2.3.18 · Physics › Modern Physics
Intuition The big picture
Ek atom mostly empty space hota hai, lekin uske tiny centre mein nucleus hota hai — protons aur neutrons ki ek dense ball jo ek aise force se ek saath tiki hoti hai jo electric repulsion ko bhi beat kar sakti hai . Puzzle yeh hai: positive protons ko toh alag ud jaana chahiye (same charges repel karte hain), phir bhi woh nahi udte. KYUN? Kyunki ~1 0 − 15 m ki distance par ek nayi, bahut zyada strong attractive force kick in karti hai. Nuclear structure ko samajhna = is tug-of-war ko samajhna.
Yeh numbers ka matlab kya hai?
Atomic number Z = protons ki sankhya → element fix karta hai.
Mass number A = nucleons ki sankhya = Z + N , jahan N = neutrons ki sankhya.
Notation: Z A X , jaise 6 12 C mein 6 protons, 6 neutrons hain.
Definition Isotopes / Isobars / Isotones
Isotopes : same Z , different A (same element). jaise 1 1 H , 1 2 H .
Isobars : same A , different Z . jaise 1 3 H , 2 3 He .
Isotones : same N . jaise 1 3 H ( N = 2 ) , 2 4 He ( N = 2 ) .
Intuition Radius formula kyun hoti hai?
Scattering experiments (Rutherford, phir electron scattering) dikhate hain ki nuclear matter ki density roughly constant hoti hai — har nucleon lagbhag utna hi volume leta hai, jaise ek bag mein pack kiye hue marbles. Agar density constant hai, toh volume nucleons ki sankhya ke proportional hona chahiye.
R = R 0 A 1/3 scratch se derive kaise karein:
Nucleus ka volume (sphere): V = 3 4 π R 3 .
Har nucleon ek fixed volume v 0 occupy karta hai, aur A nucleons hain, isliye
V = A v 0 .
Dono ko equal set karo:
3 4 π R 3 = A v 0 ⇒ R 3 = 4 π 3 v 0 A ⇒ R = R 0 ( 4 π 3 v 0 ) 1/3 A 1/3 .
Worked example Density (lagbhag)
A se independent hoti hai
Density ρ = volume mass = 3 4 π R 3 A m n = 3 4 π R 0 3 A A m n = 3 4 π R 0 3 m n .
Yeh step kyun? A cancel ho jaata hai! → density sabhi nuclei ke liye same hoti hai.
Numbers daalne par: ρ ≈ 3 4 π ( 1.2 × 1 0 − 15 ) 3 1.67 × 1 0 − 27 ≈ 2.3 × 1 0 17 kg/m 3 . Insanely dense — ek teaspoon ka weight ~billions of tonnes hoga.
Definition Nuclear force ki properties
Sabse strongest known fundamental force (EM force se ≈100× zyada ∼ 1 fm par).
Short-ranged : sirf ~2 − 3 fm tak effective; iske baad practically zero.
Charge independent : p − p , n − n , p − n forces nearly equal hain → yeh charge ko ignore karta hai.
Saturated : har nucleon sirf apne nearest neighbours ko attract karta hai, baaki sabko nahi.
Typical separations par attractive lekin bahut short range par repulsive (< 0.5 fm) — yeh hard core nucleus ko collapse hone se rokta hai.
Intuition "Saturation" kyun matter karta hai
Agar strong force har nucleon ko har doosre se kheenchti, toh binding energy A ( A − 1 ) /2 ∼ A 2 jaisi badhti. Experiments dikhate hain ki binding energy ∼ A (linear) jaisi badhti hai. Iska sirf ek hi matlab hai: har nucleon fixed chhote number of neighbours se bond karta hai → saturation . Yeh exactly kisi solid mein covalent bonds jaisa hai.
Intuition Force short-ranged kyun hai (Yukawa idea, qualitative)
Yukawa ne propose kiya ki yeh force ek particle exchange karne se carry hoti hai (pion , π , mass ∼ 140 MeV/c²). Ek massive exchange particle thodi der ke liye hi energy "borrow" kar sakta hai (uncertainty principle Δ E Δ t ∼ ℏ ), isliye woh thodi si hi distance travel kar sakta hai:
r ∼ m π c ℏ ≈ 1.4 fm .
Yeh step kyun? Heavier mediator → shorter range. Photon (massless) infinite -range EM force deta hai; ek massive pion finite range deta hai. Yeh ~few-fm cutoff explain karta hai!
Intuition Neutron = "nuclear glue + spacer"
Neutrons strong attraction feel karte hain lekin koi charge nahi rakhte, isliye woh binding add karte hain bina Coulomb repulsion add kiye. Halke nuclei N ≈ Z se khush hote hain. Jaise Z badhta hai, Coulomb repulsion (∝ Z 2 ) attraction se zyada tezi se badhta hai, isliye heavy stable nuclei ko bound rehne ke liye extra neutrons (N > Z ) chahiye hote hain. Isliye stability line N = Z se upar ki taraf bend karti hai.
Intuition Mass gayab ho jaata hai
Ek bound nucleus apne alag parts se kam wazni hota hai. "Khoyi hui" mass woh energy ban gayi jo ise bind karti hai (Einstein: E = m c 2 ). Ise alag karne ke liye aapko woh energy wapas daalni padegi.
1 2 H ki binding energy
Masses: m p = 1.007825 u (H atom), m n = 1.008665 u, M ( 2 H ) = 2.014102 u.
