Level 2 — RecallCell Theory & Microscopy

Cell Theory & Microscopy

30 minutes40 marksprintable — key stays hidden on paper

Level 2 (Recall & Standard Problems)

Time Limit: 30 minutes
Total Marks: 40


Q1. State the three tenets of the cell theory. (3 marks)

Q2. Match each scientist to their contribution. (5 marks)

Scientist Contribution
(a) Robert Hooke
(b) Antonie van Leeuwenhoek
(c) Matthias Schleiden
(d) Theodor Schwann
(e) Rudolf Virchow

Q3. Define magnification and resolution. Explain clearly how the two differ. (4 marks)

Q4. Complete the following unit conversions. (4 marks)

(a) 2.5 mm= μm2.5\ \text{mm} = \underline{\hspace{2cm}}\ \mu\text{m}
(b) 750 nm= μm750\ \text{nm} = \underline{\hspace{2cm}}\ \mu\text{m}
(c) 0.02 mm= nm0.02\ \text{mm} = \underline{\hspace{2cm}}\ \text{nm}
(d) 8000 nm= mm8000\ \text{nm} = \underline{\hspace{2cm}}\ \text{mm}

Q5. A cell appears 50 mm50\ \text{mm} long under a microscope. Its actual length is 20 μm20\ \mu\text{m}. Calculate the magnification. (3 marks)

Q6. A photomicrograph has a scale bar labelled 10 μm10\ \mu\text{m}. The scale bar measures 40 mm40\ \text{mm} on the page.
(a) Calculate the magnification of the image. (2 marks)
(b) A structure in the image measures 25 mm25\ \text{mm}. Calculate its actual size in μm\mu\text{m}. (3 marks)

Q7. Compare a light microscope and a transmission electron microscope (TEM) by completing the table. (5 marks)

Feature Light Microscope TEM
Radiation source
Max. resolution
Specimen (living/dead)

State one difference between a TEM and an SEM. (1 mark) (included in the 5)

Q8. Explain the purpose of staining in microscopy, and give two named examples of stains with what they show. (4 marks)

Q9. List, in order, the steps used to prepare a wet mount slide. (4 marks)

Q10. Convert the resolution of the human eye, 0.1 mm0.1\ \text{mm}, into nanometres, and state whether a bacterium of length 2 μm2\ \mu\text{m} could be seen with the naked eye. Justify. (3 marks)


End of Paper

Answer keyMark scheme & solutions

Q1. (3 marks) — 1 mark each:

  1. All living organisms are composed of one or more cells.
  2. The cell is the basic (structural and functional) unit of life.
  3. All cells arise from pre-existing cells (by division).

Why: These are the three classical tenets synthesising the work of Schleiden, Schwann and Virchow.


Q2. (5 marks) — 1 mark each:

  • (a) Hooke — first observed and named "cells" (in cork, 1665).
  • (b) Leeuwenhoek — first observed living microorganisms/"animalcules" (bacteria, protists).
  • (c) Schleiden — proposed all plants are made of cells.
  • (d) Schwann — proposed all animals are made of cells (co-founded cell theory).
  • (e) Virchow — stated omnis cellula e cellula — all cells arise from pre-existing cells.

Q3. (4 marks)

  • Magnification (1): the number of times larger an image appears compared with the actual (real) size of the object. Ratio image size : actual size (1).
  • Resolution (1): the minimum distance between two points at which they can still be distinguished as separate (ability to reveal detail) (1).
  • Difference (1): magnification only enlarges; increasing it beyond the resolving limit gives a bigger but blurred image ("empty magnification"). Resolution sets the true detail limit.

