Level 2 — RecallTaxonomy & Classification

Taxonomy & Classification

30 minutes40 marksprintable — key stays hidden on paper

Level 2 — Recall (definitions, standard textbook items, short reasoning) Time limit: 30 minutes Total marks: 40


Instructions: Answer all questions. Marks are shown in brackets. Write biological terms precisely; spelling of taxonomic names matters.


Q1. State two reasons why biologists classify living organisms. [2]

Q2. Define binomial nomenclature. Using the human species Homo sapiens as an example, state which word is the genus and which is the species (specific epithet). [3]

Q3. The taxonomic hierarchy runs from the broadest to the narrowest rank. Write the eight ranks in the correct order from domain down to species. [4]

Q4. Name the three domains in the three-domain system of classification. [3]

Q5. Copy and complete the table by giving one correct entry for each blank. [6]

Kingdom Cell type (pro/eukaryotic) Nutrition (auto/heterotrophic)
Plantae (a) (b)
Fungi (c) (d)
Animalia (e) (f)

Q6. State three features that distinguish domain Archaea from domain Bacteria. [3]

Q7. Give one distinguishing main feature for each of the following eukaryotic kingdoms: (a) Protista (b) Fungi (c) Plantae (d) Animalia. [4]

Q8. Explain what a dichotomous key is and state what the word "dichotomous" refers to about the choices at each step. [3]

Q9. Below is a simple dichotomous key for four organisms.

1a. Has feathers .......................... go to 2
1b. No feathers .......................... go to 3
2a. Cannot fly ........................... Ostrich
2b. Can fly .............................. Sparrow
3a. Has scales ........................... Snake
3b. No scales, has fur ................... Rabbit

Using the key, identify the organism that: has no feathers, no scales, and has fur. Show the steps you followed. [3]

Q10. Explain how molecular phylogenetics is used in classification, and name one type of molecule commonly compared between organisms. [3]

Q11. State the correct written conventions for a scientific name (give two rules). [3]


End of paper

Answer keyMark scheme & solutions

Q1. [2] — Any two (1 mark each):

  • To organise the huge diversity of life into manageable, ordered groups.
  • To show evolutionary relationships / common ancestry between organisms.
  • To allow a universal naming system so scientists worldwide communicate clearly.
  • To aid identification of organisms and prediction of shared characteristics.

Why: classification's purpose is order, communication and reflecting phylogeny.

Q2. [3]

  • Binomial nomenclature = a two-word naming system giving each species a unique scientific name consisting of genus + specific epithet (1).
  • Genus = Homo (1).
  • Species/specific epithet = sapiens (1).

Why: "binomial" = two names; genus first (capitalised), epithet second.

Q3. [4] — Correct order (deduct marks per error; full 4 for all eight correctly ordered): Domain → Kingdom → Phylum → Class → Order → Family → Genus → Species.

  • 4 marks all correct; 3 marks one slip; 2 marks two slips; etc.

Q4. [3] — 1 mark each: Archaea, Bacteria, Eukarya.

Q5. [6] — 1 mark each cell:

Kingdom Cell type Nutrition
Plantae (a) eukaryotic (b) autotrophic
Fungi (c) eukaryotic (d) heterotrophic
Animalia (e) eukaryotic (f) heterotrophic

Why: all three are eukaryotic; plants photosynthesise (auto), fungi absorb/animals ingest (hetero).

Q6. [3] — Any three (1 each):

  • Archaea have membrane lipids with branched (ether-linked) chains; Bacteria have unbranched (ester-linked) lipids.
  • Archaeal cell walls lack peptidoglycan; bacterial walls contain peptidoglycan.
  • Archaea often live in extreme environments (extremophiles); many bacteria in moderate conditions.
  • Differences in rRNA/gene sequences and some RNA-polymerase/histone features (Archaea share some traits with Eukarya).

Q7. [4] — 1 mark each:

  • (a) Protista: mostly unicellular eukaryotes (a diverse "catch-all" group).
  • (b) Fungi: eukaryotic, heterotrophic by absorption, cell walls of chitin.
  • (c) Plantae: multicellular, autotrophic (photosynthesis), cellulose cell walls.
  • (d) Animalia: multicellular, heterotrophic by ingestion, no cell walls.

Q8. [3]

  • A dichotomous key is an identification tool that leads the user through a series of paired statements about characteristics (1).
  • At each step you choose between two alternatives, directing you to the next step or a final identification (1).
  • "Dichotomous" means each step offers two (a pair of) contrasting choices (1).

Q9. [3]

  • Step 1: no feathers → 1b → go to 3 (1).
  • Step 2: no scales, has fur → 3b (1).
  • Identification: Rabbit (1).

Q10. [3]

  • Molecular phylogenetics compares sequences of molecules (DNA, RNA or proteins) between species (1).
  • The degree of similarity/difference in sequence indicates how closely related organisms are and how recently they shared a common ancestor — used to build phylogenetic trees and refine classification (1).
  • Example molecule: DNA / rRNA (ribosomal RNA) / a protein such as cytochrome c (1).

Q11. [3] — Any two rules (1½ each, or 1+1+1 for three):

  • Genus name capitalised, species name lowercase.
  • Both words italicised (or underlined when handwritten).
  • Genus written first; may be abbreviated to initial after first use (e.g. H. sapiens).

[
  {"claim":"Taxonomic hierarchy has 8 ranks from domain to species",
   "code":"ranks=['Domain','Kingdom','Phylum','Class','Order','Family','Genus','Species']; result=(len(ranks)==8 and ranks[0]=='Domain' and ranks[-1]=='Species')"},
  {"claim":"Three-domain system names Archaea, Bacteria, Eukarya",
   "code":"domains={'Archaea','Bacteria','Eukarya'}; result=(len(domains)==3)"},
  {"claim":"Q9 key path for no-feathers/no-scales/fur leads to Rabbit",
   "code":"feathers=False; scales=False; fur=True; step='1b' if not feathers else '1a'; ident='Rabbit' if (step=='1b' and not scales and fur) else None; result=(ident=='Rabbit')"},
  {"claim":"Q5 all three kingdoms are eukaryotic",
   "code":"cells={'Plantae':'eukaryotic','Fungi':'eukaryotic','Animalia':'eukaryotic'}; result=(all(v=='eukaryotic' for v in cells.values()))"}
]