3.1.22 · Physics › Compressible Flow & Aerodynamics
Intuition Badi picture (WHY yeh exist karta hai)
Ek infinite (2D) wing ko inviscid flow mein koi drag nahi hota (d'Alembert's paradox), aur uska fixed lift slope 2 π per radian hota hai. Lekin ek real wing finite hoti hai : tips par, neeche ki high-pressure air upar ki low-pressure side par leak karti hai. Isse ek trailing vortex sheet banti hai jo air ko wing ke peeche neeche ki taraf dhakelta hai.
Yeh downwash local "felt" velocity ko tilt karta hai, jo lift vector ko bhi peeche ki taraf tilt karta hai → ab lift ka ek component peeche ki taraf point karta hai = induced drag (drag-due-to-lift). Prandtl ki lifting-line theory sabse simple model hai jo yeh sab kuch ek single line of vortices se capture karti hai.
Bound vortex Γ ( y ) : span ke saath circulation, "lifting line" (1/4 -chord line) par located. Kutta–Joukowski ke hisaab se, unit span par local lift hai L ′ ( y ) = ρ ∞ V ∞ Γ ( y ) .
Trailing vortices : kyunki Γ span ke saath vary karta hai, vorticity ko downstream shed karna padta hai (Helmholtz: ek vortex filament fluid mein khatam nahi ho sakta). Shed strength per unit span hai − d y d Γ .
Downwash w ( y ) : poore trailing sheet ke dwara wing par induce ki gayi vertical velocity.
Aspect ratio A R = S b 2 , jahan b =span, S =planform area.
Geometry kaise baat karta hai: strength − d Γ/ d y ki trailing sheet ek row of semi-infinite vortex lines ki tarah behave karti hai. Har ek Biot–Savart se ek downwash contribute karta hai, aur hum unhe sum (integrate) karte hain.
Intuition Downwash sab kuch kyun tilt karta hai
Wing V ∞ mein fly karti hai, lekin locally V ∞ plus w neeche ki taraf feel hota hai. Resultant induced angle se neeche tilt ho jata hai:
α i ( y ) = tan − 1 V ∞ w ≈ V ∞ w ( y ) .
Local airfoil ki lift is local flow ke perpendicular hoti hai → vertical se α i peeche ki taraf tilt ho jati hai. Uska peeche wala component induced drag hai.
HOW hum ise solve karte hain: y = − 2 b cos θ substitute karo aur ek Fourier sine series lo:
Γ ( θ ) = 2 b V ∞ ∑ n = 1 ∞ A n sin ( n θ ) .
Yeh automatically Γ = 0 tips par satisfy karta hai (θ = 0 , π ). A n ko collocation se dhundha jaata hai.
Intuition Elliptic lift best kyun hai
Kyunki δ ≥ 0 aur = 0 sirf tab jab A 2 = A 3 = ⋯ = 0 , minimum induced drag tab hoti hai jab sirf A 1 = 0 ⇒ Γ ( θ ) = Γ 0 sin θ = elliptical circulation distribution. Tab:
C D , i = π A R C L 2
aur span ke across constant downwash hota hai. Zyada A R ⇒ kam induced drag — isliye gliders ki wings lambi aur patli hoti hain.
Worked example (A) Elliptic wing ka induced drag
A R = 7 , C L = 0.6 .
C D , i = π A R C L 2 = π ⋅ 7 0.36 = 0.0164.
Yeh step kyun? Elliptic ⇒ δ = 0 , clean formula use karo. Yeh us lift aur span ke liye minimum possible induced drag hai.
Worked example (B) Aspect ratio double karne ka effect
Same C L , A R = 7 → 14 karo. C D , i → π ⋅ 14 0.36 = 0.0082 . Aadha ho gaya.
Kyun? C D , i ∝ 1/ A R : zyada lambi span trailing vorticity ko spread karti hai, unit lift par weaker downwash.
Worked example (C) Non-elliptic penalty
Ek wing mein A 2 / A 1 = 0.1 , A 3 / A 1 = 0.05 , baaki zero hain.
δ = 2 ( 0.1 ) 2 + 3 ( 0.05 ) 2 = 0.02 + 0.0075 = 0.0275.
Toh e = 1/1.0275 = 0.973 aur drag elliptic minimum se 2.75% upar hai.
Yeh step kyun? δ measure karta hai ki lift shape ideal se kitni door hai; chhote higher harmonics bhi real drag cost karte hain.
Worked example (D) 3D lift slope
Elliptic wing, A R = 8 . a = 1 + 2 π / ( 8 π ) 2 π = 1 + 0.25 2 π = 1.25 2 π = 5.03 /rad .
Yeh step kyun? 2D a 0 = 2 π = 6.28 se compare karo: finite wing "softer" hai — induced downwash effective incidence ko reduce karta hai.
Common mistake "Induced drag friction/viscous drag hai."
Kyun sahi lagta hai: saara drag "rub" jaisa lagta hai. Fix: induced drag bilkul inviscid flow mein bhi exist karta hai — yeh trailing vortices mein le jaai jaane wali energy hai (swirling wake ki kinetic energy). Yeh ek pressure-related, lift-coupled drag hai, skin friction aur profile drag se alag.
