3.1.5 · Physics › Compressible Flow & Aerodynamics
Ek duct mein compressible gas flow karte waqt, cross-section area ko kaise change karna padega taaki flow accelerate ho, yeh depend karta hai ki flow subsonic hai ya supersonic. Sound ki speed se neeche, tum squeeze (converge) karte ho speed badhane ke liye. Sound ki speed se upar, tumhe open up (diverge) karna padta hai speed badhane ke liye. Mach number M ek switch ki tarah kaam karta hai jo relationship ka sign flip kar deta hai — aur yahi switch exactly reason hai ki de Laval nozzle ek hourglass jaisi shape ka hota hai.
Definition Players (characters)
A = duct ka local cross-sectional area [ m 2 ]
V = local flow speed [ m/s ]
ρ = density [ kg/m 3 ]
a = local speed of sound [ m/s ]
M = V / a = Mach number (dimensionless)
Flow assume ki gayi hai steady, 1-D, isentropic (adiabatic + reversible), inviscid .
Hum chahte hain ek single equation jo fractional area change d A / A ko fractional speed change d V / V se link kare.
Humein teen physical statements chahiye. Hum inhe differentiate karenge, phir combine karenge.
Steady flow mein mass pile up ya vanish nahi ho sakta. Isliye mass flow per second, m ˙ = ρ A V , har cross-section par same hoti hai.
ρ A V = constant
Natural log lo, phir differentiate karo (yeh ek product ko fractional changes ke sum mein convert kar deta hai — woh trick jo sab kuch clean banati hai):
ln ρ + ln A + ln V = const
\boxed{\frac{d\rho}{\rho} + \frac{dA}{A} + \frac{dV}{V} = 0} \tag{1}
Intuition Log-differentiate kyun karte hain?
Product X Y Z = const ke liye, d ( X Y Z ) = 0 messy hai. Lekin d ( ln X + ln Y + ln Z ) = X d X + Y d Y + Z d Z = 0 seedha fractional changes deta hai, jo is poore topic ki language hai.
Ek steady inviscid flow Newton's law ko streamline ke along follow karta hai: net pressure force per unit mass acceleration produce karta hai. Ek horizontal nozzle mein gas dynamics ke liye koi gravity term nahi hota.
1-D steady Euler (momentum) equation:
dp + \rho V\,dV = 0 \quad\Longrightarrow\quad \frac{dp}{\rho} = -V\,dV \tag{2}
Accelerate karne ke liye (d V > 0 ) pressure drop karna chahiye (d p < 0 ). Gas speed tabhi badhata hai jab pressure kharch ho. Theek hai — equation (2) agree karta hai.
Density changes pressure changes se linked hoti hain. Chhoti isentropic disturbances ke liye, proportionality ka constant exactly speed of sound ka square hota hai:
a 2 = ( ∂ ρ ∂ p ) s ⟹ d p = a 2 d ρ
Yeh a ki definition hai — ek sound wave ek tiny pressure pulse hai, aur yeh kitni tez travel karta hai yeh depend karta hai ki pressure density ke response mein kitna stiffly react karta hai.
Toh:
d\rho = \frac{dp}{a^2} \tag{3}
(2) ko (3) mein daalo:
d ρ = a 2 − ρ V d V
ρ se divide karo:
\frac{d\rho}{\rho} = -\frac{V^2}{a^2}\frac{dV}{V} = -M^2\,\frac{dV}{V} \tag{4}
Ab (4) ko continuity equation (1) mein substitute karo:
d ρ / ρ − M 2 V d V + A d A + V d V = 0
A d A = M 2 V d V − V d V = ( M 2 − 1 ) V d V
( M 2 − 1 ) ka sign padhkar flow accelerate karo (d V > 0 ):
Regime
M 2 − 1
d V > 0 paane ke liye humein chahiye...
Duct shape
Subsonic M < 1
negative
d A < 0
Converging
Sonic M = 1
zero
d A = 0
Throat (minimum area)
Supersonic M > 1
positive
d A > 0
Diverging
Intuition Yeh flip kyun hota hai?
Subsonically, gas almost paani ki tarah behave karta hai: density barely change hoti hai, isliye area squeeze karne se speed badh jaati hai (continuity). Supersonically, density itni tezi se girti hai (yeh speed se bhi tezi se girti hai) ki ρ A V constant rakhne ke liye area ko actually grow karna padta hai. Woh crossover jahan density aur velocity effects exactly balance hote hain woh M = 1 hai — throat .
Definition de Laval (converging–diverging) nozzle
Ek nozzle jo throat tak converging hai, phir diverging . Yeh gas ko subsonic se accelerate karta hai, throat par exactly M = 1 se hote hue , supersonic speeds mein — rockets aur supersonic wind tunnels ka engine.
Common mistake "Sound se tez jaane ke liye bas squeeze karte raho"
Kyun sahi lagta hai: everyday liquids aur subsonic gas ke liye, narrow pipe = faster flow, isliye hum extrapolate karte hain. Trap: M = 1 par factor ( M 2 − 1 ) = 0 , isliye d A = 0 — area stationary hai (ek minimum). Converge karte rehne se d A < 0 hoga jabki hum d V > 0 chahte hain, jo equation supersonic flow mein forbid karta hai. Fix: throat par tumhe diverging mein switch karna chahiye. Yeh non-negotiable hai: sonic flow sirf throat par hi ho sakti hai (d A = 0 ).
