Level 4 — ApplicationCirculatory System

Circulatory System

60 minutes50 marksprintable — key stays hidden on paper

Level 4: Application (Novel Problems)

Time Limit: 60 minutes Total Marks: 50

Instructions: Answer all questions. Apply your understanding to the unseen scenarios described. No formula sheet or hints are provided. Show reasoning where calculations are required.


Question 1 — Clinical Case: The Breathless Climber (10 marks)

A mountaineer ascends to 5,500 m, where atmospheric oxygen partial pressure is roughly half that at sea level. After two weeks, blood tests show a raised red blood cell count and a raised haematocrit (proportion of blood volume occupied by RBCs).

(a) Explain, in terms of haemoglobin function, why oxygen delivery to tissues is initially impaired at altitude. (3)

(b) Explain how an increased RBC count helps restore oxygen delivery. (2)

(c) Haematocrit rising too high increases blood viscosity. Predict two consequences this would have for the heart and for circulation, justifying each. (4)

(d) State one blood component (other than RBCs) whose count would not be expected to rise due to altitude, and say what its normal role is. (1)


Question 2 — Tracing a Faulty Valve (12 marks)

A patient is diagnosed with a leaking (incompetent) bicuspid (mitral) valve, which allows some blood to flow backwards during ventricular contraction.

(a) Name the two chambers on either side of this valve, and state which side of the heart is affected. (3)

(b) During which phase of the cardiac cycle would the leak cause abnormal backflow? Explain what should normally happen at this valve during that phase. (3)

(c) Trace the correct path of a red blood cell from the moment it leaves the affected ventricle until it returns to the same ventricle. Name every chamber, vessel and valve in order. (4)

(d) Predict one effect the leak would have on the volume of blood the heart must handle and hence on the left atrium over time. (2)


Question 3 — The Transfusion Puzzle (10 marks)

An accident victim of unknown blood group needs an emergency transfusion. Three donor units are available: Type O Rh−, Type AB Rh+, and Type A Rh−.

(a) Which single unit is the safest choice to give immediately without cross-matching? Justify your answer using antigens and antibodies. (4)

(b) The victim is later found to be Type B Rh+. Explain why giving the AB Rh+ unit would have caused a serious reaction. (3)

(c) A pregnant woman is Rh−, and her fetus is Rh+. Explain the risk to a second Rh+ pregnancy and why the first is usually unaffected. (3)


Question 4 — Reading the Pressure Trace (10 marks)

A student measures a resting adult's blood pressure as 120/80 mmHg, and heart rate as 72 beats per minute.

(a) Identify what the two numbers 120 and 80 represent, linking each to an event in the cardiac cycle. (3)

(b) Calculate the pulse pressure and the duration of one cardiac cycle in seconds. Show your working. (3)

(c) The person then stands up suddenly and briefly feels dizzy. Explain how the body's blood pressure regulation (baroreceptor reflex) acts to correct the fall in pressure. (4)


Question 5 — Comparing Two Animals (8 marks)

An insect (open circulatory system) and a fish (closed, single circulation) are compared.

(a) State two structural or functional differences between open and closed circulatory systems. (2)

(b) The insect is highly active in flight yet its circulatory system does not deliver most of its oxygen. Explain how it obtains oxygen instead, and why an open circulatory system is still adequate for it. (3)

(c) A fish has a single circulation while a mammal has a double circulation. Explain one advantage the mammalian double circulation gives, relating it to pressure and oxygen delivery. (3)


Answer keyMark scheme & solutions

Question 1 (10 marks)

(a) At altitude the partial pressure of O₂ in inspired air is low (1), so less O₂ is available to bind haemoglobin in the lungs (1); haemoglobin becomes less saturated, so each unit of blood carries less O₂ and tissue delivery falls (1). (3)

(b) More RBCs means more haemoglobin per unit volume (1), increasing the total oxygen-carrying capacity of the blood to compensate for lower saturation (1). (2)

(c) Any two, each consequence (1) + justification (1):

