Calculus I — Limits & Derivatives
Level 1 — Recognition Test
Time limit: 20 minutes Total marks: 30
Section A — Multiple Choice (1 mark each)
Choose the single best answer.
Q1. equals: (a) (b) (c) (d) undefined
Q2. The derivative of (power rule) is: (a) (b) (c) (d)
Q3. equals: (a) (b) (c) (d)
Q4. The derivative of is: (a) (b) (c) (d)
Q5. A function is continuous at if: (a) exists only (b) exists only (c) (d) is differentiable at
Q6. The derivative of is: (a) (b) (c) (d)
Q7. For , the line is a: (a) horizontal asymptote (b) vertical asymptote (c) removable discontinuity (d) inflection point
Q8. The derivative of is: (a) (b) (c) (d)
Q9. The product rule states (a) (b) (c) (d)
Q10. The difference quotient defining is: (a) (b) (c) (d)
Q11. The Intermediate Value Theorem requires the function to be: (a) differentiable (b) continuous on a closed interval (c) increasing (d) bounded
Q12. A jump discontinuity occurs when: (a) both one-sided limits exist but are unequal (b) the limit equals the value (c) the function is undefined everywhere (d) the derivative is infinite
Section B — Matching (1 mark each; total 6)
Q13. Match each function to its derivative:
| Function | Derivative | |
|---|---|---|
| (i) | (A) | |
| (ii) | (B) | |
| (iii) | (C) | |
| (iv) | (D) |
(4 marks — one per correct pair)
Q14. Match the theorem/rule to its statement (2 marks):
| Item | Statement | |
|---|---|---|
| (i) Rolle's Theorem | (P) for | |
| (ii) L'Hôpital's Rule | (Q) If , some has |
Section C — True/False WITH Justification (2 marks each; 1 T/F + 1 reason)
Q15. The Squeeze Theorem can be used to show . True/False — justify.
Q16. If exists, then is continuous at . True/False — justify.
Q17. The quotient rule gives . True/False — justify.
Q18. At a local maximum of a differentiable function, . True/False — justify.
Answer keyMark scheme & solutions
Section A (12 marks)
Q1. (b) — the fundamental trig limit. (1)
Q2. (a) — power rule. (1)
Q3. (c) — definition of . (1)
Q4. (a) — standard derivative. (1)
Q5. (c) — all three conditions (limit exists, value exists, equal) summarised by this equation. (1)
Q6. (b) — is its own derivative. (1)
Q7. (b) vertical asymptote — as , . (1)
Q8. (a) — derivative of natural log. (1)
Q9. (b) — product rule. (1)
Q10. (a) — first-principles difference quotient (limit as ). (1)
Q11. (b) continuous on a closed interval — IVT hypothesis. (1)
Q12. (a) both one-sided limits exist but are unequal — definition of jump discontinuity. (1)
Section B (6 marks)
Q13. (i)→(B), (ii)→(A), (iii)→(D), (iv)→(C). (1 each = 4)
- ; ; ; .
Q14. (i)→(Q), (ii)→(P). (1 each = 2)
Section C (8 marks)
Q15. True. (1) Since , we get . Both bounds as , so by the Squeeze Theorem the middle . (1)
Q16. False. (1) Existence of the limit is not enough — we also need defined and equal to the limit. E.g. a removable discontinuity has a limit but may differ or be undefined. (1)
Q17. True. (1) This is the correct quotient rule (numerator , denominator ), valid where . (1)
Q18. True. (1) By Fermat's theorem, at an interior local extremum of a differentiable function the tangent is horizontal, so (a necessary condition). (1)
[
{"claim":"limit sin(x)/x -> 1","code":"x=symbols('x'); result = (limit(sin(x)/x, x, 0)==1)"},
{"claim":"limit (1+1/x)**x -> e","code":"x=symbols('x'); result = (limit((1+1/x)**x, x, oo)==E)"},
{"claim":"derivative of tan(x) is sec(x)**2","code":"x=symbols('x'); result = simplify(diff(tan(x),x)-sec(x)**2)==0"},
{"claim":"squeeze: limit x**2 sin(1/x) -> 0","code":"x=symbols('x'); result = (limit(x**2*sin(1/x), x, 0)==0)"}
]