3.2.8 · Physics › Orbital Mechanics & Astrodynamics
Ek orbit ek fixed ellipse hoti hai jo 3D space mein floating hai , jisme ek satellite move karta hai. Ise poori tarah se pin karne ke liye tumhe teen sawaalon ka jawab dena hoga:
Ellipse ki shape aur size kya hai? → a (size) aur e (shape).
Ellipse space mein kaise tilted/oriented hai? → i , Ω , ω (teen rotation angles).
Abhi satellite ellipse par kahan hai? → ν (true anomaly).
Ye exactly 6 numbers hain, kyunki ek 3D position + 3D velocity bhi 6 numbers hoti hai. Keplerian elements sirf ( r , v ) ka ek geometrically meaningful repackaging hai.
Intuition Degrees of freedom
Ek satellite ki ek instant par poori state hoti hai position r = ( x , y , z ) aur velocity v = ( v x , v y , v z ) — 6 numbers . Newton ki equation r ¨ = − μ r / r 3 phir saari future motion determine kar deti hai.
Isliye kisi bhi complete orbit description mein exactly 6 independent quantities hone chahiye. Keplerian elements wo choice hain jahan 5 constant hote hain (ideal two-body gravity mein orbit ki shape/orientation nahi badalti) aur sirf 1 (ν ) time ke saath badalta hai . Isliye yeh pasand kiye jaate hain: yeh unchanging geometry ko moving point se alag karte hain.
Definition Semi-major axis
a
Orbital ellipse ke sabse lambe diameter ka aadha . Yeh orbit ki size set karta hai aur, vis-viva relation ke through, total energy bhi.
a ko fix karti hai
1/ r 2 force mein energy conserved hoti hai. Agar hum energy jaante hain, to orbit ki size lock ho jaati hai — chahe satellite kahaan bhi baithe.
HOW. Specific orbital energy (energy per unit mass):
ε = 2 v 2 − r μ .
Perigee aur apogee par velocity purely tangential hoti hai, isliye angular momentum h = r v se milta hai v = h / r . Dono apsides par ε ka conservation:
2 r p 2 h 2 − r p μ = 2 r a 2 h 2 − r a μ .
Solve karo aur use karo r p = a ( 1 − e ) , r a = a ( 1 + e ) , r p + r a = 2 a . Algebra ke baad (neeche verified) constant value hai:
ε = − 2 a μ
ε = v 2 /2 − μ / r ko rearrange karne par milti hai vis-viva equation :
v 2 = μ ( r 2 − a 1 )
Hum ek Earth-Centered Inertial (ECI) frame mein kaam karte hain: X vernal equinox (♈) ki taraf, Z Earth ke spin axis ke saath (North), X –Y equatorial plane hai.
i
Equatorial plane ke relative orbital plane ka tilt : orbit ke angular-momentum vector h aur Z -axis ke beech ka angle. i = 0 equatorial, i = 9 0 ∘ polar, i > 9 0 ∘ retrograde.
Ω (Right Ascension of the Ascending Node)
==Equatorial plane mein angle, X (♈) se ascending node tak measure kiya gaya==. Ascending node woh jagah hai jahan satellite equator ko south→north jaate hue cross karta hai. RAAN batata hai tilted plane kis taraf ghuma hua hai .
Definition Argument of perigee
ω
Orbital plane mein angle, ascending node se perigee tak measure kiya gaya . Yeh batata hai plane ke andar ellipse kis taraf point kar rahi hai (closest approach kahan hai).
ν
Perigee se satellite ki current position tak ka angle , focus (Earth's center) par measure kiya gaya, motion ki direction mein. Yeh akela element hai jo time ke saath badalta hai .
Intuition WHY ek rotation matrix chahiye
Orbit ke apne "perifocal" frame mein (P perigee ki taraf, Q 9 0 ∘ aage) position trivial hoti hai. Hume sirf us frame ko teen angles ka use karke ECI mein rotate karna hai — yahi Ω , i , ω ka geometric meaning hai.
Perifocal position (P–Q–W axes):
r P Q W = r cos ν sin ν 0 , r = 1 + e c o s ν a ( 1 − e 2 ) .
ECI mein transform teen elementary rotations se:
r E C I = R z ( Ω ) R x ( i ) R z ( ω ) r P Q W .
Yahan R z ( θ ) Z ke around rotate karta hai, R x ( i ) line of nodes ke around. Yeh single product teeno orientation angles ki operational definition hai .
Worked example 1 — Apogee/perigee altitudes se
a aur e nikaalein
Ek satellite ka perigee altitude 400 km aur apogee altitude 1600 km hai. Earth radius R E = 6378 km. a aur e nikaalein.
Step 1: Earth's center se radii mein convert karo.
r p = 6378 + 400 = 6778 km, r a = 6378 + 1600 = 7978 km.
Kyun? Orbital elements focus (Earth's center) se distance use karte hain, altitude nahi.
Step 2: a = 2 r p + r a = 2 6778 + 7978 = 7378 km.
Kyun? Major axis = r p + r a = 2 a .
Step 3: e = r a + r p r a − r p = 14756 1200 = 0.0813 .
Kyun? r a − r p = 2 a e aur r a + r p = 2 a se, divide karo.
Worked example 2 — Perigee par speed (vis-viva)
Wohi orbit, μ E = 3.986 × 1 0 5 km³/s². v p nikaalein.
Step 1: r = r p par vis-viva use karo: v 2 = μ ( r p 2 − a 1 ) .
Kyun? vis-viva speed ko position se sirf a ka use karke connect karta hai — energy constant hai.
