conjugate of the denominator.
Q18. The sum of all th roots of unity is equal to .
Answer keyMark scheme & solutions
Section A (1 mark each)
Q1 — (d) . Powers of cycle with period 4. , so . (Reduce exponent mod 4.)
Q2 — (b) . For , real part , imaginary part (the coefficient of , including its sign).
Q3 — (a) . .
Q4 — (b) . Conjugate flips the sign of the imaginary part only.
Q5 — (c) . Direct statement of Euler's formula.
Q6 — (b) negative imaginary axis. Real part , imaginary part , so it sits on the imaginary axis below the origin.
Q7 — (a) . Statement of De Moivre's theorem.
Q8 — (d) . A non-zero complex number has exactly distinct th roots.
Q9 — (b) . (product of conjugates ).
Q10 — (b) . Exponential form of a complex number.
Section B
Q11 (1 mark each):
- (i) → (R)
- (ii) → (S) (or T, both give ; accept either)
- (iii) → (Q)
- (iv) → (P)
- (v) → (T) (or S)
Award full 5 marks if all values correct; accept the S/T ambiguity for .
Section C (1 mark verdict + 1 mark justification)
Q12 — TRUE. If , then , which is real (imaginary parts cancel).
Q13 — FALSE. The correct modulus rule is (product, not sum). Counter-example: gives but .
Q14 — TRUE. Cube roots of unity are , i.e. at — equally spaced apart on the unit circle.
Q15 — FALSE. ; complex numbers were introduced precisely to solve this. Two solutions exist.
Q16 — TRUE. lies in the first quadrant; .
Q17 — TRUE. Multiplying by the conjugate of the denominator makes the denominator real (), enabling division into form.
Q18 — FALSE. The sum of all th roots of unity is (for ), since they are roots of whose coefficient of is . (Only for is the sum .)
[
{"claim":"i^15 = -i","code":"result = (I**15 == -I)"},
{"claim":"|3+4i| = 5","code":"result = (Abs(3+4*I) == 5)"},
{"claim":"(2+3i)(2-3i) = 13","code":"result = (expand((2+3*I)*(2-3*I)) == 13)"},
{"claim":"sum of cube roots of unity is 0","code":"roots=[exp(2*pi*I*k/3) for k in range(3)]; result = (simplify(sum(roots))==0)"},
{"claim":"1/i = -i","code":"result = (simplify(1/I) == -I)"},
{"claim":"arg(1+i) = pi/4","code":"result = (arg(1+I) == pi/4)"}
]