Level 4 — ApplicationCell Theory & Microscopy

Cell Theory & Microscopy

50 marksprintable — key stays hidden on paper

Level 4: Application (Novel Problems)

Time: 60 minutes | Total Marks: 50


Instructions: Answer ALL questions. Show all working for calculations. Where units are required, marks will be lost if omitted. Use 1mm=1000μm1\,\text{mm} = 1000\,\mu\text{m} and 1μm=1000nm1\,\mu\text{m} = 1000\,\text{nm}.


Question 1 (12 marks)

A student photographs an onion epidermal cell through a light microscope. On the printed image the cell measures 48mm48\,\text{mm} in length. The image was captured at a total magnification of ×400\times400.

(a) Calculate the actual length of the cell. Give your answer in micrometres. (3)

(b) Express this actual length in nanometres and in millimetres. (2)

(c) The student now wants to view internal ribosomes (diameter 25nm\approx 25\,\text{nm}). Explain, with reference to resolution, whether this light microscope (resolution 200nm\approx 200\,\text{nm}) could resolve two adjacent ribosomes. (3)

(d) A classmate says "if we just increase the magnification to ×2000\times2000 we'll see the ribosomes clearly." Evaluate this claim. (4)


Question 2 (10 marks)

A micrograph of a chloroplast carries a scale bar labelled 2μm\mathbf{2\,\mu m}. When measured with a ruler, the scale bar is 16mm16\,\text{mm} long, and the whole chloroplast measures 40mm40\,\text{mm} across its longest axis.

(a) Calculate the magnification of the micrograph. (3)

(b) Calculate the actual longest-axis length of the chloroplast in μm\mu\text{m}. (3)

(c) The micrograph shows internal membrane detail (thylakoid stacks 0.5μm\approx 0.5\,\mu\text{m} apart) resolved as separate structures. Deduce which type of microscope (light, TEM or SEM) most likely produced this image, and justify using TWO distinct pieces of evidence from the data or description. (4)


Question 3 (10 marks)

Three historical researchers made the following (fictionalised) observations:

  • Researcher X examined thin slices of cork and described tiny empty "boxes."
  • Researcher Y scraped material from between her teeth and observed moving "animalcules."
  • Researcher Z studied diseased tissue and concluded that all cells causing the disease arose from division of pre-existing cells.

(a) Match each researcher (X, Y, Z) to the real scientist whose contribution it resembles. (3)

(b) State which ONE tenet of the cell theory Researcher Z's conclusion most directly supports. (2)

(c) Neither Researcher X nor Y could have formulated the full cell theory alone. Explain why, referring to what their tools and observations could and could not establish. (5)


Question 4 (10 marks)

A lab technician prepares two slides of the same unstained cheek cell sample:

  • Slide A: cells in water, no stain.
  • Slide B: cells treated with methylene blue.

(a) Describe the correct sequence of steps to prepare a wet mount for Slide A, and state the purpose of lowering the coverslip at an angle. (4)

(b) Explain, in terms of contrast and light absorption, why the nucleus is far more visible in Slide B than in Slide A. (3)

(c) The technician wishes to view the same cheek cells under a Scanning Electron Microscope instead. State TWO reasons why the wet mount preparation above would be unsuitable for SEM. (3)


Question 5 (8 marks)

The table gives approximate resolving power (smallest resolvable distance) for three instruments:

Instrument Resolving power
Human eye 100μm100\,\mu\text{m}
Light microscope 200nm200\,\text{nm}
TEM 0.5nm0.5\,\text{nm}

(a) Convert all three resolving powers to nanometres. (3)

(b) A virus is 80nm80\,\text{nm} across and a mitochondrion is 3μm3\,\mu\text{m} long. Determine which instrument(s) could resolve each, and briefly justify. (3)

(c) Explain in ONE sentence why the electron microscope achieves better resolution than the light microscope. (2)


Answer keyMark scheme & solutions

Question 1 (12 marks)

(a) Actual size = image size ÷ magnification. Image length =48mm=48000μm= 48\,\text{mm} = 48000\,\mu\text{m}. (1 — convert) Actual=48000μm400=120μm\text{Actual} = \frac{48000\,\mu\text{m}}{400} = 120\,\mu\text{m} (1 — divide, 1 — correct value + unit)

(b) 120μm=120×1000=120000nm120\,\mu\text{m} = 120\times1000 = 120000\,\text{nm} (1) 120μm=120/1000=0.12mm120\,\mu\text{m} = 120/1000 = 0.12\,\text{mm} (1)

(c) Two ribosomes are 25nm25\,\text{nm} across, so adjacent ribosomes are separated by a distance smaller than the microscope's resolution of 200nm200\,\text{nm}. (1) Any two points closer than the resolution limit appear as one. (1) Therefore the light microscope cannot resolve two adjacent ribosomes as separate. (1)