Step 1 — parts ka sum: 1.007825 + 1.008665 = 2.016490 u. Kyun? Woh ek free proton + neutron hai (atomic masses, electron cancel hota hai).
Step 2 — mass defect: Δ m = 2.016490 − 2.014102 = 0.002388 u. Kyun? Bound system halka hota hai.
Step 3 — energy: E B = 0.002388 × 931.5 ≈ 2.22 MeV. Kyun? Mass ko energy mein convert karo.
Toh deuteron ko todne ke liye 2.22 MeV chahiye — aur yahi exactly photodisintegration experiments mein dekha gaya photon energy hai. ✔
Recall Feynman: ek 12-saal ke bacche ko samjhao
Socho ek bag mein chhote magnetic marbles hain. Kuch marbles (protons) par "+" sticker laga hai aur woh push karte hain ek doosre ko. Lekin har marble par super-strong velcro laga hai jo sirf usse touching marbles ko pakadta hai. Velcro push karne se bahut zyada strong hai, isliye bag ek saath clumped rehta hai. Hum kuch sticker-less marbles (neutrons) add karte hain — woh extra velcro laate hain lekin koi pushing nahi, isliye woh clump ko saath hold karne mein madad karte hain. Velcro tab hi kaam karta hai jab marbles touch karein (super short range); door se sirf pushing feel hoti hai.
"P-N STICKS CLOSE, SATURATED, SHORT."
Nuclear force P rotons & N eutrons ke beech hoti hai, charge-independent hai (STICKS to anyone), CLOSE range, SATURATED (sirf neighbours), SHORT (~2–3 fm).
Common mistake "Protons repel karte hain, toh nucleus exist nahi karna chahiye."
Kyun sahi lagta hai: Aap correctly Coulomb's law yaad karte ho — same charges repel karte hain. ✅
Fix: Aap ek doosra , stronger force bhool rahe ho. ≤ 2 fm par strong nuclear force Coulomb ko overwhelm kar deti hai. Repulsion real hai lekin nuclear distances par haarta hai.
Common mistake "Bada nucleus = badi density."
Kyun sahi lagta hai: Bada usually heavier hota hai aur aap imagine karte ho ki zyada cheezein pack ho rahi hain.
Fix: Volume ∝ A badhta hai aur mass ∝ A badhta hai, toh woh cancel ho jaate hain: ρ sabhi nuclei ke liye constant hai (~2.3 × 1 0 17 kg/m³). Ise prove karne ke liye R = R 0 A 1/3 use karo.
Common mistake "Nucleus apne parts se heavier hota hai kyunki yeh bound hai."
Kyun sahi lagta hai: "Glue add karne se weight add hona chahiye."
Fix: Binding energy release karti hai, aur woh energy mass le jaati hai (E = m c 2 ). Bound nucleus mass defect Δ m se lighter hota hai.
Common mistake "Strong force poore nucleus mein equally act karta hai."
Kyun sahi lagta hai: Gravity aur EM sabhi pairs par act karte hain, toh aap assume karte ho ki strong bhi karta hai.
Fix: Strong force saturate hoti hai — sirf nearest neighbours. Isliye E B ∝ A hai, A 2 nahi.
Worked example Compute karne se pehle predict karo
Q: 13 27 Al ka radius vs 216 ? nucleus (A = 216 )?
Forecast: 216/27 = 8 , aur 8 1/3 = 2 , toh bada nucleus exactly do baar ka radius hona chahiye.
Verify: R = R 0 A 1/3 , ratio = ( 216/27 ) 1/3 = 2 . ✔ Aapka forecast match karta hai.
Nucleons kya hote hain? Protons aur neutrons — nucleus ke andar ke particles.
Mass number A aur atomic number Z define karo. Z = protons ki sankhya (element fix karta hai); A = total nucleons = Z + N .
Isotopes kya hote hain? Same Z lekin different A wale nuclei (same element, different neutron count).
Nuclear radius formula derive aur state karo. Constant density se, V ∝ A toh R ∝ A 1/3 ; R = R 0 A 1/3 , R 0 ≈ 1.2 fm.
Kya sabhi nuclei ki nuclear density same hoti hai? Kyun? Haan (~2.3 × 1 0 17 kg/m³); mass ∝ A aur volume ∝ A cancel ho jaate hain.
Nuclear force ki 4 properties list karo. Strongest, short-ranged (~2–3 fm), charge-independent, saturated (sirf nearest neighbours); repulsive core <0.5 fm.
Nuclear force short-ranged kyun hai (Yukawa)? Yeh ek massive particle (pion) se mediate hoti hai; range ∼ ℏ/ ( m π c ) ≈ 1.4 fm. Massive mediator → finite range.
Saturation kyun imply karta hai ki E B ∝ A hai, A 2 nahi? Har nucleon sirf fixed nearest neighbours se bond karta hai, isliye total bonds A ke saath scale karte hain, na ki sabhi pairs ke saath.
Heavy nuclei ko extra neutrons (N > Z ) kyun chahiye? Neutrons strong attraction add karte hain bina Coulomb repulsion ke, Z 2 -growing proton repulsion ko balance karte hue.
Mass defect aur binding energy define karo. Δ m = [ Z m p + N m n ] − M n u c l e u s ; E B = Δ m c 2 .
Conversion: 1 u·c 2 = ? 931.5 MeV.
Bound nucleus apne parts se heavier hota hai ya lighter? Lighter, Δ m se; khoyi hui mass binding energy ban jaati hai.
Isotopes Isobars Isotones