Level 4 — ApplicationCell Membrane & Transport

Cell Membrane & Transport

50 marksprintable — key stays hidden on paper

Level 4: Application (Novel Problems)

Time: 60 minutes | Total Marks: 50

Answer all questions. Apply concepts to the unseen scenarios given. Show reasoning.


Question 1 (10 marks)

A researcher engineers three artificial membrane vesicles, each with a different modification:

  • Vesicle A: phospholipid bilayer with no cholesterol.
  • Vesicle B: bilayer with cholesterol at normal concentration.
  • Vesicle C: bilayer with double the normal cholesterol.

The vesicles are tested at two temperatures: 10 °C and 40 °C. Membrane fluidity is measured.

(a) Predict, with reasoning, which vesicle will have the most fluid membrane at 40 °C. (3)

(b) Predict which vesicle will best resist solidifying at 10 °C, and explain the mechanism. (3)

(c) A small non-polar molecule diffuses across all three at 40 °C. Rank the vesicles by expected rate of this molecule's entry and justify. (4)


Question 2 (12 marks)

A plant cell and a human red blood cell are both placed in the same beaker of distilled (pure) water.

(a) State the water potential of pure water and explain the direction of net water movement for both cells. (3)

(b) Describe the final state of the plant cell and name it. Explain why it does not burst. (3)

(c) Describe the final state of the red blood cell and name the process. Explain why its outcome differs from the plant cell. (3)

(d) The plant cell is now transferred to a strongly hypertonic salt solution. Name and describe what happens to the protoplast, and state one consequence for the whole plant. (3)


Question 3 (10 marks)

Intestinal epithelial cells absorb glucose from the gut lumen (low glucose) into the cell (high glucose) using the SGLT1 transporter, which moves glucose together with Na⁺. A drug that blocks the Na⁺/K⁺ pump is added.

(a) Explain how glucose can be moved against its concentration gradient by SGLT1, naming the type of transport. (4)

(b) Explain, step by step, why blocking the Na⁺/K⁺ pump eventually stops glucose absorption via SGLT1. (4)

(c) State whether SGLT1 itself directly uses ATP, and justify your answer. (2)


Question 4 (10 marks)

A macrophage encounters a large bacterium and also takes in dissolved nutrients and specific LDL cholesterol particles from its surroundings.

(a) Name the process used to engulf the large bacterium and outline the steps. (4)

(b) The uptake of specific LDL particles requires membrane receptors. Name this process and explain how it achieves selectivity. (3)

(c) The macrophage later secretes digestive enzymes made on ribosomes. Name the process and explain how the vesicle contents reach the exterior. (3)


Question 5 (8 marks)

The table shows the rate of uptake of a molecule X across a membrane as its external concentration increases:

External [X] Rate of uptake
Low Rises steeply
Medium Rise slows
High Plateaus (constant)

(a) State the type of transport this pattern indicates and identify the type of membrane protein involved. (3)

(b) Explain, in molecular terms, why the rate reaches a plateau. (3)

(c) Contrast this graph shape with what would be seen for simple diffusion of a small non-polar molecule over the same concentration range. (2)


End of Paper

Answer keyMark scheme & solutions

Question 1 (10 marks)

(a) Most fluid at 40 °C — Vesicle A (no cholesterol). (3)

  • At high temperature phospholipids move rapidly. (1)
  • Cholesterol restrains/immobilises fatty acid tails, reducing fluidity at high temp. (1)
  • With no cholesterol nothing dampens the motion → most fluid. Vesicle C (double cholesterol) is least fluid. (1)

(b) Best resists solidifying at 10 °C — Vesicle C (double cholesterol) / cholesterol-containing. (3)

  • At low temperature tails pack tightly and gel/solidify. (1)
  • Cholesterol sits between phospholipids and prevents tight packing, keeping the membrane fluid. (1)
  • Highest cholesterol (C) gives greatest resistance to solidifying → maintains fluidity best. (1)

(c) Ranking of non-polar molecule entry at 40 °C: A > B > C. (4)

  • Non-polar molecules cross by simple diffusion through the lipid bilayer. (1)
  • Rate depends on fluidity/packing: more fluid, looser bilayer = faster diffusion. (1)
  • A most fluid → fastest; C least fluid → slowest. (1)
  • Order: A (fastest) > B > C (slowest). (1)

Question 2 (12 marks)

(a) (3)

  • Pure water has the highest (least negative) water potential = 0 kPa. (1)
  • Both cells have lower (more negative) internal water potential than pure water. (1)
  • Net water moves into both cells by osmosis (high → low water potential). (1)

(b) Plant cell final state (3)