(d) The claim is incorrect. (1) Magnification only enlarges the image; it does not improve resolution. (1) Beyond the resolution limit, increasing magnification produces "empty magnification" — a larger but blurred image with no extra detail. (1) Since ribosome separation (<200nm<200\,\text{nm}) is below the light microscope's limit, no magnification will make them clearer; an electron microscope is required. (1)


Question 2 (10 marks)

(a) Magnification = measured scale-bar length ÷ actual length it represents. 16mm=16000μm16\,\text{mm} = 16000\,\mu\text{m}. (1) M=16000μm2μm=8000  (×8000)M = \frac{16000\,\mu\text{m}}{2\,\mu\text{m}} = 8000\;(\times8000) (1 — division, 1 — value)

(b) Actual = image ÷ magnification. Chloroplast image =40mm=40000μm=40\,\text{mm}=40000\,\mu\text{m}. (1) 400008000=5μm\frac{40000}{8000} = 5\,\mu\text{m} (1 — method, 1 — value + unit) (Alternatively by ratio: 40mm40\,\text{mm} is 40/16=2.5×40/16 = 2.5\times the bar, so 2.5×2=5μm2.5\times2 = 5\,\mu\text{m}.)

(c) Most likely TEM. (1) Evidence 1: resolution — thylakoids 0.5μm=500nm0.5\,\mu\text{m} = 500\,\text{nm} apart are resolved, which is within a light microscope limit; but resolving internal membrane fine detail and the high magnification (×8000\times8000) point to electron microscopy. (1) Evidence 2: internal/cross-sectional membrane detail (thylakoid stacks) indicates a thin section viewed by transmission, characteristic of TEM (SEM gives surface-only 3-D images). (2)


Question 3 (10 marks)

(a) X = Robert Hooke (cork "boxes"/cells). (1) Y = Antonie van Leeuwenhoek (animalcules from teeth scrapings). (1) Z = Rudolf Virchow (cells from pre-existing cells). (1)

(b) Supports the tenet: all cells arise from pre-existing cells (by division)omnis cellula e cellula. (2)

(c) Hooke observed only the empty cell walls of dead cork; he could not see living contents or establish that cells are the basic unit of all life. (2) Leeuwenhoek saw living single-celled organisms but had no framework linking them to the structure of larger organisms. (1) Neither could demonstrate that all organisms are composed of cells (Schleiden/Schwann's generalisation) nor how cells originate (Virchow). (2) Their microscopes and single observations established existence, not the unifying principles.


Question 4 (10 marks)

(a) Steps: place a drop of water on a clean slide (1); add/transfer the specimen into the drop (1); lower a coverslip at an angle onto the drop (1). Purpose of the angle: to allow water to spread and to exclude/prevent trapping of air bubbles which would obscure the view. (1)

(b) Unstained cells are largely transparent and let light pass, giving little contrast. (1) Methylene blue is a basic dye that binds to acidic components (DNA) in the nucleus. (1) The stained nucleus absorbs light, appearing dark against the pale cytoplasm, increasing contrast and visibility. (1)

(c) Any TWO of: SEM operates under vacuum so liquid water would evaporate/boil and disrupt cells (1); the specimen must be dry and coated with metal (conductive), not wet (1); electrons cannot pass through/around water and a glass slide + coverslip. (1) (Max 3)


Question 5 (8 marks)

(a) Eye: 100μm=100000nm100\,\mu\text{m} = 100000\,\text{nm} (1); Light microscope: 200nm200\,\text{nm} (already) (1); TEM: 0.5nm0.5\,\text{nm} (already) (1).

(b) Virus 80nm80\,\text{nm}: smaller than light microscope limit (200nm200\,\text{nm}) so only the TEM (0.5nm0.5\,\text{nm}) can resolve it. (1.5) Mitochondrion 3μm=3000nm3\,\mu\text{m} = 3000\,\text{nm}: larger than the light microscope limit, so both light microscope and TEM can resolve it (not the naked eye). (1.5)

(c) Electrons have a much shorter wavelength than visible light, and resolution improves as wavelength decreases. (2)


[
  {"claim":"Q1a actual cell length is 120 micrometres","code":"image_um=48*1000; mag=400; result=(image_um/mag==120)"},
  {"claim":"Q1b 120 um equals 120000 nm and 0.12 mm","code":"result=(120*1000==120000) and (120/1000==0.12)"},
  {"claim":"Q2a magnification of micrograph is 8000","code":"bar_um=16*1000; actual=2; result=(bar_um/actual==8000)"},
  {"claim":"Q2b chloroplast actual length is 5 micrometres","code":"image_um=40*1000; mag=8000; result=(image_um/mag==5)"},
  {"claim":"Q5a eye resolving power 100 um equals 100000 nm","code":"result=(100*1000==100000)"}
]