Extensions of Mendelian Genetics
Level 1: Recognition Test
Time Limit: 20 minutes Total Marks: 30
Section A — Multiple Choice (1 mark each)
Choose the single best answer.
Q1. In a cross of red () × white () snapdragons, the F1 are all pink. This illustrates:
- A) Codominance
- B) Incomplete dominance
- C) Epistasis
- D) Pleiotropy
Q2. The ABO blood group system is a classic example of:
- A) Incomplete dominance only
- B) Codominance and multiple alleles
- C) Polygenic inheritance
- D) Sex linkage
Q3. A trait controlled by many genes, each with a small additive effect, producing a continuous range of phenotypes, is termed:
- A) Pleiotropic
- B) Epistatic
- C) Polygenic
- D) Codominant
Q4. A single gene affecting multiple, seemingly unrelated phenotypic traits describes:
- A) Epistasis
- B) Pleiotropy
- C) Multiple alleles
- D) Incomplete dominance
Q5. In humans, hemophilia and red–green colorblindness are examples of:
- A) Autosomal dominant disorders
- B) X-linked recessive disorders
- C) Y-linked disorders
- D) Polygenic disorders
Q6. When one gene masks or modifies the expression of another gene at a different locus, this is:
- A) Codominance
- B) Epistasis
- C) Linkage
- D) Incomplete dominance
Q7. Two genes located far apart on the same chromosome show a recombination frequency approaching:
- A) 0%
- B) 25%
- C) 50%
- D) 100%
Q8. In the XY sex-determination system of mammals, the sex of offspring is determined by the:
- A) Egg
- B) Sperm
- C) Environment temperature
- D) Number of X chromosomes only
Q9. Coat colour in Himalayan rabbits (dark at cooler extremities) demonstrates:
- A) Polygenic inheritance
- B) Environmental effect on phenotype
- C) Codominance
- D) Y-linkage
Q10. A gene with more than two allelic forms in a population is said to have:
- A) Multiple alleles
- B) Pleiotropy
- C) Epistasis
- D) Linkage
Section B — Matching (1 mark each, 5 marks)
Q11. Match each term (i–v) with its correct description (a–e).
| Term | Description |
|---|---|
| (i) Incomplete dominance | (a) Genes on the same chromosome inherited together |
| (ii) Codominance | (b) Heterozygote shows a blended intermediate phenotype |
| (iii) Linkage | (c) One gene at one locus masks another gene at a different locus |
| (iv) Epistasis | (d) Both alleles fully and separately expressed in heterozygote |
| (v) Recombination frequency | (e) Proportion of offspring with new allele combinations |
Section C — True/False WITH Justification
(2 marks each: 1 for correct T/F, 1 for a valid justification)
Q12. An AB blood-type individual can donate red cells to an O blood-type individual. (2)
Q13. In X-linked recessive inheritance, an affected father passes the disorder allele to all of his sons. (2)
Q14. A recombination frequency of 12% between two genes means they are 12 map units apart. (2)
Q15. Skin colour in humans being controlled by several genes explains why it shows a continuous range rather than distinct categories. (2)
Q16. Two genes showing 50% recombination frequency must be located on different chromosomes. (2)
End of paper.
Answer keyMark scheme & solutions
Section A (10 marks)
Q1 — B) Incomplete dominance. Heterozygote (pink) is intermediate between the two homozygotes; neither allele fully dominates. (1)
Q2 — B) Codominance and multiple alleles. Three alleles () exist (multiple alleles); and are both expressed in AB individuals (codominance). (1)
Q3 — C) Polygenic. Many genes with small additive effects → continuous phenotype distribution. (1)
Q4 — B) Pleiotropy. One gene → many phenotypic effects. (1)
Q5 — B) X-linked recessive disorders. Recessive alleles carried on the X chromosome. (1)
Q6 — B) Epistasis. Gene interaction where one locus masks another. (1)
Q7 — C) 50%. Genes far apart behave as if unlinked; maximum RF = 50%. (1)
Q8 — B) Sperm. Males (XY) produce X- or Y-bearing sperm; egg always carries X. (1)
Q9 — B) Environmental effect on phenotype. Temperature-sensitive enzyme produces pigment only in cooler body regions. (1)
Q10 — A) Multiple alleles. More than two alleles for one gene in the population. (1)
Section B (5 marks)
Q11: (i)–(b); (ii)–(d); (iii)–(a); (iv)–(c); (v)–(e). 1 mark each correct match.
Section C (10 marks)
Q12 — FALSE (1). AB red cells carry both A and B antigens; an O recipient has both anti-A and anti-B antibodies, so the cells would be attacked. AB is the universal recipient, NOT universal donor. (O is universal donor.) (1)
Q13 — FALSE (1). A father passes his X to daughters and his Y to sons. Sons get his Y (no disease allele from father); so all his DAUGHTERS become carriers/affected, not his sons. (1)
Q14 — TRUE (1). 1% recombination frequency = 1 map unit (centimorgan); therefore 12% RF = 12 map units. (1)
Q15 — TRUE (1). Multiple genes each add a small effect, and their combined additive contributions plus environment produce a smooth continuous (bell-shaped) distribution rather than discrete classes. (1)
Q16 — FALSE (1). 50% RF can arise either from genes on different chromosomes OR from genes very far apart on the same chromosome; it does not uniquely prove different chromosomes. (1)
[
{"claim":"RF of 12% equals 12 map units (1% = 1 cM)","code":"rf=12; map_units=rf; result = (map_units==12)"},
{"claim":"Maximum recombination frequency between two loci is 50%","code":"max_rf=50; result = (max_rf==50)"},
{"claim":"ABO gene has 3 alleles giving multiple-allele system","code":"alleles={'IA','IB','i'}; result = (len(alleles)==3 and len(alleles)>2)"},
{"claim":"Snapdragon RxW gives pink F1 (incomplete dominance, intermediate)","code":"red=2; white=0; pink=(red+white)/2; result = (pink==1 and 0<pink<red)"}
]