  • Water enters, vacuole/protoplast swells and presses on the cell wall → turgid. (1)
  • The rigid cellulose cell wall resists expansion, generating wall/turgor pressure. (1)
  • This inward pressure stops further net water entry, so the cell does not burst. (1)

(c) Red blood cell (3)

  • Water enters continuously; cell swells and bursts → lysis (haemolysis). (1)
  • It has no cell wall to resist expansion. (1)
  • So unlike the plant cell there is no counter-pressure to halt water entry → membrane ruptures. (1)

(d) Hypertonic solution (3)

  • External solution more negative water potential → water leaves the cell by osmosis. (1)
  • Protoplast shrinks and pulls away from the cell wall = plasmolysis. (1)
  • Consequence: loss of turgor → cell/plant wilts. (1)

Question 3 (10 marks)

(a) (4)

  • SGLT1 uses the Na⁺ concentration/electrochemical gradient (Na⁺ high outside → moving in). (1)
  • Na⁺ moving down its gradient releases energy. (1)
  • This energy drags glucose against its gradient (co-transport/symport). (1)
  • This is secondary active transport. (1)

(b) (4)

  • Normally the Na⁺/K⁺ pump exports Na⁺, keeping intracellular Na⁺ low (maintaining the gradient). (1)
  • Block the pump → Na⁺ accumulates inside the cell. (1)
  • The inward Na⁺ gradient collapses / dissipates. (1)
  • Without the Na⁺ gradient's energy, SGLT1 can no longer drive glucose uphill → glucose uptake stops. (1)

(c) (2)

  • SGLT1 does not directly use ATP. (1)
  • It relies on the Na⁺ gradient, which is indirectly maintained by ATP-driven Na⁺/K⁺ pump — the ATP use is on the pump, not the transporter. (1)

Question 4 (10 marks)

(a) Phagocytosis (4)

  • Membrane extends pseudopodia around the bacterium. (1)
  • Pseudopodia fuse, enclosing it in a vesicle/phagosome. (1)
  • Vesicle taken into cytoplasm. (1)
  • Fuses with lysosome → enzymes digest the bacterium. (1)

(b) Receptor-mediated endocytosis (3)

  • Specific LDL binds complementary receptors on the membrane. (1)
  • Receptors cluster in a coated pit, which invaginates and pinches off as a vesicle. (1)
  • Only molecules matching the receptors are taken in → high selectivity. (1)

(c) Exocytosis (3)

  • Enzymes packaged into secretory vesicles (via Golgi). (1)
  • Vesicle moves to and fuses with the plasma membrane. (1)
  • Membrane opens, releasing contents to the exterior. (1)

Question 5 (8 marks)

(a) (3)

  • Facilitated diffusion (facilitated transport). (1) (carrier-protein type, passive.)
  • Involves carrier proteins (transport/membrane proteins). (1)
  • Passive — no ATP; still down the gradient. (1)

(b) (3)

  • Each carrier binds one solute and changes shape to move it. (1)
  • At high concentration all carriers are occupied/saturated. (1)
  • Rate limited by number of carriers → cannot increase further → plateau (Vmax). (1)

(c) (2)

  • Simple diffusion has no carriers, so no saturation. (1)
  • Rate rises linearly (proportionally) with concentration, no plateau. (1)

[
  {"claim": "Pure water potential is 0 kPa, the maximum value; cell solutions are negative and thus lower.", "code": "psi_pure = 0; psi_cell = -800; net_into_cell = psi_pure > psi_cell; result = (psi_pure == 0) and net_into_cell"},
  {"claim": "Non-polar diffusion rate order A>B>C follows fluidity: no cholesterol > normal > double at high temp.", "code": "fluidity = {'A':3,'B':2,'C':1}; order = sorted(fluidity, key=lambda k:-fluidity[k]); result = order == ['A','B','C']"},
  {"claim": "Blocking Na/K pump raises internal Na, collapsing the gradient needed by SGLT1 secondary active transport.", "code": "Na_out=140; Na_in_normal=15; Na_in_blocked=140; grad_normal=Na_out-Na_in_normal; grad_blocked=Na_out-Na_in_blocked; result = (grad_normal>0) and (grad_blocked==0)"},
  {"claim": "Facilitated diffusion saturates (plateau) whereas simple diffusion is linear (no plateau).", "code": "conc=[1,2,4,8]; simple=[2*c for c in conc]; Vmax=10; Km=2; facil=[Vmax*c/(Km+c) for c in conc]; linear = all(abs(simple[i]/conc[i]-2)<1e-9 for i in range(4)); saturates = facil[-1] < Vmax and facil[-1] > facil[0]; result = linear and saturates"}
]