Level 2 — RecallPopulation Genetics & Speciation

Population Genetics & Speciation

40 marksprintable — key stays hidden on paper

Level 2 — Recall (Definitions, Standard Problems, Short Derivations)

Time allowed: 30 minutes Total marks: 40


Question 1. (4 marks) State the Hardy-Weinberg principle. List four assumptions that must hold for a population to be in Hardy-Weinberg equilibrium.

Question 2. (4 marks) In a population, the recessive allele aa causes a condition with a frequency of 1 in 400 individuals showing the recessive phenotype (aaaa). (a) Calculate the frequency of allele aa. (2) (b) Calculate the frequency of the dominant allele AA and the frequency of heterozygous carriers (AaAa). (2)

Question 3. (4 marks) Define the following terms: (a) Genetic drift (2) (b) Gene flow (2)

Question 4. (4 marks) Distinguish between the bottleneck effect and the founder effect, giving one example of each.

Question 5. (4 marks) Explain the role of mutation in evolution. In your answer, state why mutation alone is usually a weak evolutionary force and why it is nonetheless essential.

Question 6. (4 marks) Define a species according to the biological species concept. State two limitations of this concept.

Question 7. (6 marks) Distinguish between allopatric and sympatric speciation. Give one mechanism and one example for each.

Question 8. (5 marks) Reproductive isolation mechanisms are classified as prezygotic or postzygotic. (a) Define prezygotic and postzygotic isolation. (2) (b) Classify each of the following as prezygotic or postzygotic: temporal isolation, hybrid sterility, mechanical isolation, hybrid inviability. (3)

Question 9. (5 marks) Compare gradualism and punctuated equilibrium as models of evolutionary change. Refer to rate of change and appearance in the fossil record.


End of paper

Answer keyMark scheme & solutions

Question 1. (4 marks)

  • Principle: In a large, randomly mating population that is not subject to evolutionary forces, allele and genotype frequencies remain constant from generation to generation. (2)
    • Frequencies follow p2+2pq+q2=1p^2 + 2pq + q^2 = 1, where p+q=1p+q=1.
  • Assumptions (any four, ½ each = 2): (1) No mutation; (2) No natural selection; (3) No gene flow/migration; (4) Random mating; (5) Very large (infinite) population — no genetic drift. Why: Each assumption prevents one force that would otherwise change allele frequencies.

Question 2. (4 marks) (a) q2=1400=0.0025q^2 = \frac{1}{400} = 0.0025, so q=0.0025=0.05q = \sqrt{0.0025} = 0.05. (2) (b) p=1q=10.05=0.95p = 1 - q = 1 - 0.05 = 0.95. (1) Heterozygotes 2pq=2(0.95)(0.05)=0.0952pq = 2(0.95)(0.05) = 0.095 (≈9.5%). (1) Why: aaaa genotype frequency equals q2q^2; the rest follows from p+q=1p+q=1 and the HW expansion.


Question 3. (4 marks) (a) Genetic drift: random change in allele frequencies from one generation to the next due to chance sampling of gametes, most pronounced in small populations. (2) (b) Gene flow: the transfer of alleles between populations through the movement (migration) of individuals or gametes, which tends to make populations genetically more similar. (2)


Question 4. (4 marks)

  • Bottleneck effect: a drastic reduction in population size (e.g. by disaster) leaves a small surviving group whose allele frequencies differ from the original by chance; reduces genetic diversity. Example: northern elephant seals / cheetahs. (2)
  • Founder effect: a new population is started by a few individuals carrying only a fraction (non-representative sample) of the parent population's alleles. Example: Amish population and high frequency of Ellis–van Creveld syndrome. (2) Why: Both are special cases of drift; distinction is cause (crash vs colonisation).

Question 5. (4 marks)

  • Mutation is the ultimate source of new alleles / genetic variation, providing the raw material on which selection and drift act. (2)
  • Weak alone: mutation rates are very low, so the change in allele frequency per generation is tiny. (1)
  • Essential: without mutation there would be no new variation to be selected or to arise; other forces only redistribute existing alleles. (1)

Question 6. (4 marks)

  • Biological species concept: a species is a group of actually or potentially interbreeding natural populations that produce fertile offspring and are reproductively isolated from other such groups. (2)
  • Limitations (any two, 1 each): cannot apply to asexual/self-fertilising organisms; cannot apply to fossils/extinct species; difficult where hybridisation occurs; hard to test "potentially interbreeding". (2)

Question 7. (6 marks)

Feature Allopatric Sympatric
Geography Populations physically/geographically separated Populations in the same area, no physical barrier
Mechanism Geographic barrier → reduced gene flow → divergence (1) e.g. polyploidy, disruptive selection, niche/host shift (1)
Example Darwin's finches / squirrels of Grand Canyon (1) Polyploid plants; apple maggot fly (1)

Award 2 for correct geographic distinction, 2 for mechanisms, 2 for examples.


Question 8. (5 marks) (a) Prezygotic: isolating mechanisms that prevent mating or fertilisation, so no zygote forms. Postzygotic: mechanisms acting after fertilisation, reducing viability or fertility of the hybrid. (2) (b) (½ each, rounded to 3):

  • Temporal isolation → prezygotic
  • Hybrid sterility → postzygotic
  • Mechanical isolation → prezygotic
  • Hybrid inviability → postzygotic (3)

Question 9. (5 marks)

  • Gradualism: evolution proceeds by slow, steady, continuous accumulation of small changes; predicts many transitional forms in the fossil record. (2)
  • Punctuated equilibrium: long periods of stasis (little change) interrupted by short bursts of rapid change, often at speciation; few transitional forms — sudden appearance in fossil record. (2)
  • Valid comparison of rate/fossil pattern for the final mark. (1)

[
  {"claim": "q = sqrt(1/400) = 0.05", "code": "q = sqrt(Rational(1,400)); result = (q == Rational(1,20))"},
  {"claim": "p = 1 - q = 0.95", "code": "q = Rational(1,20); p = 1 - q; result = (p == Rational(19,20))"},
  {"claim": "Heterozygote frequency 2pq = 0.095", "code": "q = Rational(1,20); p = 1 - q; result = (2*p*q == Rational(19,200))"},
  {"claim": "HW genotype frequencies sum to 1", "code": "q = Rational(1,20); p = 1 - q; result = (p**2 + 2*p*q + q**2 == 1)"}
]