Step 1 — Mass generation rate.
Surface rate r se recede karta hai (units m/s). Time dt mein Ab area pe rdt thickness ki layer gas ban jaati hai. Uska mass:
dm=ρpAb(rdt)
Yeh step kyun? Volume burned = area × thickness receded; mass = density × volume. Pure geometry hai.
Toh mass generation rate:
m˙=ρpAbr
Step 2 — Burn rate pressure pe depend karta hai (Vieille's law / Saint-Robert):r=apcn
Kyun? Zyada chamber pressure pc solid mein heat zyada fast push karta hai, toh surface aur tezi se andar jaati hai. a, n propellant ke empirical constants hain (n usually 0.2–0.5).
Step 3 — Mass balance se chamber pressure.
Steady operation mein, gas generated = gas leaving the nozzle throat (At). Nozzle mass flow m˙out∝pcAt. Generation = exhaust set karo:
ρpAbapcn=c∗pcAtpc ke liye solve karo:
pc=(Atρpac∗Ab)1−n1
Exponent 1−n1 kyun?pc dono sides pe hai (left mein r ke through), toh isolate karne par (1−n) power invert hoti hai. Isi liye n<1 hona zaroori hai stability ke liye — warna pressure runaway ho jaata hai.
Step 4 — Thrust.F=CFpcAt
Kyunki At aur CF ≈ fixed hain, thrust pc ke saath track karta hai, jo Ab ke saath track karta hai. Ratio define karo:
K=AtAb
Ek hollow cylinder. Bahar ki taraf jalta hai (port radius badhta hai, woh surface badhti hai) AUR ends se andar (annulus, axial length mein ghatta hai). Ek single unrestricted-end BATES segment ke liye, length L, inner radius Ri, outer Ro, burning surfaces hain inner cylinder + do annular ends.
Yeh neutral trend kyun karta hai? Port term badhta hai jabki end term ghatta hai; sahi L/D chunne se dono cancel ho jaate hain → near-neutral. Ek lamba, end-inhibited BATES (sirf inner surface jalta hai) purely progressive hota hai.
Ek star-shaped port. Bahut saare points aur valleys ek bada initial perimeter dete hain jo, jalne par, round out hota hai — perimeter roughly constant rehta hai.
Neutral kyun? Shuruaat mein pointed "fingers" jal jaate hain (area girta) lekin valleys web mein khuljati hain (area badhta); ek achi tarah se designed star in dono ko balance karta hai → neutral. Case-bonded motor mein constant thrust ke liye classic choice hai (ends inhibited hain, toh end-burning ki chinta nahi).
Ek star jisme aur bhi gehri, patli spokes hain — ek extreme high-perimeter design.
Highly progressive/high-thrust-early kyun? Bahut bada initial burning perimeter ⇒ bahut bada initial Ab ⇒ shuruaat mein badi thrust. Tab use karo jab tumhe high initial thrust / high mass flow chahiye (boost phase). Trade-off: patli spokes slivers chhodti hain aur regressive tail deti hain.
Fixed nozzle wale solid motor ka instantaneous thrust kya set karta hai?
Current burning surface area Ab (kyunki m˙=ρpAbr aur pc∝Ab1/(1−n)).
Web burned w define karo.
Woh perpendicular distance jitni burning surface propellant ke andar ja chuki hai.
Saint-Robert / Vieille burn law kya hai?
r=apcn, burn rate vs chamber pressure, n typically 0.2–0.5.
n<1 kyun hona chahiye?
Warna pc∝Ab1/(1−n) blow up ho jaata hai / unstable ho jaata hai; n<1 pressure ko bounded aur self-regulating rakhta hai.
Neutral vs progressive vs regressive burn?
Ab constant / increasing / decreasing over time → flat / rising / falling thrust.
Circular (BATES inner-only) port ka burn class?
Progressive — port perimeter bahar ki taraf recede hone par badhta hai.
Achi tarah se designed star grain ka burn class?
Neutral — jalne wale points aur khuljate valleys ek doosre ko balance karte hain taaki perimeter ≈ constant rahe.
Wagon wheel kyun use karte hain?
Bahut bada initial burning perimeter → bahut zyada initial thrust (boost phase); downside hai slivers/regressive tail.
End-burner ka burn class?
Neutral, low-thrust, long-duration (constant flat face area πR2).
Case-bonded grain ke liye area aur port perimeter ka relation?
Ab(w)=P(w)⋅L (perimeter × grain length).
Geometry se thrust tak master chain?
Ab→K=Ab/At→pc∝K1/(1−n)→F=CFpcAt.
"Sliver" kya hota hai?
Web burnout ke baad bache hue propellant ke tukde jo regressively jalte hain, thrust ko tail off karte hue.
Recall Feynman: 12-saal ke bachche ko explain karo
Socho ek birthday candle, lekin "flame" upar nahi hai — woh ek hole ki walls ke saath hai jo tumne candle mein kiya. Aag mombatti ko sideways khaati hai, hole se bahar har direction mein jaati hai. Jitni zyada wall abhi aag mein hai, utna zyada dhuaan (thrust) nikalta hai. Agar tum round hole karo, wall jalne par badi hoti jaati hai → zyada zyada aag → thrust badhta hai. Agar tum star-shaped hole karo, pointy bits jal jaate hain jabki dents khulte hain, aur sab balance ho jaata hai → steady aag. Agar tum wagon-wheel shape ka hole karo bahut saari patli spokes ke saath, shuruaat mein BAHUT zyada wall hoti hai → pehle bada whoosh, phir fade hota hai. Toh engineers mombatti nahi badlte — woh sirf hole ki shape badlte hain yeh decide karne ke liye ki rocket flat push kare, zyada-se-zyada, ya pehle bada phir soft.