Common mistake Yeh sochna ki
M = 1 automatically throat par reach ho jaata hai
Kyun sahi lagta hai: throat woh jagah hai jahan d A = 0 , aur M = 1 ke liye d A = 0 chahiye, isliye log inhe equal maan lete hain. Subtlety: throat par d A = 0 allow karta hai d V = 0 ya toh isliye ki M = 1 hai ya isliye ki flow wahan simply accelerate nahi ho raha. Sonic conditions throat par tabhi hoti hain jab pressure ratio itna bada ho ki flow "choke" ho jaye. Warna throat bas ek max-speed subsonic point hota hai.
Worked example Example 1 — Subsonic intake ko kis shape mein banana chahiye?
Air ek duct mein M = 0.5 par enter karti hai aur hum ise accelerate karna chahte hain. Kaunsi shape?
Step: M < 1 ⇒ M 2 − 1 = 0.25 − 1 = − 0.75 < 0 . Yeh step kyun? ( M 2 − 1 ) ka sign sab kuch decide karta hai.
d V > 0 ke liye humein chahiye d A / A = ( − 0.75 ) ( d V / V ) < 0 , yaani d A < 0 → converging . ✅ Subsonic flow ke liye intuition se match karta hai.
Worked example Example 2 — Chhoti speed change se percent area change
M = 2 par ek supersonic flow 1% speed badhata hai (d V / V = 0.01 ). Fractional area change kya hai?
Step: d A / A = ( M 2 − 1 ) ( d V / V ) = ( 4 − 1 ) ( 0.01 ) = 0.03 . Yeh step kyun? M pata hone par direct plug-in.
Toh area ko sirf 1% speed gain ke liye 3% increase karna padega — supersonic acceleration area mein "expensive" hai, isliye nozzle bells itne wide flare karti hain.
Worked example Example 3 — Throat par
Flow throat se guzarti hai (d A = 0 ) aur sonic hai. d V find karo.
Step: 0 = ( M 2 − 1 ) V d V with M = 1 ⇒ ( M 2 − 1 ) = 0 . Yeh step kyun? Bracket vanish ho jaata hai, isliye d V / V is equation se unconstrained hai — indeterminate 0 ⋅ ( d V / V ) exactly wahi hai jis se flow smoothly sub→supersonic transition karta hai. Velocity throat ke across badhti reh sakti hai chahe d A = 0 locally ho.
Area–velocity relation derive karne ke liye kaunse teen conservation/physical laws combine kiye jaate hain? Continuity (mass), Euler's momentum equation, aur isentropic speed-of-sound relation d p = a 2 d ρ .
Area–velocity relation state karo. A d A = ( M 2 − 1 ) V d V .
Subsonic flow mein gas accelerate karne ke liye duct converge karega ya diverge? Converge (d A < 0 ), kyunki M 2 − 1 < 0 .
Supersonic flow mein gas accelerate karne ke liye duct converge karega ya diverge? Diverge (d A > 0 ), kyunki M 2 − 1 > 0 .
Exactly M = 1 par relation ka kya hota hai? M 2 − 1 = 0 , isliye d A = 0 — sonic flow sirf throat (minimum area) par ho sakti hai.
Continuity ke differential form derive karne mein log-differentiation kyun help karta hai? Yeh product ρ A V = const ko fractional changes ke sum d ρ / ρ + d A / A + d V / V = 0 mein convert karta hai.
a 2 = ( ∂ p / ∂ ρ ) s physically kya mean karta hai?Speed of sound ka square equal hota hai us stiffness se jis se pressure constant entropy par density ke response mein react karta hai.
De Laval nozzle converging–diverging kyun hona chahiye? Subsonic se accelerate karne ke liye (converging chahiye) M = 1 throat se hote hue supersonic mein (diverging chahiye).
Euler's equation se, flow speed up hone ke liye pressure ko kya karna chahiye? Pressure drop karna chahiye: d p = − ρ V d V , isliye d V > 0 ⇒ d p < 0 .
d ρ / ρ ko M aur d V / V ke terms mein derive karo.d p = − ρ V d V aur d ρ = d p / a 2 se: d ρ / ρ = − ( V 2 / a 2 ) ( d V / V ) = − M 2 ( d V / V ) .
Recall Feynman: ek 12-saal ke bachche ko explain karo
Socho tum hawa ko ek hose se push kar rahe ho taaki woh tezi se nikal sake. Jab tak hawa sound se dheerae chal rahi hai, hose ko pinch karne se woh tezi ho jaati hai — bilkul paani ki tarah. Lekin jab hawa sound se tez chal rahi hoti hai, kuch ajeeb hota hai: ab tumhe hose ko wide karna padta hai taaki woh aur tez ho sake. Hawa itni tezi se spread aur thin ho jaati hai ki zyada room dene se actually speed badhti hai. Isliye ek rocket nozzle hourglass jaisi dikhti hai: ek narrow neck (jahan hawa exactly sound ki speed pakadti hai) aur phir ek wide bell jahan woh super fast jaati hai.
Mnemonic Switch yaad rakho
"Sub squeeze karta hai, Super spread karta hai, Sonic sabse slim jagah par."
(Subsonic → converge, Supersonic → diverge, M = 1 → throat.)
Recall Quick self-test (answers chhupa lo)
d A ka sign kya hoga jab M = 0.3 aur tumhe d V > 0 chahiye? → negative (converge).
Bracket ko zero kya banata hai? → M = 1 .
Continued converging supersonic flow kyun nahi de sakta? → yeh d A < 0 force karta hai jabki supersonic acceleration ko d A > 0 chahiye.
supersonic M gt 1 diverge
drho/rho + dA/A + dV/V = 0
drho/rho = -M squared dV/V
dA/A = M squared minus 1 times dV/V