Q4. (4 marks) — 1 each:

  • (a) 2.5 mm×1000=2500 μm2.5\ \text{mm} \times 1000 = 2500\ \mu\text{m}
  • (b) 750 nm÷1000=0.75 μm750\ \text{nm} \div 1000 = 0.75\ \mu\text{m}
  • (c) 0.02 mm×106=20000 nm0.02\ \text{mm} \times 10^6 = 20000\ \text{nm}
  • (d) 8000 nm÷106=0.008 mm8000\ \text{nm} \div 10^6 = 0.008\ \text{mm}

Why: 1 mm=1000 μm=106 nm1\ \text{mm}=1000\ \mu\text{m}=10^6\ \text{nm}; 1 μm=1000 nm1\ \mu\text{m}=1000\ \text{nm}.


Q5. (3 marks)

  • Convert to same units: image 50 mm=50000 μm50\ \text{mm} = 50000\ \mu\text{m} (1).
  • Mag=image sizeactual size=5000020\text{Mag} = \dfrac{\text{image size}}{\text{actual size}} = \dfrac{50000}{20} (1).
  • =×2500= \times 2500 (1).

Q6. (5 marks) (a) Scale bar: image 40 mm=40000 μm40\ \text{mm}=40000\ \mu\text{m} represents 10 μm10\ \mu\text{m}.

  • Mag=40000/10=×4000\text{Mag} = 40000/10 = \times 4000 (2).

(b) Actual size =image sizemag=25 mm4000=25000 μm4000=\dfrac{\text{image size}}{\text{mag}} = \dfrac{25\ \text{mm}}{4000} = \dfrac{25000\ \mu\text{m}}{4000} (2).

  • =6.25 μm= 6.25\ \mu\text{m} (1).

Q7. (5 marks) — table 1 mark per correct row-pair completion (4) + SEM difference (1):

Feature Light Microscope TEM
Radiation source Light (visible) Electron beam
Max. resolution ~200 nm (0.2 µm) ~0.2–1 nm
Specimen Living or dead Dead only (vacuum)
  • SEM difference: SEM scans the surface giving a 3-D image; TEM passes electrons through a thin section giving a 2-D internal image (1).

Q8. (4 marks)

  • Purpose (2): stains add contrast/colour to otherwise transparent cells, making cells and specific structures visible/distinguishable.
  • Examples (1 each, any two): iodine — stains starch blue-black; methylene blue — stains nuclei/cheek cells; eosin — stains cytoplasm pink; crystal violet/Gram stain — differentiates bacteria.

Q9. (4 marks) — 1 mark per correct step / ordering:

  1. Place a drop of water (or stain) on a clean glass slide.
  2. Place the thin specimen in the drop using forceps/mounted needle.
  3. Add a stain if required.
  4. Lower a coverslip at an angle (using a needle) to avoid trapping air bubbles. (Blot excess liquid — acceptable extra step.)

Q10. (3 marks)

  • 0.1 mm=0.1×106 nm=100000 nm0.1\ \text{mm} = 0.1 \times 10^6\ \text{nm} = 100000\ \text{nm} (equivalently 100 μm100\ \mu\text{m}) (2).
  • Bacterium 2 μm<100 μm2\ \mu\text{m} < 100\ \mu\text{m} resolving limit ⇒ cannot be seen with the naked eye (1).

[
  {"claim":"Q5 magnification = 2500", "code":"image=Rational(50*1000); actual=20; mag=image/actual; result=(mag==2500)"},
  {"claim":"Q6a magnification = 4000", "code":"bar_img=40*1000; bar_real=10; mag=bar_img/bar_real; result=(mag==4000)"},
  {"claim":"Q6b actual size = 6.25 um", "code":"img=25*1000; mag=4000; actual=Rational(img,mag); result=(actual==Rational(25,4))"},
  {"claim":"Q4 conversions correct", "code":"a=2.5*1000; b=750/1000; c=0.02*10**6; d=8000/10**6; result=(a==2500 and abs(b-0.75)<1e-9 and c==20000 and abs(d-0.008)<1e-9)"},
  {"claim":"Q10 0.1 mm = 100000 nm", "code":"nm=0.1*10**6; result=(nm==100000)"}
]