Step 2: v p 2 = 3.986 × 1 0 5 ( 6778 2 − 7378 1 ) = 3.986 × 1 0 5 ( 2.951 × 1 0 − 4 − 1.355 × 1 0 − 4 ) .
Step 3: v p 2 = 3.986 × 1 0 5 ( 1.596 × 1 0 − 4 ) = 63.6 → v p ≈ 7.98 km/s.
Kyun yeh sensible hai? Circular LEO speed (~7.6 km/s) se thoda zyada, kyunki perigee sabse fast point hota hai.
ν se current radius
a = 7378 km, e = 0.0813 ke saath, ν = 9 0 ∘ par r nikaalein.
Step 1: p = a ( 1 − e 2 ) = 7378 ( 1 − 0.00661 ) = 7329 km.
Step 2: r = 1 + e cos ν p = 1 + 0.0813 ⋅ 0 7329 = 7329 km.
Kyun? ν = 9 0 ∘ par, cos ν = 0 , isliye r = p — semi-latus rectum literally woh radius hai jo perigee se quarter-orbit baad hota hai.
Common mistake "Inclination batata hai ki plane kis direction mein rotate hua hai."
Kyun sahi lagta hai: i aur Ω dono "orientation" angles hain, inhe blur karna aasaan hai.
Fix: i tilt hai (plane equator se kitna jhuka hua hai). Ω swing hai (tilted plane ka node kis longitude par hai). Ek jhukta hai, doosra Z ke around ghoomta hai.
Common mistake "Semi-major axis = orbit ki altitude."
Kyun sahi lagta hai: circular LEO ke liye a ≈ ek fixed altitude.
Fix: a ek Earth's center se distance hai, aur yeh apogee aur perigee radii ka average hai, altitude nahi. Altitude ke liye R E ghatao.
Common mistake "True anomaly
ν time ke saath uniformly increase karta hai."
Kyun sahi lagta hai: yeh obvious "main kahan hun" angle hai.
Fix: ν perigee par sabse fast, apogee par sabse slow badalta hai (Kepler's 2nd law). Uniformly-increasing angle mean anomaly M hai; ν ko M se eccentric anomaly E ke through Kepler's equation se milta hai.
ω aur ν ek hi jagah se measure hote hain."
Kyun sahi lagta hai: dono in-plane angles hain focus par measure kiye gaye.
Fix: ω ascending node se perigee tak hai (fixed); ν perigee se satellite tak hai (moving). Unka sum, argument of latitude u = ω + ν , node→satellite hai.
Recall Feynman: ek 12-saal ke bachchey ko explain karo
Socho ek hula-hoop ek tabletop par tili hui hai, aur ek bead hoop ke around slide kar rahi hai.
Hoop ki size aur kitni squashed hai = a aur e .
Tumne hoop ko table se kitna tilaya = i .
Poori tili hui hoop ko kis taraf ghuma diya = Ω .
Hoop par "candle ke sabse paas wala point" kahan hai = ω .
Abhi is second hoop par bead kahan hai = ν .
Inme se paanch kabhi nahi badalte — sirf bead chalti rehti hai (ν ). Chhey chhote numbers aur tum bead ki poori yatra ke baare mein sab jaante ho!
Mnemonic Order aur meaning
"A Eccentric Italian Opera, Omitting Nothing."
a , e , i , Ω (RAAN), ω , ν — Shape, Shape, Tilt, Swing, Point, Position.
Yeh bhi: shAPE (a , e ) → fRAME (i , Ω , ω ) → plAce (ν ).
Semi-major axis a physically kya determine karta hai? Orbit ki size aur (via ε = − μ /2 a ) total orbital energy.
Specific orbital energy aur a ke beech relation kya hai? ε = − μ / ( 2 a ) .
Vis-viva equation batao. v 2 = μ ( r 2 − a 1 ) .
Apogee aur perigee radii se a kaise nikalte hain? a = ( r a + r p ) /2 .
Apogee aur perigee radii se e kaise nikalte hain? e = ( r a − r p ) / ( r a + r p ) .
Inclination i define karo. Orbital plane (
h vector) aur equatorial plane (
Z -axis) ke beech ka angle; orbit ka tilt.
RAAN Ω define karo. Equatorial plane mein vernal equinox (X ) se ascending node tak ka angle.
Ascending node kya hota hai? Woh point jahan satellite equator ko south→north jaate hue cross karta hai.
Argument of perigee ω define karo. In-plane angle ascending node se perigee tak.
True anomaly ν define karo. Focus par perigee se satellite ki current position tak ka angle, motion ki direction mein.
Ideal two-body problem mein kaun sa orbital element time ke saath badalta hai? Sirf true anomaly ν (baaki paanch constant hote hain).
r ( ν ) ke liye orbit (conic) equation likho.r = 1 + e cos ν a ( 1 − e 2 ) = 1 + e cos ν p .
Semi-latus rectum p h ke terms mein kya hai? p = h 2 / μ = a ( 1 − e 2 ) .
Perifocal se ECI coordinates mein map karne ka rotation sequence kya hai? R z ( Ω ) R x ( i ) R z ( ω ) .
Exactly 6 elements kyun chahiye? Kyunki full state
( r , v ) 6 numbers hota hai; 6 elements equivalent information carry karte hain.
Argument of latitude u kya hai? u = ω + ν , ascending node se satellite tak ka angle.
Position r and velocity v, 6 numbers
Keplerian elements, 6 numbers
Vis-viva, energy = -mu/2a
Ellipse geometry, rp and ra