Combustion Chemistry (Propulsion Bridge)
Time limit: 20 minutes
Total marks: 30
Instructions: Answer all questions. For True/False items, a correct justification is required for full marks. Use notation where needed.
Section A — Multiple Choice (1 mark each) — 10 marks
Q1. For a stoichiometric mixture, the equivalence ratio equals:
- (a) (b) (c) (d)
Q2. A fuel-rich combustion mixture is characterized by:
- (a) excess oxidizer (b) excess fuel (c) exactly balanced reactants (d) no fuel
Q3. The adiabatic flame temperature is highest when the mixture is:
- (a) very fuel-lean (b) very fuel-rich (c) near stoichiometric (slightly rich) (d) inert-diluted
Q4. At high temperatures, dissociation reactions such as cause the actual flame temperature to be:
- (a) higher than the ideal value (b) lower than the ideal value (c) unchanged (d) infinite
Q5. A detonation differs from a deflagration primarily because it:
- (a) propagates subsonically (b) propagates supersonically via a shock wave (c) requires no fuel (d) has lower pressure
Q6. In a diffusion flame, fuel and oxidizer are:
- (a) premixed before combustion (b) mixed only at the reaction zone (c) never in contact (d) both inert
Q7. A common hypergolic propellant combination is:
- (a) + (b) RP-1 + LOX (c) + UDMH/MMH (d) methane + air
Q8. Vieille's law for solid propellant burn rate is written as:
- (a) (b) (c) (d)
Q9. In an AP/HTPB/Al composite solid propellant, HTPB acts as the:
- (a) oxidizer (b) metal fuel additive (c) polymeric binder/fuel (d) catalyst only
Q10. Thermal formation (Zeldovich mechanism) is favoured by:
- (a) low temperatures (b) high temperatures (c) absence of nitrogen (d) fuel-rich soot zones only
Section B — Matching (1 mark each) — 8 marks
Q11. Match Column A to Column B.
| Column A | Column B |
|---|---|
| (i) RP-1 | (P) Cryogenic gaseous fuel, no carbon |
| (ii) Hydrogen | (Q) Refined kerosene hydrocarbon |
| (iii) Ammonium perchlorate | (R) Solid oxidizer |
| (iv) Aluminium | (S) Metal fuel raising flame temperature |
Q12. Match the pollutant/species to its origin.
| Column A | Column B |
|---|---|
| (i) Soot | (P) High-T reaction of and |
| (ii) | (Q) Rich-zone carbon particulates |
| (iii) Unburned hydrocarbons | (R) Incomplete/quenched combustion |
| (iv) | (S) Product of dissociation at high T |
Section C — True/False with Justification (2 marks each) — 12 marks
(1 mark answer + 1 mark justification)
Q13. "The NASA-CEA tool computes equilibrium products, chamber temperature , and assuming chemical equilibrium." — True/False? Justify.
Q14. "A fuel-lean mixture always produces more soot than a fuel-rich mixture." — True/False? Justify.
Q15. "Ignition delay of a hypergolic propellant is the time between contact of fuel and oxidizer and the onset of combustion." — True/False? Justify.
Q16. "Premixed flames generally have a well-defined propagation (flame) speed, whereas diffusion flames are limited by mixing rate." — True/False? Justify.
Q17. "Increasing chamber pressure always decreases the burn rate of a solid propellant." — True/False? Justify.
Q18. "Chapman–Jouguet condition corresponds to the detonation wave moving at exactly sonic velocity relative to the burned gases behind it." — True/False? Justify.
Answer keyMark scheme & solutions
Section A (1 mark each)
Q1. (b) . Equivalence ratio is defined as actual fuel/oxidizer ratio divided by stoichiometric ratio; at stoichiometric it equals 1. ✔
Q2. (b) excess fuel. Fuel-rich means , more fuel than can be fully oxidized. ✔
Q3. (c) near stoichiometric (slightly rich). Maximum heat release per unit mixture with minimal excess diluent; peak often shifts slightly rich because dissociation and product speciation. ✔
Q4. (b) lower. Dissociation is endothermic; it absorbs energy, reducing the actual flame temperature below the ideal (no-dissociation) value. ✔
Q5. (b) supersonic via shock wave. Detonation couples a shock to the reaction zone and travels supersonically; deflagration is subsonic conduction/diffusion-driven. ✔
Q6. (b) mixed only at the reaction zone. In diffusion flames reactants meet by molecular diffusion at the flame surface. ✔
Q7. (c) + UDMH/MMH. Classic hypergolic pair igniting on contact without external ignition. ✔
Q8. (a) . Vieille's (Saint-Robert's) law; = temperature coefficient, = pressure exponent. ✔
Q9. (c) polymeric binder/fuel. HTPB (hydroxyl-terminated polybutadiene) binds the composite and serves as fuel. ✔
Q10. (b) high temperatures. Zeldovich thermal has high activation energy, so it rises steeply with temperature. ✔
Section B (1 mark each; award per correct pair)
Q11. (i)→Q, (ii)→P, (iii)→R, (iv)→S. RP-1 = kerosene; = cryogenic carbon-free fuel; AP = solid oxidizer; Al = metal fuel additive.
Q12. (i)→Q, (ii)→P, (iii)→R, (iv)→S. Soot from rich carbon particulates; from thermal ; UHC from quenched combustion; CO from dissociation / incomplete oxidation.
Section C (2 marks each: 1 answer + 1 justification)
Q13. True. CEA solves for equilibrium composition by minimizing Gibbs free energy and outputs , product mole fractions, and performance parameters including . (1+1)
Q14. False. Soot forms predominantly in fuel-rich zones where excess carbon lacks oxidizer; lean mixtures have excess oxygen and soot little. (1+1)
Q15. True. Ignition delay is exactly the interval from contact/mixing of hypergolic reactants to detectable combustion; short delay is desired for reliable ignition. (1+1)
Q16. True. A premixed flame has a characteristic laminar flame speed ; a diffusion flame's rate is governed by how fast fuel and oxidizer inter-diffuse/mix. (1+1)
Q17. False. Per Vieille's law with , burn rate increases with pressure. (1+1)
Q18. True. At the C–J point the detonation propagates such that the flow velocity of the products relative to the wave equals the local sound speed (Mach 1 in the burned gas frame); this is the stable steady-detonation condition. (1+1)
[
{"claim":"Vieille's law: at n>0, higher P gives higher r (Q17 False since claim says decrease)","code":"P1,P2,a,n=symbols('P1 P2 a n',positive=True); r1=a*P1**n; r2=a*P2**n; result = bool(simplify((r2-r1).subs({a:1,n:0.35,P1:5,P2:10}))>0)"},
{"claim":"Stoichiometric equivalence ratio equals 1 (Q1)","code":"phi=Rational(1,1); result = (phi==1)"},
{"claim":"Vieille exponent example: doubling pressure with n=0.4 multiplies burn rate by 2**0.4","code":"a,P,n=symbols('a P n',positive=True); ratio=(a*(2*P)**n)/(a*P**n); result = bool(simplify(ratio - 2**n).subs(n,Rational(2,5))==0)"}
]