Common mistake "Zyada wing area hamesha induced drag reduce karti hai."
Kyun sahi lagta hai: zyada area = zyada lift, efficient lagta hai. Fix: jo cheez matter karti hai woh span hai, area nahi: C D , i ∝ C L 2 / ( π A R ) = C L 2 S / ( π b 2 ) . Fixed b ke liye, chord (area) badhane se fixed C L par induced drag badhti hai. Lamba patla > chhota mota.
Common mistake "Saare harmonics lift mein contribute karte hain."
Kyun sahi lagta hai: series mein kaafi A n hain. Fix: orthogonality ki wajah se sirf A 1 hi C L set karta hai; baaki (n ≥ 2 ) drag add karte hain par lift nahi — pure penalty hai.
Common mistake Trailing filaments ke liye
2 π r Γ (full line) use karna.
Kyun sahi lagta hai: yeh familiar vortex formula hai. Fix: trailing filaments semi-infinite hain (wing se shuru hokar ∞ tak jaate hain), isliye yeh 4 π r Γ hai — bilkul downwash integral wala factor.
Recall Quick self-test (answers chhupao)
Ek 2D infinite wing ko inviscid flow mein kaunsa drag hota hai? → Koi nahi (d'Alembert).
Physically induced drag kya create karta hai? → Trailing tip vortices / downwash lift ko peeche tilt karta hai.
Kaunsi Γ distribution induced drag minimize karti hai? → Elliptic , C D , i = C L 2 / ( π A R ) .
Lift mein sirf A 1 kyun? → [ 0 , π ] par sin n θ ki orthogonality.
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho ek wide tray ko paani mein flat push kar rahe ho. Kinaron ke paas, paani neeche ki high-pressure se upar ki low-pressure side par round aata hai, chhote spinning tornadoes banaata hai jo peeche trail karte hain. Woh tornadoes banane mein energy lagti hai, aur woh energy "drag" wing ko thoda peeche khichne ke roop mein feel hoti hai. Ek lamba, patla tray edge-tornadoes ko beech mein ki saari acchi lifting ke comparison mein kamzor banata hai — isliye lambi, patli wings (jaise glider ki) kam energy waste karti hain. Lift ki perfect sharing, tips ke paas chhoti aur beech mein sabse badi ek oval shape mein, sabse chhote possible tornadoes banati hai.
Mnemonic Result yaad rakho
"LIFT loves A-one; DRAG pays for the rest."
C L = π A R A 1 (sirf A 1 ), C D , i = π A R ∑ n A n 2 (sabko pay karna padta hai).
Aur "Long & lean = less induced" (C D , i ∝ 1/ A R ).
Kutta–Joukowski theorem — L ′ = ρ V ∞ Γ deta hai jo har strip mein use hota hai.
Thin airfoil theory — local lift slope 2 π aur α L = 0 provide karta hai.
Biot–Savart law — downwash integral ka basis hai.
Helmholtz vortex theorems — isliye trailing vorticity shed karni padti hai.
d'Alembert's paradox — kyun 2D wing mein zero drag hota hai.
Aspect ratio & wing design — gliders/airliners ke liye practical consequence.
Oswald efficiency factor — drag polar C D = C D , 0 + C L 2 / ( π e A R ) .
Induced drag define karo. Drag-due-to-lift trailing vortices se: downwash local lift vector ko peeche tilt karta hai; inviscid flow mein bhi exist karta hai.
Prandtl ka downwash integral state karo. w ( y ) = 4 π 1 ∫ − b /2 b /2 y − η d Γ/ d η d η .
Trailing filament downwash mein 4 π kyun, 2 π kyun nahi? Trailing filaments semi-infinite hain, isliye Γ/ ( 4 π r ) milta hai, infinite-line value ka aadha.
Fourier coefficients ke terms mein C L kya hai? C L = π A R A 1 (sirf pehla coefficient).
Fourier coefficients ke terms mein C D , i kya hai? C D , i = π A R ∑ n = 1 ∞ n A n 2 = π A R C L 2 ( 1 + δ ) .
Kaunsi lift distribution induced drag minimize karti hai aur kyun? Elliptic (Γ = Γ 0 sin θ ); sirf A 1 = 0 isliye δ = 0 , constant downwash.
Minimum induced drag formula? C D , i = C L 2 / ( π A R ) elliptic wing ke liye.
Span efficiency e define karo. e = 1/ ( 1 + δ ) ≤ 1 ; C D , i = C L 2 / ( π e A R ) ; e = 1 elliptic ke liye.
Finite-wing lift slope (elliptic)? a = a 0 / ( 1 + a 0 / ( π A R )) jahan a 0 = 2 π .
C D , i span par depend kyun karta hai, sirf area par kyun nahi?C D , i = C L 2 S / ( π b 2 ) ; zyada span par vorticity spread karna downwash ko kamzor karta hai.
Lift mein sirf A 1 kyun contribute karta hai? Orthogonality: ∫ 0 π sin n θ sin θ d θ = 0 jab n = 1 .
Aspect ratio ki definition? A R = b 2 / S (span squared divided by planform area).
Effective angle of attack
Aspect ratio b squared over S