Calculus III — Sequences & Series
Level 1 Paper — Recognition
Time limit: 20 minutes Total marks: 30
Section A — Multiple Choice (1 mark each)
Select the single best answer.
Q1. The sequence converges to: (a) (b) (c) (d)
Q2. The geometric series converges to: (a) (b) (c) (d) diverges
Q3. The -series converges if and only if: (a) (b) (c) (d)
Q4. By the Divergence Test, : (a) converges to (b) diverges (c) converges to (d) test is inconclusive
Q5. For the Ratio Test, the series converges absolutely if with: (a) (b) (c) (d) only
Q6. The Maclaurin series of is: (a) (b) (c) (d)
Q7. The radius of convergence of is: (a) (b) (c) (d)
Q8. The Alternating Series (Leibniz) Test requires the terms to be: (a) increasing and (b) positive, decreasing, and (c) bounded only (d)
Q9. A series that converges but whose absolute-value series diverges is called: (a) absolutely convergent (b) divergent (c) conditionally convergent (d) geometric
Q10. The telescoping series converges to: (a) (b) (c) (d) diverges
Section B — Matching (1 mark each, Q11 total 5 marks)
Q11. Match each series in Column A to its correct classification in Column B.
| Column A | Column B |
|---|---|
| (i) | (P) converges (geometric, $ |
| (ii) | (Q) diverges (-series, ) |
| (iii) | (R) converges (-series, ) |
| (iv) | (S) diverges (divergence test) |
| (v) | (T) conditionally convergent |
Section C — True/False WITH justification (2 marks each: 1 for T/F, 1 for reason)
Q12. Every bounded sequence converges. (T/F + justify)
Q13. If , then converges. (T/F + justify)
Q14. The Squeeze Theorem gives . (T/F + justify)
Q15. Absolute convergence implies convergence. (T/F + justify)
Q16. The Ratio Test with proves the series diverges. (T/F + justify)
Q17. The Maclaurin series of contains only even powers of . (T/F + justify)
Q18. A monotonic sequence that is bounded above must converge. (T/F + justify)
Answer keyMark scheme & solutions
Section A (1 mark each)
Q1 — (b) . Divide numerator and denominator by : . (1)
Q2 — (c) . Geometric with , : sum . (1)
Q3 — (a) . Standard -series result via integral test. (1)
Q4 — (b) diverges. ; divergence test. (1)
Q5 — (c) . Ratio test convergence condition. (1)
Q6 — (a) . Definition of Maclaurin series. (1)
Q7 — (b) . . (1)
Q8 — (b) positive, decreasing, . Leibniz conditions. (1)
Q9 — (c) conditionally convergent. By definition. (1)
Q10 — (b) . Partial sum . (1)
Section B
Q11 — (i)→(Q); (ii)→(R); (iii)→(T); (iv)→(P); (v)→(S). (1 each, 5 total) Reasoning: harmonic () diverges; converges; alternating harmonic converges but diverges ⇒ conditional; geometric converges; diverges.
Section C (2 marks each: 1 T/F, 1 reason)
Q12 — False. is bounded but oscillates and does not converge. (1+1)
Q13 — False. Necessary not sufficient: has yet diverges. (1+1)
Q14 — True. , both bounds , so squeeze gives . (1+1)
Q15 — True. If converges then converges (standard theorem). (1+1)
Q16 — False. is inconclusive; the test gives no information. (1+1)
Q17 — True. ; all exponents even. (1+1)
Q18 — True. Monotone Convergence Theorem: bounded + monotone ⇒ convergent. (1+1)
[
{"claim":"Q1 limit of (3n^2+1)/(2n^2+5) is 3/2","code":"n=symbols('n'); result = limit((3*n**2+1)/(2*n**2+5), n, oo) == Rational(3,2)"},
{"claim":"Q2 geometric sum sum_{n=0}^inf (2/3)^n = 3","code":"n=symbols('n'); result = summation(Rational(2,3)**n,(n,0,oo)) == 3"},
{"claim":"Q10 telescoping sum sum_{n=1}^inf (1/n-1/(n+1)) = 1","code":"n=symbols('n'); result = summation(1/n-1/(n+1),(n,1,oo)) == 1"},
{"claim":"Q14 squeeze limit sin(n)/n -> 0","code":"n=symbols('n'); result = limit(sin(n)/n, n, oo) == 0"}
]