Physical Chemistry (Advanced)
Time limit: 20 minutes
Total marks: 30
Instructions: Answer all questions. For True/False items, a correct verdict without justification earns half marks. Use notation where relevant.
Section A — Multiple Choice (1 mark each)
Q1. For a particle in a 1-D box of length , the energy of level is:
- (a)
- (b)
- (c)
- (d)
Q2. The ground-state energy of the hydrogen atom is:
- (a) eV (b) eV (c) eV (d) eV
Q3. The variational principle guarantees that the trial energy satisfies:
- (a) (b) (c) (d) no relation to
Q4. In the Hartree–Fock method, the electron–electron interaction is treated via:
- (a) exact correlation (b) a mean (average) field (c) neglect entirely (d) classical point charges only
Q5. For a rigid rotor, the rotational energy levels are given by ( = rotational constant):
- (a) (b) (c) (d)
Q6. The vibrational energy levels of a harmonic oscillator are:
- (a) (b) (c) (d)
Q7. The Langmuir isotherm assumes:
- (a) multilayer adsorption (b) monolayer adsorption on equivalent sites (c) infinite adsorption energy (d) adsorbate–adsorbate attraction
Q8. The BET isotherm is used to describe:
- (a) monolayer only (b) multilayer adsorption / surface area determination (c) chemisorption only (d) liquid–liquid emulsions
Q9. The critical micelle concentration (CMC) is the concentration above which:
- (a) surfactant precipitates (b) micelles begin to form (c) surface tension increases sharply (d) emulsion breaks
Q10. At high overpotential, the Butler–Volmer equation reduces to the:
- (a) Nernst equation (b) Tafel equation (c) Langmuir equation (d) Arrhenius equation
Q11. The Stark–Einstein law states that:
- (a) one photon can excite many molecules (b) one absorbed photon activates one molecule (c) quantum yield is always 1 (d) light intensity equals rate
Q12. In a semiconductor, conductivity increases with temperature because:
- (a) the band gap widens (b) more electrons are promoted across the gap (c) phonon scattering decreases (d) the Fermi level vanishes
Section B — Matching (½ mark each, 4 marks total)
Q13. Match each partition function to its dominant physical origin.
| Column X | Column Y |
|---|---|
| (i) | (P) spacing of vibrational modes |
| (ii) | (Q) mass and box volume |
| (iii) | (R) degeneracy of ground electronic state |
| (iv) | (S) moment of inertia |
Q14. Match photophysical process to description.
| Column X | Column Y |
|---|---|
| (i) Fluorescence | (P) , spin-forbidden, long-lived |
| (ii) Phosphorescence | (Q) , spin-allowed, fast |
| (iii) Internal conversion | (R) non-radiative |
| (iv) Intersystem crossing | (S) , spin change |
Section C — True/False with Justification (2 marks each)
Q15. "The energy levels of a particle in a box are non-degenerate and increase in spacing as increases." — True or False? Justify.
Q16. "The Freundlich isotherm () predicts saturation of the surface at high pressure." — True or False? Justify.
Q17. "A quantum yield greater than 1 is impossible under any circumstances." — True or False? Justify.
Q18. "In the Morse potential, vibrational levels converge as increases and the molecule can dissociate." — True or False? Justify.
Q19. "A superconductor below its critical temperature expels magnetic flux (Meissner effect) and has zero DC resistance." — True or False? Justify.
Q20. "In density functional theory (DFT), the ground-state energy is a functional of the electron density ." — True or False? Justify.
Answer keyMark scheme & solutions
Section A (1 mark each)
Q1 — (a). From solving the Schrödinger equation with infinite walls, ; energy scales as . ✔
Q2 — (b) eV. eV; ground state gives eV. ✔
Q3 — (c) . Any trial wavefunction gives an expectation energy that is an upper bound to the true ground-state energy. ✔
Q4 — (b) mean field. Each electron feels the averaged field of all others; correlation beyond this is neglected. ✔
Q5 — (b) . Standard rigid-rotor result. ✔
Q6 — (b) . Equally spaced levels with zero-point energy . ✔
Q7 — (b) monolayer on equivalent sites. Langmuir assumes uniform sites, no lateral interactions, monolayer coverage. ✔
Q8 — (b) multilayer / surface area. BET extends Langmuir to multilayers; used for surface-area measurement. ✔
Q9 — (b) micelles begin to form. Above CMC surfactant aggregates into micelles; surface tension plateaus. ✔
Q10 — (b) Tafel. At large one exponential term dominates → linear vs . ✔
Q11 — (b) one photon activates one molecule. Primary photochemical act is 1:1. ✔
Q12 — (b) more electrons promoted across gap. Thermal excitation increases carrier concentration → intrinsic semiconductors more conductive when hot. ✔
Section B
Q13 (½ each): (i)–Q, (ii)–S, (iii)–P, (iv)–R.
Reasoning: depends on mass/volume; on moment of inertia ; on mode spacing ; on ground-state degeneracy.
Q14 (½ each): (i)–Q, (ii)–P, (iii)–R, (iv)–S.
Section C (verdict 1 + justification 1)
Q15 — TRUE. Levels are non-degenerate in 1-D; spacing grows with . (verdict 1, justification 1)
Q16 — FALSE. Freundlich is a power law with no plateau; keeps rising with , so it does not predict saturation (Langmuir does). (1+1)
Q17 — FALSE. In chain reactions (e.g. H₂+Cl₂), one photon can initiate a chain giving quantum yields ≫ 1. (1+1)
Q18 — TRUE. Morse anharmonicity makes levels converge ( decreases with ) toward the dissociation limit . (1+1)
Q19 — TRUE. Both zero DC resistance and Meissner flux expulsion are defining properties below . (1+1)
Q20 — TRUE. By the Hohenberg–Kohn theorem, ground-state energy is a unique functional of . (1+1)
[
{"claim":"PIB level spacing between n=2 and n=1 equals 3h^2/8mL^2 (coefficient 3)","code":"h,m,L,n=symbols('h m L n',positive=True); E=lambda k: k**2*h**2/(8*m*L**2); diff=simplify(E(2)-E(1)); coeff=simplify(diff/(h**2/(8*m*L**2))); result=(coeff==3)"},
{"claim":"Hydrogen ground state -13.6/n^2 gives -13.6 eV at n=1 and -3.4 at n=2","code":"n=symbols('n'); E=lambda k:-Rational(136,10)/k**2; result=(E(1)==Rational(-136,10)) and (E(2)==Rational(-34,10))"},
{"claim":"Harmonic oscillator spacing is constant (independent of v)","code":"h,nu,v=symbols('h nu v',positive=True); E=lambda k:h*nu*(k+Rational(1,2)); s1=simplify(E(v+1)-E(v)); s2=simplify(E(v+2)-E(v+1)); result=simplify(s1-s2)==0"},
{"claim":"Rigid rotor J=1 to J=0 gives energy 2hcB","code":"h,c,B,J=symbols('h c B J',positive=True); E=lambda k:h*c*B*k*(k+1); result=simplify(E(1)-E(0))==2*h*c*B"}
]