  • Heart must work harder / higher workload because thicker (more viscous) blood is harder to pump (1)+(1).
  • Increased risk of clots / sluggish flow / poor capillary perfusion because viscous blood flows more slowly (1)+(1).
  • Raised blood pressure due to increased resistance (accept). (4)

(d) Any: platelets — role in clotting; WBCs — role in immune defence; plasma proteins — transport/osmotic balance. (1 for component + role) (1)


Question 2 (12 marks)

(a) Left atrium and left ventricle (2); left side of the heart (1). (3)

(b) During ventricular systole (contraction) (1). Normally the rising ventricular pressure forces the bicuspid valve shut (1), preventing backflow into the atrium so all blood is ejected into the aorta (1). (3)

(c) Correct order (award ~0.5 per correct element, round to 4): Left ventricle → aortic (semilunar) valve → aorta → systemic arteries/body/capillaries → venae cavae → right atrium → tricuspid valve → right ventricle → pulmonary (semilunar) valve → pulmonary artery → lungs (capillaries) → pulmonary veins → left atrium → bicuspid valve → left ventricle. (4)

(d) Blood leaks back into the left atrium, so the ventricle handles extra volume each cycle (1); the left atrium becomes overfilled and enlarges/dilates over time (1). (2)


Question 3 (10 marks)

(a) Type O Rh− (1). O red cells have neither A nor B antigens, and Rh− has no D antigen (1), so there are no antigens on the donor cells for any recipient antibodies to attack (1) — universal donor, safe regardless of the victim's group (1). (4)

(b) The victim is Type B, so their plasma contains anti-A antibodies (1). AB donor cells carry the A antigen (1), so anti-A would bind and agglutinate the transfused cells, causing a haemolytic reaction (1). (3)

(c) In the first pregnancy the Rh− mother is usually not yet sensitised, so no anti-Rh (anti-D) antibodies are present at first (1). Fetal Rh+ blood mixing at birth causes her to produce anti-D antibodies (1). In a second Rh+ pregnancy these antibodies cross the placenta and destroy fetal RBCs (haemolytic disease of the newborn) (1). (3)


Question 4 (10 marks)

(a) 120 = systolic pressure, during ventricular contraction/systole (1)+(1 event); 80 = diastolic pressure, when ventricles relax/diastole (1). (3)

(b) Pulse pressure = 120 − 80 = 40 mmHg (1). Cardiac cycle duration = 60 s ÷ 72 = 0.833 s (≈0.83 s) (2, working shown). (3)

(c) On standing, blood pools in the legs, cardiac output and BP drop (1). Baroreceptors in the carotid sinus/aortic arch detect reduced stretch (1) and send signals to the medulla (cardiovascular centre) (1). Sympathetic activity increases → heart rate and force rise and vessels constrict, restoring blood pressure (1). (4)


Question 5 (8 marks)

(a) Any two (1 each): open — blood (haemolymph) bathes tissues directly in body cavity vs closed — blood stays within vessels; open — low pressure vs closed — higher pressure; closed has capillaries for exchange, open does not; closed allows faster/more directed delivery. (2)

(b) The insect uses a tracheal system: air enters through spiracles and travels via trachea/tracheoles directly to tissues (1)+(1), so O₂ delivery does not depend on blood (1); the open system only needs to distribute nutrients/hormones, for which low pressure suffices. (3)

(c) In double circulation blood is re-pressurised by the heart between the lungs and body (1), maintaining high pressure to the systemic tissues (1), and oxygenated and deoxygenated blood are kept separate for more efficient O₂ delivery (1). (3)


[
  {"claim": "Pulse pressure = 120 - 80 = 40 mmHg", "code": "result = (120 - 80 == 40)"},
  {"claim": "Cardiac cycle duration = 60/72 ≈ 0.833 s", "code": "result = abs(Rational(60,72) - Rational(5,6)) == 0 and abs(float(Rational(60,72)) - 0.8333) < 0.01"},
  {"claim": "Heart rate 72 bpm gives 0.833 s per beat, so ~1.2 beats per second", "code": "result = abs(72/60 - 1.2) < 1e-9"}
]